Question Number 156663 by KONE last updated on 13/Oct/21 $${calcul}\:\int_{\mathrm{0}} ^{\mathrm{10}} {e}^{{x}−{E}\left({x}\right)} {dx}\:\left({E}\:{la}\:{partie}\:{entiere}\right) \\ $$$${besoin}\:{d}'{aide} \\ $$ Commented by benhamimed last updated on 14/Oct/21 $$=\underset{\mathrm{0}}…
Question Number 156636 by SANOGO last updated on 13/Oct/21 Answered by TheSupreme last updated on 13/Oct/21 $${R}_{{eq}} ={R}+\frac{{R}_{\mathrm{1}} {R}_{\mathrm{2}} }{{R}_{\mathrm{1}} +{R}_{\mathrm{2}} } \\ $$$${I}=\:\frac{{E}}{{R}_{{eq}} }…
Question Number 91093 by jagoll last updated on 28/Apr/20 $${dear}\:{admint}\: \\ $$$${Tinkutara}.\:{why}\:{my}\:{phone} \\ $$$${nothing}\:{have}\:{notification}\:{sir}? \\ $$$$ \\ $$ Commented by mr W last updated on…
Question Number 91068 by Maclaurin Stickker last updated on 27/Apr/20 $${Find}\:{the}\:{sum} \\ $$$$\sqrt{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }}+\sqrt{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{4}^{\mathrm{2}} }}+…+\sqrt{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{999}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{1000}^{\mathrm{2}} }} \\ $$ Answered by mr W…
Question Number 156600 by ZiYangLee last updated on 13/Oct/21 $$\int\:\frac{{e}^{{x}} }{{e}^{\mathrm{2}{x}} +\mathrm{4}}\:{dx}\:=?\: \\ $$ Answered by gsk2684 last updated on 13/Oct/21 $${put}\:{e}^{{x}} ={t} \\ $$$${e}^{{x}}…
Question Number 156595 by otchereabdullai@gmail.com last updated on 13/Oct/21 $$\mathrm{Mary}\:\mathrm{walks}\:\mathrm{9}\:\mathrm{city}\:\mathrm{blocks}\:\mathrm{south}, \\ $$$$\mathrm{2}\:\mathrm{blocks}\:\mathrm{east},\:\mathrm{3}\:\mathrm{blocks}\:\mathrm{south}\:\mathrm{and}\: \\ $$$$\mathrm{7}\:\mathrm{blocks}\:\mathrm{east}.\:\mathrm{if}\:\mathrm{all}\:\mathrm{blocks}\:\mathrm{are}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{length}.\:\mathrm{How}\:\mathrm{far}\:\mathrm{is}\:\mathrm{she}\:\mathrm{from}\:\mathrm{her}\:\mathrm{starting} \\ $$$$\mathrm{point}. \\ $$$$ \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{with}\:\mathrm{the}\:\mathrm{aid}\:\mathrm{of}\:\mathrm{a}\:\mathrm{diagram} \\ $$ Commented…
Question Number 156590 by naka3546 last updated on 12/Oct/21 Answered by puissant last updated on 13/Oct/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:{f}\left({x}\right)=\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{{x}^{\mathrm{2}} +{x}−\mathrm{1}}{{x}^{\mathrm{2}} −{x}+\mathrm{1}}=\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{{x}^{\mathrm{2}} }{{x}^{\mathrm{2}} }=\mathrm{1} \\…
Question Number 156571 by otchereabdullai@gmail.com last updated on 12/Oct/21 Answered by puissant last updated on 12/Oct/21 $$\mathscr{A}\:\:=\:\mathrm{100}−\left(\mathrm{30}+\mathrm{35}+\mathrm{6}\right)=\mathrm{100}−\mathrm{71} \\ $$$$\Rightarrow\:\mathscr{A}\:=\:\mathrm{29}\:{cm}^{\mathrm{2}} .. \\ $$ Commented by otchereabdullai@gmail.com…
Question Number 25477 by Mcfaithal last updated on 11/Dec/17 $$\frac{\mathrm{1}+{x}}{\mathrm{2}}={x}−\mathrm{3}+\frac{\mathrm{5}}{{x}} \\ $$$${LCM}=\left(\:\mathrm{2}\right)\left({x}\right) \\ $$$${multiply}\:{each}\:{step}\:{by}\:\mathrm{2}{x} \\ $$$$ \\ $$$$\left(\mathrm{2}\right)\left({x}\right)\left(\frac{\mathrm{1}+{x}}{\mathrm{2}}\right)=\left(\mathrm{2}\right)\left({x}\right)\left({x}−\mathrm{3}\right)+\left(\mathrm{2}\right)\left({x}\right)\left(\frac{\mathrm{5}}{{x}}\right) \\ $$$$ \\ $$$$\left({x}\right)\left(\mathrm{1}+{x}\right)=\mathrm{2}{x}\left({x}−\mathrm{3}\right)+\left(\mathrm{2}\right)\left(\mathrm{5}\right)\:\:\:\:\:\:\:\:\:\:\: \\ $$$${x}+{x}^{\mathrm{2}} =\mathrm{2}{x}^{\mathrm{2}}…
Question Number 91011 by talminator2856791 last updated on 27/Apr/20 $$\:\mathrm{how}\:\mathrm{to}\:\mathrm{make}\:\mathrm{the}\:\mathrm{sigma}\:\mathrm{and}\:\mathrm{prod}\:\mathrm{sign}\:\mathrm{bigger}? \\ $$ Answered by $@ty@m123 last updated on 27/Apr/20 $${No}\:{need}\:{to}\:{make}\:{bigger}. \\ $$$${Uniform}\:{size}\:{will}\:{make}\:{sense}. \\ $$$${Dont}\:{worry}.\:{Post}\:{your}\:{question}. \\…