Question Number 163126 by Diels last updated on 04/Jan/22 $$\:\boldsymbol{{Please}}\:\boldsymbol{{dear}}\:\boldsymbol{{members}}.\:\boldsymbol{{concerning}}\:\boldsymbol{{this}}\:\boldsymbol{{App}} \\ $$$$\:\boldsymbol{{How}}\:\boldsymbol{{to}}\:\boldsymbol{{change}}\:\boldsymbol{{the}}\:\boldsymbol{{color}}\: \\ $$$$\:\boldsymbol{{of}}\:\boldsymbol{{the}}\:\boldsymbol{{paper}}\:\boldsymbol{{on}}\:\boldsymbol{{which}}\:\boldsymbol{{we}}\:\boldsymbol{{are}} \\ $$$$\:\boldsymbol{{writing}}\left(\boldsymbol{{for}}\:\boldsymbol{{example}}\:\boldsymbol{{from}}\:\boldsymbol{{white}}\:\boldsymbol{{to}}\:\boldsymbol{{any}}\:\boldsymbol{{kind}}\right. \\ $$$$\left.\:\:\boldsymbol{{of}}\:\boldsymbol{{color}}\right)?????? \\ $$ Commented by mr W last…
Question Number 163110 by ampomahlosotho last updated on 03/Jan/22 Answered by mahdipoor last updated on 03/Jan/22 $$\mathrm{2}^{{x}−\mathrm{2}} =\mathrm{8}{x}\Rightarrow\frac{\mathrm{1}}{\mathrm{32}}\mathrm{2}^{{x}} ={x}\Rightarrow−\frac{\mathrm{1}}{\mathrm{32}×{ln}\mathrm{2}}=\left(−\frac{{x}}{{ln}\mathrm{2}}\right)\mathrm{2}^{\left(−{x}\right)} = \\ $$$$\left(−\frac{{x}}{{ln}\mathrm{2}}\right)\mathrm{2}^{{ln}\mathrm{2}×\frac{−{x}}{{ln}\mathrm{2}}} =\left(−\frac{{x}}{{ln}\mathrm{2}}\right){e}^{\left(\frac{−{x}}{{ln}\mathrm{2}}\right)} \Rightarrow \\…
Question Number 163111 by SANOGO last updated on 03/Jan/22 $${calcul}\:{en}\:{fonction}\:{de}\:{n} \\ $$$$\:\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\mathrm{3}^{{k}−\mathrm{1}} \left(_{{k}} ^{{n}} \right) \\ $$$$\underset{{k}=\mathrm{0}} {\overset{{k}={n}} {\sum}}{sin}\left({kx}\right)\left(_{{k}} ^{{n}} \right) \\ $$$$…
Question Number 97554 by 1549442205 last updated on 08/Jun/20 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{triples}\:\mathrm{of}\:\mathrm{positive}\:\mathrm{integers}\:\left(\mathrm{x};\mathrm{y};\mathrm{z}\right) \\ $$$$\mathrm{so}\:\mathrm{that}\:\frac{\mathrm{x}−\mathrm{y}\sqrt{\mathrm{2020}}}{\mathrm{y}−\mathrm{z}\sqrt{\mathrm{2020}}}\:\mathrm{is}\:\mathrm{a}\:\mathrm{rational}\:\mathrm{number} \\ $$$$\mathrm{and}\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} \mathrm{be}\:\mathrm{a}\:\mathrm{prime}\:\mathrm{number}. \\ $$ Commented by Rasheed.Sindhi last updated on…
Question Number 97555 by 175 last updated on 08/Jun/20 Commented by bemath last updated on 08/Jun/20 $$\mathrm{yes}\:\mathrm{nice}\:{problem}\: \\ $$ Commented by prakash jain last updated…
Question Number 97541 by mathocean1 last updated on 08/Jun/20 $${Determinate} \\ $$$$\underset{{x}\rightarrow\mathrm{1}/\mathrm{2}} {{lim}}\:\frac{{sin}\left(\mathrm{2}{x}−\mathrm{1}\right)}{\mathrm{2}{x}−\mathrm{1}} \\ $$$$\underset{{x}\rightarrow+\infty\:} {{lim}}\:\frac{{cosx}}{\mathrm{1}+{x}^{\mathrm{2}\:} } \\ $$ Commented by bobhans last updated on…
Question Number 97506 by ali_golmakani last updated on 08/Jun/20 $${please}\:{prove}\:{it} \\ $$$$ \\ $$$$\mathrm{cos}\:{x}=\:{J}_{\mathrm{0}} \left({x}\right)\:+\:\mathrm{2}\sum_{{x}−\mathrm{1}} \left(−\mathrm{1}\right)^{{x}} {J}_{\mathrm{2}{n}} \left({x}\right) \\ $$ Terms of Service Privacy Policy…
Question Number 97490 by ali_golmakani last updated on 08/Jun/20 $${please}\:\:{prove}\:\:{it} \\ $$$$\mathrm{cos}{x}=\:{J}_{\mathrm{0}} \left({x}\right)+\mathrm{2}\sum_{{x}−\mathrm{1}} \left(−\mathrm{1}\right)^{{x}} {J}_{\mathrm{2}{x}} \left({x}\right) \\ $$ Answered by smridha last updated on 08/Jun/20…
Question Number 31954 by mondodotto@gmail.com last updated on 17/Mar/18 Answered by mrW2 last updated on 18/Mar/18 $${A}={A}_{\mathrm{0}} {e}^{−\lambda{t}} \\ $$$$\mathrm{0}.\mathrm{5}{A}_{\mathrm{0}} ={A}_{\mathrm{0}} {e}^{−\mathrm{15}\lambda} \\ $$$$\Rightarrow\lambda=\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{15}} \\…
Question Number 163024 by SANOGO last updated on 03/Jan/22 $${calcul}\:{en}\:{fonction}\:{de}\:{n} \\ $$$$\underset{{k}=\mathrm{0}} {\overset{\mathrm{2}{n}} {\sum}}\left(_{{k}} ^{\mathrm{2}{n}} \right)^{{n}−\mathrm{2}{k}} \\ $$ Commented by SANOGO last updated on 03/Jan/22…