Question Number 31295 by Ruchinna1 last updated on 05/Mar/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 31289 by mondodotto@gmail.com last updated on 05/Mar/18 Answered by MJS last updated on 05/Mar/18 $$\mathrm{1}^{\mathrm{st}} \:\mathrm{white}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{red}\:+\:\mathrm{1}^{\mathrm{st}} \:\mathrm{red}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{white} \\ $$$$\frac{\mathrm{5}}{\mathrm{8}}×\frac{\mathrm{3}}{\mathrm{7}}+\frac{\mathrm{3}}{\mathrm{8}}×\frac{\mathrm{5}}{\mathrm{7}}=\frac{\mathrm{15}}{\mathrm{28}} \\ $$…
Question Number 162351 by ZiYangLee last updated on 29/Dec/21 $$\mathrm{how}\:\mathrm{to}\:\mathrm{show}\: \\ $$$${f}\left({x}\right)={x}^{\mathrm{4}} +\mathrm{2}{x}^{\mathrm{3}} +\mathrm{5}{x}^{\mathrm{2}} −\mathrm{16}{x}−\mathrm{20}\: \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{form}\:\mathrm{of}\:\left({x}^{\mathrm{2}} +{x}+{a}\right)^{\mathrm{2}} −\mathrm{4}\left({x}+{b}\right)^{\mathrm{2}} . \\ $$ Answered by Rasheed.Sindhi…
Question Number 162344 by stelor last updated on 28/Dec/21 Commented by mr W last updated on 29/Dec/21 $${two}\:{equations}\:{for}\:{three}\:{unknowns} \\ $$$$\Rightarrow{no}\:{unique}\:{solution}! \\ $$ Answered by aleks041103…
Question Number 31265 by aplus last updated on 04/Mar/18 Commented by Tinkutara last updated on 05/Mar/18 a 90 b 120 c 5 Commented by aplus last updated on 05/Mar/18 $$\mathrm{help}\:\mathrm{please}…
Question Number 162326 by stelor last updated on 28/Dec/21 $${Hello}\:{please}\:{show}\:{it}… \\ $$$$\:{a}\:\in\:\left[\mathrm{0}\:,\:\frac{\pi}{\mathrm{4}}\right]\:\:\:\:\:\:\:\:{a}\:\leqslant{tan}\:{a}\:\leqslant\:\mathrm{2}{a} \\ $$ Answered by mindispower last updated on 28/Dec/21 $$\mathrm{1}\leqslant\mathrm{1}+{tg}^{\mathrm{2}} \left({a}\right)\leqslant\mathrm{2},\forall{a}\in\left[\mathrm{0},\frac{\pi}{\mathrm{4}}\right] \\ $$$$\int_{\mathrm{0}}…
Question Number 96782 by M±th+et+s last updated on 04/Jun/20 $$\left.\mathrm{1}\right)\frac{{cos}^{\mathrm{4}} \left(\theta\right)}{{x}}−\frac{{sin}^{\mathrm{4}} \left(\theta\right)}{{y}}=\frac{\mathrm{1}}{{x}+{y}} \\ $$$${find}\:\frac{{dy}}{{dx}} \\ $$$$ \\ $$$$\left.\mathrm{2}\right){solve}:\mathrm{2}\lfloor{x}−\mathrm{4}+\lfloor{x}\rfloor\rfloor=\mathrm{6}−\mathrm{3}\lfloor{x}\rfloor \\ $$$$ \\ $$$$\left.\mathrm{3}\right)\underset{{x}\rightarrow\mathrm{4}} {{lim}}\frac{\left({cos}\left({x}\right)\right)^{{x}} −\left({sin}\left({x}\right)\right)^{{x}} −{cos}\left(\mathrm{2}{x}\right)}{\left({x}−\mathrm{4}\right)}…
Question Number 162280 by MathsFan last updated on 28/Dec/21 $${y}={x}^{{sinx}} \\ $$$${find}\:\:{y}' \\ $$ Answered by Ar Brandon last updated on 28/Dec/21 $${y}={x}^{\mathrm{sin}{x}} \\ $$$$\mathrm{ln}{y}=\mathrm{sin}{x}\mathrm{ln}{x}…
Question Number 31188 by mondodotto@gmail.com last updated on 03/Mar/18 Commented by Tinkutara last updated on 03/Mar/18 $$\mathrm{tan}\:\theta=\frac{\mathrm{4}}{\mathrm{3}} \\ $$$$\mathrm{sin}\:\theta=\pm\frac{\mathrm{4}}{\mathrm{5}};\mathrm{cos}\:\theta=\pm\frac{\mathrm{3}}{\mathrm{5}} \\ $$$$\pm\frac{\mathrm{3}}{\mathrm{5}}=\mathrm{1}−\mathrm{2sin}^{\mathrm{2}} \:\frac{\theta}{\mathrm{2}} \\ $$$$\mathrm{sin}^{\mathrm{2}} \:\frac{\theta}{\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{5}}…
Question Number 162249 by SANOGO last updated on 28/Dec/21 Answered by mr W last updated on 28/Dec/21 $$\left(\mathrm{1}\right) \\ $$$$\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\begin{pmatrix}{{n}}\\{{k}}\end{pmatrix}\:{x}^{{k}} =\left(\mathrm{1}+{x}\right)^{{n}} \\ $$$${set}\:{x}=−\mathrm{1}…