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Question Number 159759 by SANOGO last updated on 21/Nov/21 Answered by puissant last updated on 21/Nov/21 $${Soit}\:{x}\:{cette}\:{largeur}.. \\ $$$${en}\:{effet}\:,\:{la}\:{longueur}\:{restante}\:{est}\: \\ $$$$\mathrm{4}−{x}\:{et}\:{la}\:{largeur}\:{restante}\:{est}\:\mathrm{3}−{x} \\ $$$${Ainsi}\:{l}'{aire}\:{restante}\:{est}\:\left(\mathrm{4}−{x}\right)\left(\mathrm{3}−{x}\right) \\ $$$$\Rightarrow\:\mathscr{A}_{{r}}…
Question Number 94214 by abony1303 last updated on 17/May/20 $${Find}\:{f}\left(\mathrm{0}\right)\:{when}\:{a}\:{polynomial}\:{f}\left({x}\right)\:{satisfies} \\ $$$$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{{f}\left({x}\right)}{{x}^{\mathrm{2}} −\mathrm{1}}=\mathrm{2} \\ $$$$\underset{{x}\rightarrow−\mathrm{1}} {\mathrm{lim}}\:\:\frac{{f}\left({x}\right)}{{x}^{\mathrm{2}} −\mathrm{1}}=\mathrm{2}\:\: \\ $$$$\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\:\:\frac{{f}\left({x}\right)}{{x}^{\mathrm{4}} }\:=\mathrm{1}\:\:\:\:\:\:\:\:{pls}\:{Help}! \\ $$ Commented…
Question Number 94212 by abony1303 last updated on 17/May/20 Answered by john santu last updated on 17/May/20 $$\left(\mathrm{1}\right)\:\underset{{x}\rightarrow\mathrm{1}^{−} } {\mathrm{lim}}\:\mathrm{f}\left(\mathrm{x}\right)=\underset{{x}\rightarrow\mathrm{1}^{+} } {\mathrm{lim}f}\left(\mathrm{x}\right) \\ $$$$\underset{{x}\rightarrow\mathrm{1}^{−} }…
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Question Number 159744 by 0731619 last updated on 20/Nov/21 Answered by gsk2684 last updated on 20/Nov/21 $$\frac{\mathrm{0}}{\mathrm{0}}\:{form},\:{apply}\:{L}'{hospital}\:{rule} \\ $$$$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\frac{−\left(\mathrm{cos}\:\frac{\pi}{{x}}\right)\left(−\frac{\pi}{{x}^{\mathrm{2}} }\right)}{\left(\mathrm{sin}\:\pi{x}\right)\pi}=\underset{{x}\rightarrow\mathrm{2}} {\frac{\mathrm{1}}{\mathrm{4}}\mathrm{lim}\frac{\left(\mathrm{cos}\:\frac{\pi}{{x}}\right)}{\left(\mathrm{sin}\:\pi{x}\right)}\:} \\ $$$${again}\:{apply}\:{the}\:{same}\:{rule} \\…
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Question Number 159733 by metamorfose last updated on 20/Nov/21 $$\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\:\frac{\lfloor{xcos}\left({x}\right)\rfloor}{{xsin}\left(\pi\lfloor\frac{{e}^{\frac{\mathrm{1}}{{x}}} }{{ln}\left({x}\right)}\rfloor\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 94193 by seedhamaieng@gmail.com last updated on 17/May/20 Commented by seedhamaieng@gmail.com last updated on 17/May/20 translate into Hind language Question no 7 Commented by seedhamaieng@gmail.com last updated on 17/May/20 Commented…
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