Question Number 94096 by Rio Michael last updated on 16/May/20 $$\mathrm{The}\:\mathrm{result}\:\mathrm{of}\:\mathrm{adding}\:\mathrm{the}\:\mathrm{odd}\:\mathrm{natural}\:\mathrm{numbers}\:\mathrm{is}: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}\:=\:\mathrm{1} \\ $$$$\:\:\:\:\:\:\:\:\mathrm{1}\:+\:\mathrm{3}=\mathrm{4} \\ $$$$\:\:\mathrm{1}\:+\:\mathrm{3}+\:\mathrm{5}\:=\:\mathrm{9} \\ $$$$\mathrm{1}\:+\:\mathrm{3}\:+\:\mathrm{5}\:+\mathrm{7}\:=\:\mathrm{16} \\ $$$$\mathrm{1}\:+\:\mathrm{3}\:+\:\mathrm{5}\:+\:\mathrm{7}+\mathrm{9}\:=\:\mathrm{25} \\ $$$$\:\mathrm{show}\:\mathrm{that}\:\mathrm{from}\:\mathrm{this}\:\mathrm{result},\:\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\mathrm{2}{i}−\mathrm{1}\right)\:=\:{n}^{\mathrm{2}}…
Question Number 159591 by mathocean1 last updated on 19/Nov/21 $$\sqrt{\mathrm{3}}\:{and}\:\sqrt{\mathrm{5}}\:{are}\:{irrational}\:{numbers}. \\ $$$${Given}\:{i}=\sqrt{\mathrm{5}}−\sqrt{\mathrm{3}}\:. \\ $$$${Show}\:{that}\:{i}\:{is}\:{irrational}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 159581 by mathlove last updated on 19/Nov/21 Commented by som(math1967) last updated on 19/Nov/21 $$\frac{\mathrm{9}}{\mathrm{3}}=\mathrm{3}\:\:\left[{when}\:{a},{b},{c}\neq\mathrm{0}\:\right] \\ $$ Commented by mathlove last updated on…
Question Number 28501 by naka3546 last updated on 26/Jan/18 Commented by naka3546 last updated on 26/Jan/18 $${ABCD}\:\:{is}\:\:{not}\:\:{square}. \\ $$$${Length}\:{DE}\:\:? \\ $$ Answered by mrW2 last…
Question Number 28480 by naka3546 last updated on 26/Jan/18 Commented by math solver last updated on 29/Jan/18 $${what}\:{is}\:{full}\:{form}\:{of}\:{sbmptn}? \\ $$ Answered by ajfour last updated…
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Question Number 28479 by naka3546 last updated on 26/Jan/18 Answered by ajfour last updated on 26/Jan/18 $$\mathrm{1}+\frac{\pi}{\mathrm{3}}−\sqrt{\mathrm{3}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 28456 by mondodotto@gmail.com last updated on 26/Jan/18 Commented by Tinkutara last updated on 26/Jan/18 5 Answered by Rasheed.Sindhi last updated on 26/Jan/18 $$\mathrm{f}\left(\mathrm{2}\right)=\mathrm{5},\mathrm{f}\left(\mathrm{3}\right)=\mathrm{4},\mathrm{g}\left(\mathrm{2}\right)=\mathrm{5},\mathrm{g}\left(\mathrm{3}\right)=\mathrm{2},\mathrm{g}\left(\mathrm{4}\right)=\mathrm{1}…
Question Number 159497 by naka3546 last updated on 17/Nov/21 $${Prove}\:\:{that}\:\: \\ $$$$\:\:\:\:\:\mathrm{1}\:+\:\frac{\mathrm{1}}{\mathrm{4}}\:+\:\frac{\mathrm{1}}{\mathrm{9}}\:+\:\ldots+\:\frac{\mathrm{1}}{{n}^{\mathrm{2}} }\:\:<\:\:\mathrm{2} \\ $$$${for}\:\:{n}\:\in\:\:\mathbb{N}\:\:. \\ $$ Commented by mr W last updated on 18/Nov/21…
Question Number 159491 by akolade last updated on 17/Nov/21 Answered by Tokugami last updated on 18/Nov/21 $$\int_{\mathrm{0}} ^{\:\frac{{d}}{{dx}}\int_{\mathrm{0}} ^{\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:{e}^{−{x}} \underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{x}^{{k}} }{{k}!}} \pi\:{dt}}…