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A-new-version-of-application-with-a-few-usability-enhancement-will-be-available-on-playstore-in-next-few-days-Key-Changes-a-Continous-scrolling-on-forum-b-Clicking-on-images-pop-up-image-which-ca

Question Number 92544 by Tinku Tara last updated on 07/May/20 $$\mathrm{A}\:\mathrm{new}\:\mathrm{version}\:\mathrm{of}\:\mathrm{application}\:\mathrm{with} \\ $$$$\mathrm{a}\:\mathrm{few}\:\mathrm{usability}\:\mathrm{enhancement} \\ $$$$\mathrm{will}\:\:\mathrm{be}\:\mathrm{available}\:\mathrm{on}\:\mathrm{playstore} \\ $$$$\mathrm{in}\:\mathrm{next}\:\mathrm{few}\:\mathrm{days}. \\ $$$$\mathrm{Key}\:\mathrm{Changes} \\ $$$$\mathrm{a}.\:\mathrm{Continous}\:\mathrm{scrolling}\:\mathrm{on}\:\mathrm{forum}. \\ $$$$\mathrm{b}.\:\mathrm{Clicking}\:\mathrm{on}\:\mathrm{images}\:\mathrm{pop}\:\mathrm{up}\:\mathrm{image} \\ $$$$\mathrm{which}\:\mathrm{can}\:\mathrm{be}\:\mathrm{easily}\:\mathrm{scrolled}.…

d-3-x-dt-3-27-d-2-x-dt-2-243-dx-dt-729x-t-e-9t-x-0-x-0-x-0-0-Use-Laplace-Transformation-to-solve-it-

Question Number 92524 by naka3546 last updated on 07/May/20 $$\frac{{d}^{\mathrm{3}} {x}}{{dt}^{\mathrm{3}} }\:+\:\mathrm{27}\:\frac{{d}^{\mathrm{2}} {x}}{{dt}^{\mathrm{2}} }\:+\:\mathrm{243}\:\frac{{dx}}{{dt}}\:+\:\mathrm{729}{x}\:=\:{t}\centerdot\:{e}^{−\mathrm{9}{t}} \\ $$$$\:\:\:\:\:\:{x}\left(\mathrm{0}\right)\:=\:{x}'\left(\mathrm{0}\right)\:=\:{x}^{''} \left(\mathrm{0}\right)\:=\:\mathrm{0} \\ $$$${Use}\:\:{Laplace}\:\:{Transformation}\:\:{to}\:\:{solve}\:\:{it}\:. \\ $$ Terms of Service Privacy…

what-is-the-value-of-9-

Question Number 158050 by MathsFan last updated on 30/Oct/21 $$\:\mathrm{what}\:\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\:\mathrm{9}!! \\ $$ Answered by puissant last updated on 30/Oct/21 $$\mathrm{9}!!\:=\:\mathrm{9}×\mathrm{7}×\mathrm{5}×\mathrm{3}×\mathrm{1}\:=\:\mathrm{945} \\ $$ Commented…

given-2x-3y-and-4y-3z-find-3x-4y-2x-y-5z-

Question Number 157972 by MathsFan last updated on 30/Oct/21 $$\:{given}\:\:\mathrm{2}{x}=\mathrm{3}{y}\:\:{and}\:\:\mathrm{4}{y}=\mathrm{3}{z} \\ $$$$\:{find}\:\:\:\frac{\mathrm{3}{x}−\mathrm{4}{y}}{\mathrm{2}{x}−{y}+\mathrm{5}{z}} \\ $$ Commented by tounghoungko last updated on 30/Oct/21 $${let}\:\mathrm{3}{y}={k}\Rightarrow{y}=\frac{{k}}{\mathrm{3}}\:\wedge\:\mathrm{2}{x}={k}\Rightarrow{x}=\frac{{k}}{\mathrm{2}} \\ $$$$\Rightarrow{z}=\frac{\mathrm{4}{k}}{\mathrm{9}} \\…

Question-26889

Question Number 26889 by shiva123 last updated on 31/Dec/17 Answered by prakash jain last updated on 31/Dec/17 $$\mathrm{3}.\:{A}\cap\left({B}−{C}\right)=\left({A}\cap{B}\right)−\left({A}\cap{C}\right) \\ $$$${x}\in{A}\cap\left({B}−{C}\right) \\ $$$$\Rightarrow{x}\in{A}\:\wedge{x}\in\left({B}−{C}\right) \\ $$$$\Rightarrow{x}\in{A}\wedge{x}\in{B}\wedge{x}\notin{C} \\…