Question Number 161665 by SANOGO last updated on 21/Dec/21 $${nature}\:{de} \\ $$$$\int_{{o}} ^{\mathrm{1}} \frac{\mathrm{1}}{{t}^{\mathrm{2}} \sqrt{\mathrm{1}−{t}}}{dt} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 96114 by Tinku Tara last updated on 30/May/20 $$\mathrm{A}\:\mathrm{read}\:\mathrm{only}\:\mathrm{snapshot}\:\mathrm{of}\:\mathrm{questions} \\ $$$$\mathrm{and}\:\mathrm{answers}\:\mathrm{on}\:\mathrm{this}\:\mathrm{forum}\:\mathrm{is} \\ $$$$\mathrm{accessible}\:\mathrm{from}\:\mathrm{www}.\mathrm{tinkutara}.\mathrm{com}. \\ $$$$\mathrm{This}\:\mathrm{can}\:\mathrm{be}\:\mathrm{viewed}\:\mathrm{in}\:\mathrm{any}\:\mathrm{browser} \\ $$$$\mathrm{and}\:\mathrm{also}\:\mathrm{included}\:\mathrm{plain}\:\mathrm{text}. \\ $$$$ \\ $$$$\mathrm{Version}\:\mathrm{2}.\mathrm{079}\:\mathrm{has}\:\mathrm{been}\:\mathrm{uploaded} \\ $$$$\mathrm{to}\:\mathrm{playstore}\:\mathrm{and}\:\mathrm{will}\:\mathrm{be}\:\mathrm{available}…
Question Number 96089 by bebo last updated on 29/May/20 Answered by mr W last updated on 30/May/20 Commented by mr W last updated on 30/May/20…
Question Number 161626 by ZiYangLee last updated on 20/Dec/21 Commented by TheSupreme last updated on 20/Dec/21 $${f}\left({x},{y},\lambda\right)={x}−\mathrm{2}{y}+\lambda\left(\mathrm{4}{x}^{\mathrm{2}} +\mathrm{9}{y}^{\mathrm{2}} −\mathrm{16}{x}−\mathrm{54}{y}+\mathrm{61}\right) \\ $$$$\begin{cases}{\mathrm{1}+\lambda\left(\mathrm{8}{x}−\mathrm{16}\right)=\mathrm{0}}\\{−\mathrm{2}+\lambda\left(\mathrm{18}{y}−\mathrm{54}\right)=\mathrm{0}}\\{\mathrm{4}{x}^{\mathrm{2}} +\mathrm{9}{y}^{\mathrm{2}} −\mathrm{16}{x}−\mathrm{54}{y}+\mathrm{61}=\mathrm{0}}\end{cases} \\ $$$${x}=\mathrm{2}−\frac{\mathrm{1}}{\mathrm{8}\lambda}…
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Question Number 30543 by mondodotto@gmail.com last updated on 23/Feb/18 Commented by abdo imad last updated on 23/Feb/18 $${the}\:{ch}.{x}−\frac{\mathrm{1}}{\mathrm{2}}={sint}\:{give} \\ $$$${I}=\:\int_{−\frac{\pi}{\mathrm{2}}} ^{\frac{\pi}{\mathrm{2}}} \:\mathrm{4}\pi\left(\frac{\mathrm{1}}{\mathrm{2}}\:+{sint}\right)\sqrt{\mathrm{1}−{sin}^{\mathrm{2}} {t}}\:{cost}\:{dt} \\ $$$${I}=\:\int_{−\frac{\pi}{\mathrm{2}}}…
Question Number 96060 by liki last updated on 29/May/20 Commented by liki last updated on 29/May/20 $$..\mathrm{please}\:\boldsymbol{\mathrm{M}}\mathrm{r}\:\boldsymbol{\mathrm{W}}\:\mathrm{and}\:\mathrm{others}\:\mathrm{help}\:\mathrm{this}\:\mathrm{question}! \\ $$ Commented by john santu last updated…
Question Number 161579 by MathsFan last updated on 19/Dec/21 $$ \\ $$A gardener wishes to make a rectangular hen run of area 128m² against a…
Question Number 161578 by Ari last updated on 19/Dec/21 Commented by blackmamba last updated on 20/Dec/21 $$\:\mathrm{cos}\:\mathrm{75}°=\:\frac{\frac{\mathrm{1}}{\mathrm{2}}{a}}{\mathrm{10}}\:=\:\frac{{a}}{\mathrm{20}} \\ $$$$\:\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{2}}\:.\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{3}}\:−\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{2}}\:.\frac{\mathrm{1}}{\mathrm{2}}\:=\:\frac{{a}}{\mathrm{20}} \\ $$$$\:\Rightarrow\sqrt{\mathrm{6}}−\sqrt{\mathrm{2}}\:=\:\frac{{a}}{\mathrm{5}} \\ $$$$\Rightarrow{a}=\mathrm{5}\sqrt{\mathrm{2}}\:\left(\sqrt{\mathrm{3}}−\mathrm{1}\right)\:{cm} \\ $$$$\therefore\:{S}\left[{BDHF}\right]\:=\:{a}^{\mathrm{2}}…
Question Number 161560 by lapache last updated on 19/Dec/21 $${li}\underset{{x}\rightarrow+\infty} {{m}}\mathrm{1}+{x}^{\mathrm{2}} −\mathrm{2}{x}^{\mathrm{2}} {ln}\left({x}\right)=…? \\ $$ Answered by mathmax by abdo last updated on 19/Dec/21 $$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{2}}…