Question Number 156754 by abdurehime last updated on 15/Oct/21 Answered by MathsFan last updated on 15/Oct/21 $$\sqrt{\mathrm{5}+\mathrm{2}\sqrt{\mathrm{6}}}=\sqrt{\mathrm{5}+\sqrt{\mathrm{24}}}=\sqrt{\frac{\mathrm{5}+\sqrt{\mathrm{1}}}{\mathrm{2}}}+\sqrt{\frac{\mathrm{5}−\sqrt{\mathrm{1}}}{\mathrm{2}}}=\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}} \\ $$$$\:\:\sqrt{\mathrm{5}−\mathrm{2}\sqrt{\mathrm{6}}}=\sqrt{\frac{\mathrm{5}+\sqrt{\mathrm{1}}}{\mathrm{2}}}−\sqrt{\frac{\mathrm{5}−\sqrt{\mathrm{1}}}{\mathrm{2}}}=\sqrt{\mathrm{3}}−\sqrt{\mathrm{2}} \\ $$$$\:{i}.\:\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}}−\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}}=\:\:\mathrm{2}\sqrt{\mathrm{2}} \\ $$$$ \\ $$$$\boldsymbol{{ii}}.…
Question Number 156744 by joki last updated on 15/Oct/21 $$\mathrm{y}“+\mathrm{y}'=\mathrm{e}^{\mathrm{x}} +\mathrm{3x} \\ $$$$ \\ $$ Answered by qaz last updated on 15/Oct/21 $$\mathrm{y}_{\mathrm{p}} =\frac{\mathrm{1}}{\mathrm{D}^{\mathrm{2}} +\mathrm{D}}\left(\mathrm{e}^{\mathrm{x}}…
Question Number 25675 by naka3546 last updated on 12/Dec/17 Commented by moxhix last updated on 12/Dec/17 $$… \\ $$$$\mathrm{444}\left(\mathrm{2}{n}+\mathrm{887}\right)={k}^{\mathrm{2}} \\ $$$$\mathrm{444}=\mathrm{2}^{\mathrm{2}} ×\mathrm{3}×\mathrm{37} \\ $$$${let}\:{k}=\mathrm{2}×\mathrm{3}×\mathrm{37}×{u}=\mathrm{222}{u}\:{u}\in\mathbb{N} \\…
Question Number 25667 by adityapratap2585@gmail.com last updated on 12/Dec/17 $$\mathrm{Deepak}\:\mathrm{srarts}\:\mathrm{a}\:\mathrm{work}\:\mathrm{and}\:\mathrm{work}\:\mathrm{for}\:\mathrm{12} \\ $$$$\mathrm{days}\:\mathrm{and}\:\mathrm{find}\:\mathrm{he}\:\mathrm{has}\:\mathrm{ompleted}\:\mathrm{10\%}\: \\ $$$$\mathrm{less}\:\mathrm{work}\:\mathrm{which}\:\mathrm{he}\:\mathrm{had}\:\mathrm{to}\:\mathrm{finish}\:\mathrm{in}\: \\ $$$$\mathrm{order}\:\mathrm{to}\:\mathrm{complete}\:\mathrm{the}\:\mathrm{work}\:\mathrm{in}\:\mathrm{24}\:\mathrm{days}\bar {,} \\ $$$$\mathrm{so}\:\mathrm{he}\:\mathrm{ask}\:\mathrm{Rahman}\:\mathrm{to}\:\mathrm{join}\:\mathrm{him}\:\mathrm{to}\:\mathrm{finish} \\ $$$$\mathrm{the}\:\mathrm{work}\:\mathrm{on}\:\mathrm{time}\:.\:\mathrm{If}\:\mathrm{Rahman}\:\mathrm{work}\: \\ $$$$\mathrm{half}\:\mathrm{day}\:\mathrm{only}\:\mathrm{for}\:\mathrm{the}\:\mathrm{remaining}\:\mathrm{days}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{efficiency}\:\mathrm{of}\:\mathrm{Rahman}\:\mathrm{is}\:\mathrm{what}…
