Question Number 93512 by Shakhzod last updated on 13/May/20 $$\left({xy}+\mathrm{sin}\:{y}\right){dx}+\left(\mathrm{0}.\mathrm{5}{x}^{\mathrm{2}} +{x}\mathrm{cos}\:{y}\right){dy}={o} \\ $$ Commented by i jagooll last updated on 14/May/20 $$\mathrm{sin}\:\mathrm{ydx}+\mathrm{xcos}\:\mathrm{ydy}\:=\:−\mathrm{0}.\mathrm{5x}^{\mathrm{2}} \mathrm{dy}−\mathrm{xydx} \\ $$$$\mathrm{d}\left(\mathrm{xsin}\:\mathrm{y}\right)=\:−\:\left(\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{x}^{\mathrm{2}}…
Question Number 93510 by Shakhzod last updated on 13/May/20 $${y}^{'} −{y}.\mathrm{tan}\:{x}+{y}^{\mathrm{2}} \mathrm{cos}\:{x}=\mathrm{0} \\ $$ Commented by Shakhzod last updated on 13/May/20 $${Friends}\:{help}\:{me}\:{please}. \\ $$ Terms…
Question Number 93509 by Shakhzod last updated on 13/May/20 $$\sum_{{n}=\mathrm{1}} ^{\infty} \frac{\mathrm{1}}{{n}^{\mathrm{2}} +\mathrm{5}{n}+\mathrm{6}}\: \\ $$ Commented by Shakhzod last updated on 13/May/20 $${Help}\:{me}\:{who}\:{can}\:{solve}\:{it}. \\ $$…
Question Number 159029 by otchereabdullai@gmail.com last updated on 12/Nov/21 $$\:\mathrm{In}\:\mathrm{a}\:\mathrm{box}\:\mathrm{of}\:\mathrm{marbles},\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{red} \\ $$$$\mathrm{marble}\:\mathrm{to}\:\mathrm{total}\:\mathrm{marble}\:\mathrm{is}\:\mathrm{2}\::\mathrm{5},\:\mathrm{the}\: \\ $$$$\mathrm{ratio}\:\mathrm{of}\:\mathrm{green}\:\mathrm{marble}\:\mathrm{to}\:\mathrm{the}\:\mathrm{total}\: \\ $$$$\mathrm{marble}\:\mathrm{is}\:\mathrm{3}:\mathrm{10}\:.\:\mathrm{If}\:\mathrm{the}\:\mathrm{marbles}\:\mathrm{that}\:\mathrm{are} \\ $$$$\mathrm{neither}\:\mathrm{red}\:\mathrm{nor}\:\mathrm{green}\:\mathrm{are}\:\mathrm{blue},\:\mathrm{how}\: \\ $$$$\mathrm{many}\:\mathrm{marbles}\:\mathrm{are}\:\mathrm{in}\:\mathrm{the}\:\mathrm{box}\:\mathrm{if}\:\mathrm{there} \\ $$$$\mathrm{are}\:\mathrm{40}\:\mathrm{marbles}\:\mathrm{in}\:\mathrm{the}\:\mathrm{box} \\ $$ Commented…
Question Number 159027 by otchereabdullai@gmail.com last updated on 12/Nov/21 $$\mathrm{A}\:\mathrm{mountain}\:\mathrm{trail}\:\mathrm{is}\:\mathrm{12}.\mathrm{1}\:\mathrm{mile}\:\mathrm{long}.\:\mathrm{If} \\ $$$$\mathrm{a}\:\mathrm{hiker}\:\mathrm{walks}\:\mathrm{along}\:\mathrm{the}\:\mathrm{trail}\:\mathrm{at}\:\mathrm{rate}\:\mathrm{of} \\ $$$$\mathrm{1}.\mathrm{96}\:\mathrm{miles}\:\mathrm{per}\:\mathrm{hour}\:\mathrm{approximatly},\: \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{hours}\:\mathrm{will}\:\mathrm{the}\:\mathrm{hiker}\:\mathrm{walk}\: \\ $$$$\mathrm{the}\:\mathrm{entire}\:\mathrm{trail} \\ $$$$ \\ $$ Commented by mr…
Question Number 27944 by Tinkutara last updated on 17/Jan/18 $${Did}\:{anybody}\:{give}\:{Silverzone}\:{iOM}\:{of} \\ $$$${class}\:\mathrm{11}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 159015 by Armindo last updated on 11/Nov/21 Answered by mr W last updated on 12/Nov/21 $${say}\:\sqrt{\mathrm{2}}=\frac{{p}}{{q}}\:{with}\:{gcd}\left({p},{q}\right)=\mathrm{1} \\ $$$$\mathrm{2}=\frac{{p}^{\mathrm{2}} }{{q}^{\mathrm{2}} } \\ $$$${p}^{\mathrm{2}} =\mathrm{2}{q}^{\mathrm{2}}…
Question Number 159010 by SANOGO last updated on 11/Nov/21 $${f}:{N}\rightarrow{N} \\ $$$${n}\rightarrow\left\{_{{n}+\mathrm{1}\:{si}\:{impair}} ^{{n}\:\:{si}\:{paire}} \right. \\ $$$${f}\:{est}−{il}\:{injective},{surj}\:{ou}\:{bijec}\:? \\ $$ Commented by SLVR last updated on 12/Nov/21…
Question Number 159011 by SANOGO last updated on 11/Nov/21 $${G}:{N}\rightarrow{N} \\ $$$${n}\rightarrow\left\{_{{n}+\mathrm{1}\:{si}\:{n}\:{est}\:{paire}} ^{{n}\:\:{si}\:{n}\:{est}\:{impair}} \right. \\ $$$${g}\:{est}−{il}\:{inject}\:,{surject}\:{ou}\:{biject}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 158988 by cortano last updated on 11/Nov/21 Answered by Rasheed.Sindhi last updated on 11/Nov/21 $$\mathcal{T}{he}\:{graph}\:{of}\:{f}\left({x}\right)\:{intersects}\:{y}=\mathrm{2}{x}−\mathrm{1} \\ $$$${at}\:{x}=\mathrm{1},\mathrm{2},\mathrm{3} \\ $$$$\therefore\:\mathcal{T}{he}\:{points}\:{of}\:{intersections}: \\ $$$$\:\:\:\:\:\:\left(\mathrm{1},\mathrm{2}\left(\mathrm{1}\right)−\mathrm{1}\right)\:,\:\left(\mathrm{2},\mathrm{2}\left(\mathrm{2}\right)−\mathrm{1}\right)\:\&\left(\mathrm{3},\mathrm{2}\left(\mathrm{3}\right)−\mathrm{1}\right) \\ $$$$\:\:\:{Or}\:\left(\mathrm{1},\mathrm{1}\right),\left(\mathrm{2},\mathrm{3}\right)\:\&\:\left(\mathrm{3},\mathrm{5}\right)\:…