Question Number 161241 by help last updated on 14/Dec/21 Answered by mr W last updated on 15/Dec/21 $${let}\:{y}={xt} \\ $$$${y}'={t}+{x}\frac{{dt}}{{dx}}=\frac{{t}^{\mathrm{2}} −\mathrm{1}}{{t}} \\ $$$${x}\frac{{dt}}{{dx}}=\frac{{t}^{\mathrm{2}} −\mathrm{1}}{{t}}−{t}=−\frac{\mathrm{1}}{{t}} \\…
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Question Number 30160 by naka3546 last updated on 17/Feb/18 Commented by ajfour last updated on 18/Feb/18 $${is}\:{it}\:{right}\:? \\ $$ Commented by ajfour last updated on…
Question Number 30159 by naka3546 last updated on 17/Feb/18 Commented by mrW2 last updated on 18/Feb/18 $${sir},\:{please}\:{check}\:{your}\:{question}. \\ $$$${I}\:{think}\:{the}\:{given}\:{configuration}\:{leads} \\ $$$${to}\:{no}\:{normal}\:{solution}. \\ $$$${If}\:{BD}=\mathrm{5}\:{cm},\:{then}\:{AC}\:{must}\:{be}\:{between} \\ $$$$\mathrm{7}.\mathrm{5}\:{and}\:\mathrm{9}\:{cm}\:{to}\:{make}\:{a}\:{solution}…
Question Number 30148 by .none. last updated on 17/Feb/18 $${how}\:{to}\:{solve}\:\sqrt{\left({c}−\sqrt{−{c}}\right)^{\mathrm{2}} }+\sqrt{\left({c}+\mathrm{6}−\sqrt{−{c}}\right)^{\mathrm{2}} } \\ $$$$\mathrm{2}<{a}<\mathrm{3},\:\:−\mathrm{4}<{b}<−\mathrm{3},\:\:{c}=\frac{{a}+{b}}{\mathrm{2}} \\ $$ Answered by mrW2 last updated on 17/Feb/18 $$−\mathrm{2}<{a}+{b}<\mathrm{0} \\…
Question Number 161214 by kapoorshah last updated on 14/Dec/21 Commented by mr W last updated on 14/Dec/21 $${you}\:{can}\:{not}\:{uniquely}\:{determine} \\ $$$${three}\:{unknowns}\:{if}\:{only}\:{two}\:{equations} \\ $$$${are}\:{given}.\:{i}.{e}.\:{xyz}\:{is}\:{not}\:{unique}! \\ $$ Commented…
Question Number 95676 by Rio Michael last updated on 26/May/20 $$\mathrm{determine}\:\mathrm{the}\:\mathrm{null}\:\mathrm{space}\:\mathrm{of}\:\mathrm{the}\:\mathrm{matrix}\:\begin{pmatrix}{\mathrm{1}}&{−\mathrm{7}}\\{−\mathrm{3}}&{\mathrm{21}}\end{pmatrix} \\ $$$$\mathrm{please}\:\mathrm{any}\:\mathrm{question}\:\mathrm{number}\:\mathrm{having}\:\mathrm{the}\:\mathrm{definition}\:\mathrm{of} \\ $$$$\mathrm{linear}\:\mathrm{dependent}\:\mathrm{and}\:\mathrm{linearly}\:\mathrm{independent}\:\mathrm{vectors}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 161205 by mathocean1 last updated on 14/Dec/21 $${Soit}\:{f}:\:{E}\rightarrow{F}\:{une}\:{application}.\: \\ $$$$\mathscr{P}\left({E}\right)\:{est}\:{l}'{ensemble}\:{des}\:{parties} \\ $$$${de}\:{E}.\:{Montrer}\:{que}: \\ $$$${f}\:{est}\:{surjective}\Leftrightarrow\forall\:{B}\:\in\:\mathscr{P}\left({E}\right),\:{f}\left({f}^{−\mathrm{1}} \left({B}\right)\right)={B}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 161204 by mathocean1 last updated on 14/Dec/21 $${Soit}\:{f}:\:{E}\rightarrow{F}\:,\:{une}\:{application}. \\ $$$$\mathscr{P}\left({E}\right)\:{est}\:{l}'{ensemble}\:{des}\:{parties} \\ $$$${de}\:{E}. \\ $$$${Montrer}\:{que}\:{f}\:{est}\:{injective}\:\Leftrightarrow\:\forall\:{A}\:\in\:\mathscr{P}\left({E}\right),\:{A}\:\subset\:{f}^{−\mathrm{1}} \left({f}\left({A}\right)\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 161203 by shubh last updated on 14/Dec/21 $${Rashid}\:{Shindhi}−\:{I}\:{have}\:{a}\:{question}\:{to}\:{u}\:{that}\:{how}\:{do}\:{u}\:{cut}\:{the}\:{x}\:{of}\:\:{nominator}\:{and}\:{denominator}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com