Question Number 159027 by otchereabdullai@gmail.com last updated on 12/Nov/21 $$\mathrm{A}\:\mathrm{mountain}\:\mathrm{trail}\:\mathrm{is}\:\mathrm{12}.\mathrm{1}\:\mathrm{mile}\:\mathrm{long}.\:\mathrm{If} \\ $$$$\mathrm{a}\:\mathrm{hiker}\:\mathrm{walks}\:\mathrm{along}\:\mathrm{the}\:\mathrm{trail}\:\mathrm{at}\:\mathrm{rate}\:\mathrm{of} \\ $$$$\mathrm{1}.\mathrm{96}\:\mathrm{miles}\:\mathrm{per}\:\mathrm{hour}\:\mathrm{approximatly},\: \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{hours}\:\mathrm{will}\:\mathrm{the}\:\mathrm{hiker}\:\mathrm{walk}\: \\ $$$$\mathrm{the}\:\mathrm{entire}\:\mathrm{trail} \\ $$$$ \\ $$ Commented by mr…
Question Number 27944 by Tinkutara last updated on 17/Jan/18 $${Did}\:{anybody}\:{give}\:{Silverzone}\:{iOM}\:{of} \\ $$$${class}\:\mathrm{11}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 159015 by Armindo last updated on 11/Nov/21 Answered by mr W last updated on 12/Nov/21 $${say}\:\sqrt{\mathrm{2}}=\frac{{p}}{{q}}\:{with}\:{gcd}\left({p},{q}\right)=\mathrm{1} \\ $$$$\mathrm{2}=\frac{{p}^{\mathrm{2}} }{{q}^{\mathrm{2}} } \\ $$$${p}^{\mathrm{2}} =\mathrm{2}{q}^{\mathrm{2}}…
Question Number 159010 by SANOGO last updated on 11/Nov/21 $${f}:{N}\rightarrow{N} \\ $$$${n}\rightarrow\left\{_{{n}+\mathrm{1}\:{si}\:{impair}} ^{{n}\:\:{si}\:{paire}} \right. \\ $$$${f}\:{est}−{il}\:{injective},{surj}\:{ou}\:{bijec}\:? \\ $$ Commented by SLVR last updated on 12/Nov/21…
Question Number 159011 by SANOGO last updated on 11/Nov/21 $${G}:{N}\rightarrow{N} \\ $$$${n}\rightarrow\left\{_{{n}+\mathrm{1}\:{si}\:{n}\:{est}\:{paire}} ^{{n}\:\:{si}\:{n}\:{est}\:{impair}} \right. \\ $$$${g}\:{est}−{il}\:{inject}\:,{surject}\:{ou}\:{biject}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 158988 by cortano last updated on 11/Nov/21 Answered by Rasheed.Sindhi last updated on 11/Nov/21 $$\mathcal{T}{he}\:{graph}\:{of}\:{f}\left({x}\right)\:{intersects}\:{y}=\mathrm{2}{x}−\mathrm{1} \\ $$$${at}\:{x}=\mathrm{1},\mathrm{2},\mathrm{3} \\ $$$$\therefore\:\mathcal{T}{he}\:{points}\:{of}\:{intersections}: \\ $$$$\:\:\:\:\:\:\left(\mathrm{1},\mathrm{2}\left(\mathrm{1}\right)−\mathrm{1}\right)\:,\:\left(\mathrm{2},\mathrm{2}\left(\mathrm{2}\right)−\mathrm{1}\right)\:\&\left(\mathrm{3},\mathrm{2}\left(\mathrm{3}\right)−\mathrm{1}\right) \\ $$$$\:\:\:{Or}\:\left(\mathrm{1},\mathrm{1}\right),\left(\mathrm{2},\mathrm{3}\right)\:\&\:\left(\mathrm{3},\mathrm{5}\right)\:…
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Question Number 27909 by mondodotto@gmail.com last updated on 16/Jan/18 Commented by abdo imad last updated on 16/Jan/18 $${we}\:{have}\:\frac{{d}}{{dx}}{ln}\left(\mathrm{1}−{x}\right)=\:\frac{−\mathrm{1}}{\mathrm{1}−{x}}=−\sum_{{n}=\mathrm{0}} ^{\propto} \:{x}^{{n}} \\ $$$$\Rightarrow\:{ln}\left(\mathrm{1}−{x}\right)=\:−\sum_{{n}=\mathrm{0}} ^{\propto} \:\frac{{x}^{{n}+\mathrm{1}} }{{n}+\mathrm{1}}\:=−\sum_{{n}=\mathrm{1}}…
Question Number 93442 by PRITHWISH SEN 2 last updated on 13/May/20 $$\mathrm{To}\:\mathrm{tinkutara} \\ $$$$\mathrm{I}\:\mathrm{have}\:\mathrm{forget}\:\mathrm{my}\:\mathrm{old}\:\mathrm{password}\:\mathrm{and}\:\mathrm{has}\:\mathrm{to}\:\mathrm{create}\:\mathrm{a} \\ $$$$\mathrm{new}\:\mathrm{one}.\:\mathrm{Is}\:\mathrm{there}\:\mathrm{any}\:\mathrm{way}\:\mathrm{to}\:\mathrm{retrive}\:\mathrm{my}\:\mathrm{old}\:\mathrm{account}. \\ $$ Commented by i jagooll last updated on…
Question Number 93434 by naka3546 last updated on 13/May/20 Commented by naka3546 last updated on 13/May/20 $${AT}^{\:\mathrm{2}} +{BT}^{\:\mathrm{2}} \:=\:\mathrm{3312} \\ $$$${CT}^{\:\mathrm{2}} +{DT}^{\:\mathrm{2}} \:=\:\mathrm{3308} \\ $$$${Radius}\:\:{of}\:\:{circle}\:\:{is}\:…\:?…