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If-a-and-b-are-roots-of-the-eqn-x-2-x-1111111122222222-Find-the-value-of-a-b-

Question Number 93687 by Ayod 19 last updated on 14/May/20 $$\mathrm{If}\:{a}\:\mathrm{and}\:{b}\:\mathrm{are}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{eqn} \\ $$$$\:\mathrm{x}^{\mathrm{2}\:} +\mathrm{x}=\mathrm{1111111122222222} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{a}−{b}. \\ $$ Commented by Kunal12588 last updated on 14/May/20…

Question-159172

Question Number 159172 by aliibrahim1 last updated on 13/Nov/21 Answered by ajfour last updated on 13/Nov/21 $${Apply}\:{Integration}\:{by}\:{parts};{also} \\ $$$$\int{e}^{{x}} \left\{{f}\left({x}\right)+{f}\:'\left({x}\right)\right\}{dx}={e}^{{x}} {f}\left({x}\right)+{c} \\ $$$${Here}\:\:\:\frac{{y}}{\left({y}+\mathrm{1}\right)^{\mathrm{2}} }=\frac{{y}+\mathrm{1}−\mathrm{1}}{\left({y}+\mathrm{1}\right)^{\mathrm{2}} }…

Three-students-are-runing-for-school-SRC-president-kada-s-probability-of-winning-is-1-8-Atiga-s-probability-of-winnig-1-3-and-kada-is-half-as-likely-to-win-as-Apio-i-what-is-the-probabilit

Question Number 159159 by otchereabdullai@gmail.com last updated on 13/Nov/21 $$\:\mathrm{Three}\:\mathrm{students}\:\mathrm{are}\:\mathrm{runing}\:\mathrm{for}\:\mathrm{school} \\ $$$$\:\mathrm{SRC}\:\mathrm{president},\:\mathrm{kada}'\mathrm{s}\:\mathrm{probability}\:\mathrm{of} \\ $$$$\mathrm{winning}\:\mathrm{is}\:\frac{\mathrm{1}}{\mathrm{8}},\:\mathrm{Atiga}'\mathrm{s}\:\mathrm{probability}\: \\ $$$$\mathrm{of}\:\mathrm{winnig}\:\frac{\mathrm{1}}{\mathrm{3}}\:\mathrm{and}\:\mathrm{kada}\:\mathrm{is}\:\mathrm{half}\:\mathrm{as}\:\mathrm{likely} \\ $$$$\mathrm{to}\:\mathrm{win}\:\mathrm{as}\:\mathrm{Apio}.\: \\ $$$$\mathrm{i}.\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{both}\: \\ $$$$\:\mathrm{Atiga}\:\mathrm{and}\:\mathrm{Apio}\:\mathrm{draw} \\ $$$$\mathrm{ii}.\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{only} \\…

Question-28070

Question Number 28070 by naka3546 last updated on 19/Jan/18 Answered by mrW2 last updated on 20/Jan/18 $${let}\:\angle{QSR}=\alpha \\ $$$$\angle{PQS}=\alpha−\mathrm{40} \\ $$$$\frac{{PS}}{\mathrm{sin}\:\left(\alpha−\mathrm{40}\right)}=\frac{{PQ}}{\mathrm{sin}\:\left(\mathrm{180}−\alpha\right)}=\frac{{PQ}}{\mathrm{sin}\:\alpha} \\ $$$$\Rightarrow{PS}=\frac{\mathrm{sin}\:\left(\alpha−\mathrm{40}\right)}{\mathrm{sin}\:\alpha}×{PQ} \\ $$$$\frac{{QR}}{\mathrm{sin}\:\mathrm{40}}=\frac{{PQ}}{\mathrm{sin}\:\left(\mathrm{90}−\frac{\mathrm{40}}{\mathrm{2}}\right)}=\frac{{PQ}}{\mathrm{cos}\:\mathrm{20}}…