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Question Number 95011 by prince 5 last updated on 22/May/20 $${Given}\:{tbat}\:{a}\:{disk}\:{has}\:\mathrm{18}\:{sectors},\:\mathrm{80}\:{tracks} \\ $$$${and}\:{a}\:{sector}\:{capacity}\:{of}\:\mathrm{512}{bytes}.\:{Prove}\: \\ $$$${that}\:{the}\:{storage}\:{capacity}\:{is}\:\mathrm{1}.\mathrm{44}{MB} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 95001 by mathocean1 last updated on 22/May/20 $$\mathrm{Exercise} \\ $$$$\mathrm{Given}\:\mathrm{a},\:\mathrm{b}\:\in\:\mathbb{R}^{\ast} \:\mathrm{and}\:{t}\:\mathrm{is}\:\mathrm{a}\:\mathrm{variable}\:\mathrm{real}. \\ $$$$\left.\mathrm{1}\right)\:\mathrm{Solve}\:\mathrm{in}\:\mathbb{R}^{\mathrm{2}} \:\mathrm{for}\:{x},{y}\:\mathrm{this}\:\mathrm{system}:\: \\ $$$$\begin{cases}{{x}\mathrm{sin}\:{t}−{y}\mathrm{cos}\:{t}=−\mathrm{a}}\\{{x}\mathrm{cos}\:{t}+{y}\mathrm{sin}\:{t}={b}.}\end{cases} \\ $$$$ \\ $$$$\left.\mathrm{2}\right)/\mathrm{Demonstrate}\:\mathrm{that}\:\mathrm{these}\:\mathrm{solutions}\:\mathrm{can} \\ $$$$\mathrm{be}\:\mathrm{written}\:\mathrm{like}\:\mathrm{this}\:\left(\:{r}\:\mathrm{and}\:\theta\:\in\:\mathbb{R}\right). \\…
Question Number 160529 by LEKOUMA last updated on 01/Dec/21 $${Resolve}\: \\ $$$$\:{u}_{{n}} −\mathrm{3}{u}_{{n}−\mathrm{1}} =\mathrm{12}\left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{{n}} \:\:{and} \\ $$$$\:{u}_{{n}} =\mathrm{2}{u}_{{n}−\mathrm{1}} +\mathrm{5cos}\:\left({n}\frac{\Pi}{\mathrm{3}}\right),\:\:{u}_{{o}} =\mathrm{1} \\ $$ Answered by mr…
Question Number 94992 by Mr.D.N. last updated on 22/May/20 $$\:\mathrm{1}.\:\mathrm{Show}\:\:\mathrm{that}: \\ $$$$\:\:\:\int_{\mathrm{0}} ^{\:\:\pi} \:\:\:\frac{\mathrm{xdx}}{\left(\mathrm{a}^{\mathrm{2}} \mathrm{sin}^{\mathrm{2}} \mathrm{x}+\mathrm{b}^{\mathrm{2}} \mathrm{cos}^{\mathrm{2}} \mathrm{x}\right)^{\mathrm{2}} }\:=\:\frac{\pi^{\mathrm{2}} \left(\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} \right)}{\mathrm{4a}^{\mathrm{3}} \mathrm{b}^{\mathrm{3}} } \\…
Question Number 160526 by mathocean1 last updated on 14/Dec/21 $${Montre}\:{que}\:{Sup}\left({A}−{B}\right)={Sup}\left({A}\right)−{Inf}\left({B}\right) \\ $$$${Avec}\:{A}−{B}=\left\{{a}−{b}\:;\:{a}\in\:{A}\:,\:{b}\in\:{B}\right\} \\ $$ Answered by puissant last updated on 01/Dec/21 $${Il}\:{faut}\:{bien}\:{recopier}\:{l}'{enonc}\acute {{e}}\:{de}\:{l}'{exercice} \\ $$$${c}'{est}\:{A}−{B}=\left\{{a}−{b}\:;\:{a}\in{A}\:,\:{b}\in{B}\right\}…
Question Number 160521 by crushh last updated on 01/Dec/21 $$\left({y}^{\mathrm{2}} +\mathrm{4}{y}\right)\sqrt{{x}+\mathrm{2}}=\left(\mathrm{2}{x}+\mathrm{1}\right)\left({y}+\mathrm{1}\right) \\ $$$$\left(\frac{\mathrm{2}{x}+\mathrm{1}}{{y}}\right)^{\mathrm{2}} +{x}=\mathrm{2}{y}^{\mathrm{2}} +\mathrm{10}{y}+\mathrm{3} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 160496 by mathlove last updated on 30/Nov/21 Answered by Kamel last updated on 01/Dec/21 $$ \\ $$$${z}^{\mathrm{2}{n}+\mathrm{1}} −\mathrm{1}=\underset{{k}=\mathrm{0}} {\overset{\mathrm{2}{n}} {\prod}}\left({z}−{e}^{\frac{\mathrm{2}{k}\pi{i}}{\mathrm{2}{n}+\mathrm{1}}} \right) \\ $$$$\therefore\:\:\underset{{k}=\mathrm{0}}…
Question Number 160493 by SANOGO last updated on 30/Nov/21 $${montrer}\:{a}\:{l}\:{aide}\:{de}\:{binome}\:{de}\:{newton}\:{que}:\: \\ $$$$\underset{{k}={o}} {\overset{{r}} {\sum}}\left(\underset{{k}} {\:}^{{n}} \right)\left(_{{r}−{k}} ^{{m}} \right)=\left(_{\:\:\:\:\:{r}} ^{{m}+{n}} \right)\: \\ $$ Answered by mr…
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