Question Number 92118 by otchereabdullai@gmail.com last updated on 04/May/20 $$\mathrm{If}\:\:\mathrm{9}^{\mathrm{2x}+\mathrm{1}\:\:\:} =\:\:\frac{\mathrm{81}^{\mathrm{x}−\mathrm{2}} }{\mathrm{3x}}\:\:.\:\:\:\:\:\:\:\:\:\:\:\mathrm{find}\:\mathrm{x} \\ $$ Commented by john santu last updated on 05/May/20 $$\mathrm{9}^{\mathrm{2x}+\mathrm{1}} \:=\:\frac{\mathrm{81}^{\mathrm{x}−\mathrm{2}} }{\mathrm{3}^{\mathrm{x}}…
Question Number 92117 by otchereabdullai@gmail.com last updated on 04/May/20 $$\mathrm{solve}\:\mathrm{for}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}\:\mathrm{if}: \\ $$$$\sqrt{\mathrm{x}}+\mathrm{y}=\mathrm{11}\:\:\:\:\mathrm{and}\:\:\:\:\mathrm{x}+\sqrt{\mathrm{y}}=\mathrm{7} \\ $$ Commented by john santu last updated on 05/May/20 Commented by niroj…
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Question Number 157611 by naka3546 last updated on 25/Oct/21 $${Given}\:\:{g}\left({x}\right)\:=\:\frac{\mathrm{1}}{\mathrm{1}\:+\:\mathrm{3}^{\frac{\mathrm{1}}{\mathrm{2}}\:−\:{x}} } \\ $$$${g}\left(\frac{\mathrm{1}}{\mathrm{2017}}\right)\:+\:{g}\left(\frac{\mathrm{2}}{\mathrm{2017}}\right)\:+\:{g}\left(\frac{\mathrm{3}}{\mathrm{2017}}\right)\:+\:\ldots\:+\:{g}\left(\frac{\mathrm{2016}}{\mathrm{2017}}\right)\:\:=\:\:? \\ $$ Answered by Ar Brandon last updated on 25/Oct/21 $$\mathrm{g}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{1}+\mathrm{3}^{\frac{\mathrm{1}}{\mathrm{2}}−{x}} }=\frac{\mathrm{3}^{{x}}…
Question Number 157599 by naka3546 last updated on 25/Oct/21 $${Find}\:\:{the}\:\:{number}\:\:{of}\:\:{x}\:\in\:\left[\mathrm{1},\:\mathrm{2016}\:\right]\:\:,\:\:{x}\:\in\:\mathbb{N} \\ $$$${which}\:\:{making}\:\:{the}\:\:{expression}\:\:\mathrm{4}{x}^{\mathrm{6}} \:+\:\:{x}^{\mathrm{3}} \:+\:\mathrm{5}\:\:\:{is}\:\:{divided}\:\:\:{by}\:\:\mathrm{11}\:. \\ $$ Answered by TheSupreme last updated on 25/Oct/21 $$\mathrm{4}{x}^{\mathrm{6}} +{x}^{\mathrm{3}}…
Question Number 157598 by naka3546 last updated on 25/Oct/21 $${Given}\:\:{a},{b},{c}\:\:{nonnegative}\:\:{numbers}\:\:{which}\:\:{satisfy}\:\:\:{a}+{b}+{c}\:=\:\mathrm{3}. \\ $$$${Prove}\:\:{that}\:\: \\ $$$$\frac{\mathrm{1}}{\mathrm{2}{ab}^{\mathrm{2}} \:+\:\mathrm{1}}\:+\:\frac{\mathrm{1}}{\mathrm{2}{bc}^{\mathrm{2}} +\mathrm{1}}\:+\:\frac{\mathrm{1}}{\mathrm{2}{ac}^{\mathrm{2}} \:+\:\mathrm{1}}\:\geqslant\:\mathrm{1}\:. \\ $$ Answered by ghimisi last updated on…
Question Number 157584 by MathsFan last updated on 24/Oct/21 $${suppose}\: \\ $$$${the}\:{ratio}\:{of}\:{Jim}\:{to}\:{Rohn}\:{is}\:\mathrm{2}:\mathrm{1} \\ $$$$\:{and}\:{the}\:{ratio}\:{of}\:{Rohn}\:{to}\:{Bill}\:{is} \\ $$$$\:\mathrm{3}:\mathrm{4},\:{how}\:{do}\:{i}\:{find}\:{for}\:{the}\:{ratio} \\ $$$${of}\:{Jim}\:{to}\:{Bill}…..??? \\ $$ Answered by peter frank last…
Question Number 92036 by ar247 last updated on 04/May/20 $$\mathrm{2}^{\mathrm{3}^{\mathrm{2}} } =? \\ $$$${A}.\:\mathrm{64} \\ $$$${B}.\:\mathrm{512} \\ $$ Commented by I want to learn more…