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Question Number 159744 by 0731619 last updated on 20/Nov/21 Answered by gsk2684 last updated on 20/Nov/21 $$\frac{\mathrm{0}}{\mathrm{0}}\:{form},\:{apply}\:{L}'{hospital}\:{rule} \\ $$$$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\frac{−\left(\mathrm{cos}\:\frac{\pi}{{x}}\right)\left(−\frac{\pi}{{x}^{\mathrm{2}} }\right)}{\left(\mathrm{sin}\:\pi{x}\right)\pi}=\underset{{x}\rightarrow\mathrm{2}} {\frac{\mathrm{1}}{\mathrm{4}}\mathrm{lim}\frac{\left(\mathrm{cos}\:\frac{\pi}{{x}}\right)}{\left(\mathrm{sin}\:\pi{x}\right)}\:} \\ $$$${again}\:{apply}\:{the}\:{same}\:{rule} \\…
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Question Number 159733 by metamorfose last updated on 20/Nov/21 $$\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\:\frac{\lfloor{xcos}\left({x}\right)\rfloor}{{xsin}\left(\pi\lfloor\frac{{e}^{\frac{\mathrm{1}}{{x}}} }{{ln}\left({x}\right)}\rfloor\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 94193 by seedhamaieng@gmail.com last updated on 17/May/20 Commented by seedhamaieng@gmail.com last updated on 17/May/20 translate into Hind language Question no 7 Commented by seedhamaieng@gmail.com last updated on 17/May/20 Commented…
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Question Number 94191 by oustmuchiya@gmail.com last updated on 17/May/20 Answered by mr W last updated on 17/May/20 $$\overset{\rightarrow} {{AD}}=\boldsymbol{{c}}+\frac{\boldsymbol{{a}}}{\mathrm{2}} \\ $$$$\overset{\rightarrow} {{BE}}=\boldsymbol{{a}}+\frac{\boldsymbol{{b}}}{\mathrm{2}} \\ $$$$\overset{\rightarrow} {{CF}}=\boldsymbol{{b}}+\frac{\boldsymbol{{c}}}{\mathrm{2}}…
Question Number 159723 by stelor last updated on 20/Nov/21 $$\frac{\mathrm{1}}{{k}+\mathrm{1}}\leqslant\int_{{k}} ^{{k}+\mathrm{1}} \left(\frac{\mathrm{1}}{{x}}\right){dx}\leqslant\frac{\mathrm{1}}{{k}}\:\:\:\:\:\:\:\:\: \\ $$$$\:{please}\:{show}\:{it}\:{with}\:{k}\in\aleph−\left(\mathrm{0}\right) \\ $$$$ \\ $$ Commented by stelor last updated on 20/Nov/21…
Question Number 159716 by mathocean1 last updated on 20/Nov/21 $${Show}\:{that}\:\bigtriangledown{r}^{{n}} ={nr}^{{n}−\mathrm{2}} {r} \\ $$ Answered by puissant last updated on 20/Nov/21 $$\bigtriangledown{r}^{{n}} \:=\:{nr}^{{n}−\mathrm{1}} \:=\:{nr}^{{n}−\mathrm{2}} ×{r}…
Question Number 94158 by seedhamaieng@gmail.com last updated on 17/May/20 Commented by prakash jain last updated on 17/May/20 $$\mathrm{mass}\:{m} \\ $$$$\mathrm{acceleration}\:{a}=−\frac{{R}}{{m}} \\ $$$$\:\:\:\:\:−{ve}\:{acclerarion}\:{as}\:{mention}\:{in} \\ $$$$\:\:\:\:\:\:{question} \\…