Question Number 31442 by mondodotto@gmail.com last updated on 08/Mar/18 Commented by mondodotto@gmail.com last updated on 08/Mar/18 $$\boldsymbol{\mathrm{differentiate}} \\ $$ Commented by prof Abdo imad last…
Question Number 31423 by mondodotto@gmail.com last updated on 08/Mar/18 Commented by mondodotto@gmail.com last updated on 08/Mar/18 $$\boldsymbol{\mathrm{please}}\:\boldsymbol{\mathrm{help}}\:\boldsymbol{\mathrm{me}}! \\ $$ Answered by MJS last updated on…
Question Number 96936 by joki last updated on 05/Jun/20 Commented by PRITHWISH SEN 2 last updated on 05/Jun/20 $$\mathrm{shorter}\:\mathrm{diagonal}\:=\:\mathrm{a} \\ $$$$\mathrm{longer}\:\mathrm{diagonal}\:=\:\mathrm{a}\sqrt{\mathrm{3}} \\ $$$$\therefore\:\mathrm{Ratio}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}} \\ $$…
Question Number 96906 by zienab last updated on 05/Jun/20 Answered by abdomathmax last updated on 05/Jun/20 $$\mathrm{question}\:\mathrm{not}\:\mathrm{clear}\:\mathrm{what}\:\mathrm{mean}\:\mathrm{x}_{\mathrm{i}} \:\mathrm{and}\:\mathrm{p}_{\mathrm{i}} ? \\ $$ Commented by zienab last…
Question Number 96904 by pticantor last updated on 05/Jun/20 Commented by pticantor last updated on 05/Jun/20 $$\:\boldsymbol{{show}}\:\boldsymbol{{that}}\:\boldsymbol{{there}}\:\boldsymbol{{are}}\:\mathrm{4}\:\boldsymbol{{real}}\:\boldsymbol{{numbers}}\:\boldsymbol{{a}},\boldsymbol{{b}},\boldsymbol{{c}}\:\boldsymbol{{and}}\:\boldsymbol{{d}}\:\:\:\:\:\:\:\:\: \\ $$$$\boldsymbol{{which}}\:\boldsymbol{{will}}\:\boldsymbol{{be}}\:\boldsymbol{{specified}}\:\boldsymbol{{such}}\:\boldsymbol{{that}} \\ $$$$\left(\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{4}\boldsymbol{{x}}+\mathrm{5}\right)^{\mathrm{2}} +\left(\boldsymbol{{x}}+\mathrm{1}\right)^{\mathrm{2}} =\left(\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{ax}}+\boldsymbol{{b}}\right)\left(\boldsymbol{{x}}^{\mathrm{2}}…
Question Number 162410 by mahdipoor last updated on 29/Dec/21 $$\int\frac{{dx}}{\left({a}−{cosx}\right)^{\mathrm{2}} }\:\:\:{a}>\mathrm{1} \\ $$ Answered by mathmax by abdo last updated on 29/Dec/21 $$\mathrm{let}\:\mathrm{f}\left(\mathrm{a}\right)=\int\:\:\frac{\mathrm{dx}}{\mathrm{a}−\mathrm{cosx}}\:\Rightarrow\mathrm{f}^{'} \left(\mathrm{a}\right)=−\int\:\frac{\mathrm{dx}}{\left(\mathrm{a}−\mathrm{cosx}\right)^{\mathrm{2}} }\:\Rightarrow…
Question Number 31327 by mondodotto@gmail.com last updated on 06/Mar/18 Commented by mondodotto@gmail.com last updated on 06/Mar/18 $$\mathrm{please}\:\mathrm{help} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 96848 by DELETED last updated on 05/Jun/20 Answered by 1549442205 last updated on 05/Jun/20 $$\mathrm{we}\:\mathrm{have}\:\mathrm{A}\cup\mathrm{B}=\left\{\mathrm{0},\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{6},\mathrm{7},\mathrm{8},\mathrm{9},\mathrm{10}\right\} \\ $$$$\mathrm{B}\cup\mathrm{C}=\left\{\mathrm{0},\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5},\mathrm{6},\mathrm{7},\mathrm{8},\mathrm{9},\mathrm{10}\right\} \\ $$$$\Rightarrow\left(\mathrm{A}\cup\mathrm{B}\right)\cap\left(\mathrm{B}\cup\mathrm{C}\right)=\left\{\mathrm{0},\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{6},\mathrm{7},\mathrm{8},\mathrm{9},\mathrm{10}\right\} \\ $$ Terms of…
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Question Number 31289 by mondodotto@gmail.com last updated on 05/Mar/18 Answered by MJS last updated on 05/Mar/18 $$\mathrm{1}^{\mathrm{st}} \:\mathrm{white}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{red}\:+\:\mathrm{1}^{\mathrm{st}} \:\mathrm{red}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{white} \\ $$$$\frac{\mathrm{5}}{\mathrm{8}}×\frac{\mathrm{3}}{\mathrm{7}}+\frac{\mathrm{3}}{\mathrm{8}}×\frac{\mathrm{5}}{\mathrm{7}}=\frac{\mathrm{15}}{\mathrm{28}} \\ $$…