Question Number 156727 by SANOGO last updated on 14/Oct/21 Answered by TheHoneyCat last updated on 16/Oct/21 $$\left.\mathrm{A}\right)\:\mathrm{Le}\:\mathrm{plan}\:\left(\mathrm{O},\overset{\rightarrow} {{i}},\overset{\rightarrow} {{i}}\wedge\overset{\rightarrow} {{j}}\right)\:\mathrm{est}\:\mathrm{un}\:\mathrm{plan}\:\mathrm{d}'\mathrm{antisymetrie} \\ $$$$\:\:\:\:\:\:\:\mathrm{de}\:\mathrm{la}\:\mathrm{distribution}\:\mathrm{de}\:\mathrm{charge}. \\ $$$$\:\:\:\:\:\:\:\mathrm{Donc}\:\overset{\rightarrow} {\mathrm{E}}\:\mathrm{est}\:\mathrm{selon}\:\overset{\rightarrow}…
Question Number 91176 by Tinku Tara last updated on 28/Apr/20 $$\mathrm{My}\:\mathrm{Post}\:\mathrm{Filter}\:\mathrm{Issue} \\ $$$$\mathrm{Dear}\:\mathrm{Mr}\:\mathrm{W},\:\mathrm{can}\:\mathrm{you}\:\mathrm{send}\:\mathrm{a}\:\mathrm{few}\:\mathrm{screenshots} \\ $$$$\mathrm{on}\:\mathrm{what}\:\mathrm{is}\:\mathrm{seen}\:\mathrm{when}\:\mathrm{using}\:\mathrm{filter} \\ $$$$\mathrm{myposts}.\:\mathrm{Thank}\:\mathrm{You} \\ $$ Commented by mr W last updated…
Question Number 156709 by aliyn last updated on 14/Oct/21 $$\boldsymbol{{solve}}\:\sqrt[{\frac{\mathrm{1}}{\boldsymbol{{x}}}}]{\boldsymbol{{x}}^{\mathrm{3}} }\:=\:\mathrm{27} \\ $$ Answered by mr W last updated on 14/Oct/21 $$\sqrt[{\frac{\mathrm{1}}{{x}}}]{{x}^{\mathrm{3}} }=\left({x}^{\mathrm{3}} \right)^{{x}} =\left({x}^{{x}}…
Question Number 156691 by mathocean1 last updated on 14/Oct/21 $${Show}\:{that} \\ $$$$\left(\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{x}_{{k}} {y}_{{k}} \right)^{\mathrm{2}} \leqslant\left(\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{x}_{{k}} ^{\mathrm{2}} \right)×\left(\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{y}_{{k}} ^{\mathrm{2}} \right){t}…
Question Number 156677 by saly last updated on 14/Oct/21 Commented by cortano last updated on 14/Oct/21 $$\:\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\sqrt[{\mathrm{n}}]{\mathrm{a}}+\sqrt[{\mathrm{n}}]{\mathrm{b}}}{\mathrm{2}}\right)^{\mathrm{n}} ? \\ $$ Commented by saly last…
Question Number 25600 by Mcfaithal last updated on 11/Dec/17 $$\mathrm{A}\:\mathrm{block}\:\mathrm{pulled}\:\mathrm{along}\:\mathrm{a}\:\mathrm{horizontal}\:\mathrm{floo} \\ $$$$\mathrm{by}\:\mathrm{a}\:\mathrm{horizontal}\:\mathrm{rope}. \\ $$$$\mathrm{The}\:\mathrm{tension}\:\mathrm{in}\:\mathrm{the}\:\mathrm{rope}\:\mathrm{is}\:\mathrm{500N}\:\mathrm{and}\:\mathrm{the} \\ $$$$\mathrm{blocks}\:\mathrm{moves}\:\mathrm{at}\:\mathrm{a}\:\mathrm{constant}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{2}.\mathrm{75ms}^{−\mathrm{1}.} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{work}\:\mathrm{done}\:\mathrm{by}\:\mathrm{the}\:\mathrm{tension}\:\mathrm{in}\:\mathrm{40s} \\ $$$$\mathrm{and}\:\mathrm{also}\:\mathrm{find}\:\mathrm{the}\:\mathrm{power}\:\mathrm{applied}\:\mathrm{by}\:\mathrm{the}\:\mathrm{tension}. \\ $$$$\mathrm{GUYS}\:\mathrm{PLS}\:\mathrm{HELP} \\ $$ Answered…