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Question-28938

Question Number 28938 by mondodotto@gmail.com last updated on 01/Feb/18 Commented by Cheyboy last updated on 02/Feb/18 $${let}\:{andre}'{s}\:{money}\:{be}=\:{x} \\ $$$${let}\:{Bob}'{s}\:{money}\:{be}={y} \\ $$$${x}−\mathrm{20}={y}+\mathrm{20}\Rightarrow\left(\mathrm{1}\right) \\ $$$$\mathrm{2}\left({y}−\mathrm{22}\right)={x}+\mathrm{22}\Rightarrow\left(\mathrm{2}\right) \\ $$$${x}−{y}=\mathrm{40}…

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Question Number 159994 by mathocean1 last updated on 23/Nov/21 $$ \\ $$$$\mathrm{montrer}\:\mathrm{que}\:\mathrm{le}\:\mathrm{quotient}\:\mathrm{d}'\mathrm{un} \\ $$$$\mathrm{nombe}\:\mathrm{rationnel}\:\mathrm{et}\:\mathrm{dun}\:\mathrm{nombre}\: \\ $$$$\mathrm{irr}{a}\mathrm{tionnel}\:\mathrm{est}\:\mathrm{irrationnel} \\ $$ Answered by Tokugami last updated on 23/Nov/21…

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Question Number 159962 by bounhome last updated on 23/Nov/21 $${show}\:{me}:\:{these}\:{are}\:{the}\:{cauchy}\:{criterion}.\:{please} \\ $$$$\mathrm{1}.\left(\frac{{n}+\mathrm{1}}{{n}}\right) \\ $$$$\mathrm{2}.\:\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}!}+\frac{\mathrm{1}}{\mathrm{3}!}+…+\frac{\mathrm{1}}{{n}!}\right) \\ $$$$\mathrm{3}.\:\left(\left(−\mathrm{1}\right)^{{n}} \right) \\ $$$$\mathrm{4}.\:{n}+\frac{\left(−\mathrm{1}\right)^{{n}} }{{n}} \\ $$$$\mathrm{5}.\left(\mathrm{1}{nm}\right) \\ $$$$ \\…

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Question Number 94416 by Ar Brandon last updated on 18/May/20 $$\mathrm{A}\:\mathrm{direct}\:\mathrm{similitude}\:\mathrm{of}\:\mathrm{center},\Omega,\:\mathrm{transforms}\:\mathrm{point}\:\mathrm{A}\:\mathrm{into}\:\mathrm{point}\:\mathrm{A}' \\ $$$$\mathrm{and}\:\mathrm{point}\:\mathrm{B}\:\mathrm{into}\:\mathrm{point}\:\mathrm{B}'.\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{there}\:\mathrm{existe}\:\mathrm{a} \\ $$$$\mathrm{direct}\:\mathrm{similitude}\:\mathrm{of}\:\mathrm{center},\Omega,\:\mathrm{which}\:\mathrm{transforms}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{into}\:\mathrm{A}'\:\mathrm{and}\:\mathrm{B}'. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

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Question Number 159873 by pticantor last updated on 22/Nov/21 $${j}'{ai}\:{b}\boldsymbol{{esoin}}\:\boldsymbol{{de}}\:\boldsymbol{{la}}\:\boldsymbol{{version}}\:\boldsymbol{{pc}}\:\boldsymbol{{de}}\:\boldsymbol{{cette}}\:\boldsymbol{{application}} \\ $$$$\boldsymbol{{et}}\:\boldsymbol{{je}}\:\boldsymbol{{veux}}\:\boldsymbol{{savoir}}\:\boldsymbol{{ci}}\:\boldsymbol{{cest}}\:\boldsymbol{{possible}}\:\boldsymbol{{de}}\:\boldsymbol{{transformer}}\:\boldsymbol{{les}}\:\boldsymbol{{documents}}\:.\boldsymbol{{med}}\:\boldsymbol{{en}}\:.\boldsymbol{{pdf}} \\ $$$$ \\ $$ Answered by Tinku Tara last updated on 22/Nov/21 $$\mathrm{There}\:\mathrm{is}\:\mathrm{no}\:\mathrm{PC}\:\mathrm{version}\:\mathrm{of}\:\mathrm{this}\:\mathrm{application}.…