Question Number 94849 by mathocean1 last updated on 21/May/20 $$\mathrm{Calculate}\:\mathrm{limits}\:\mathrm{of}\:{f}\:\mathrm{at}\:+\infty;\:−\mathrm{1}\:\mathrm{and}\:\mathrm{1} \\ $$$${f}\left({x}\right)=\mathrm{2}{x}+\mathrm{3}−\frac{{x}}{\mathrm{1}−{x}^{\mathrm{2}} } \\ $$ Answered by mathmax by abdo last updated on 21/May/20 $$\mathrm{f}\left(\mathrm{x}\right)\:=\mathrm{2x}+\mathrm{3}+\frac{\mathrm{x}}{\mathrm{x}^{\mathrm{2}}…
Question Number 160371 by stelor last updated on 28/Nov/21 $${li}\underset{{t}\rightarrow{a}} {{m}}\frac{\left({alnt}−{tlna}\right)^{\mathrm{2}} \left({tlnt}−{alna}\right)}{\mathrm{2}\left({t}−{a}\right)\left({t}−{a}−{aln}\frac{{t}}{{a}}\right)} \\ $$$${please}\:{help}\:{me}. \\ $$ Answered by mathmax by abdo last updated on 28/Nov/21…
Question Number 29286 by mrW2 last updated on 06/Feb/18 $${To}\:{Developer}\:{Tinku}\:{Tara}: \\ $$$${Since}\:{the}\:{recent}\:{updates},\:{it}\:{is}\:{not}\:{more} \\ $$$${possible}\:{to}\:{change}\:{an}\:{existing}\:{image}\:{via} \\ $$$${Edit}\:{Post}''.\:{This}\:{was}\:{possible}\:{in}\:{earlier} \\ $$$${versions}\:{of}\:{the}\:{app}.\:{Can}\:{you}\:{please} \\ $$$${fix}\:{this}\:{problem}?\:{Thank}\:{you}! \\ $$ Commented by Rasheed.Sindhi…
Question Number 160344 by krupa last updated on 28/Nov/21 $${compare}\:{the}\:{following}\:{numbers}\:\frac{\mathrm{12}}{\mathrm{15}}\:,\frac{\mathrm{3}}{\mathrm{5}} \\ $$ Answered by FelipeLz last updated on 28/Nov/21 $$\frac{\mathrm{12}}{\mathrm{15}}\:=\:\frac{\mathrm{4}}{\mathrm{5}}\:>\:\frac{\mathrm{3}}{\mathrm{5}}\:\Rightarrow\:\frac{\mathrm{12}}{\mathrm{15}}\:>\:\frac{\mathrm{3}}{\mathrm{5}} \\ $$ Answered by Rasheed.Sindhi…
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Question Number 160314 by MathsFan last updated on 27/Nov/21 $${suppose}\:{the}\:{probability}\:{of}\:{a}\:{child} \\ $$$${being}\:{a}\:{boy}\:{is}\:\mathrm{0}.\mathrm{5}.\:{Find}\:{the}\: \\ $$$${probability}\:{that}\:{a}\:{family}\:{of}\: \\ $$$$\:\mathrm{3}\:{children}\:{will}\:{have}\: \\ $$$$\left({i}\right)\:{at}\:{least}\:{two}\:{boys} \\ $$$$\left({ii}\right)\:{exactly}\:{two}\:{boys} \\ $$$$\left({iii}\right)\:{all}\:{girls} \\ $$ Commented…
Question Number 29241 by mondodotto@gmail.com last updated on 05/Feb/18 Answered by ajfour last updated on 05/Feb/18 $${k}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)+{y}^{\mathrm{2}} +\mathrm{4}{y}−\mathrm{4}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{3}=\mathrm{0} \\ $$$${coeff}.\:{of}\:{x}^{\mathrm{2}} ={coeff}.\:{of}\:{y}^{\mathrm{2}} \\…
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Question Number 94774 by Hamida last updated on 20/May/20 Commented by peter frank last updated on 20/May/20 $$\mathrm{u}=\left(\mathrm{5x}^{\mathrm{2}} −\mathrm{2x}\right)^{\mathrm{3}} \\ $$$$\frac{\mathrm{du}}{\mathrm{dx}}=\mathrm{3}\left(\mathrm{5x}^{\mathrm{2}} −\mathrm{2x}\right)^{\mathrm{2}} \left(\mathrm{10x}−\mathrm{2}\right) \\ $$$$\mathrm{t}=\mathrm{sin}\:^{\mathrm{2}}…
Question Number 94773 by Hamida last updated on 20/May/20 Answered by prakash jain last updated on 20/May/20 $${slope}=\frac{{dy}}{{dx}}=\frac{{dy}/{dt}}{{dx}/{dt}}=\frac{\mathrm{8}{t}+\mathrm{1}}{\mathrm{3}{t}^{\mathrm{2}} +\mathrm{9}} \\ $$$${at}\:{t}=\mathrm{1}\:\mathrm{slopd}=\frac{\mathrm{9}}{\mathrm{12}}=\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\mathrm{point}\:\mathrm{on}\:\mathrm{curve}\:\mathrm{at}\:{t}=\mathrm{1} \\ $$$${y}=\mathrm{5},\:{x}=\mathrm{10}…