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Question-156047

Question Number 156047 by otchereabdullai@gmail.com last updated on 07/Oct/21 Commented by otchereabdullai@gmail.com last updated on 07/Oct/21 $$\mathrm{Prof}\:\mathrm{please}\:\mathrm{look}\:\mathrm{at}\:\mathrm{this}\:\mathrm{one}\:\mathrm{too}\:\mathrm{for}\:\mathrm{me} \\ $$ Commented by mr W last updated…

if-x-0-x-1-1-and-x-n-1-1996x-n-1997x-n-1-for-n-2-Find-the-remainder-of-the-division-of-x-1996-by-3-

Question Number 90485 by Maclaurin Stickker last updated on 23/Apr/20 $${if}\:{x}_{\mathrm{0}} ={x}_{\mathrm{1}} =\mathrm{1}\:{and}\:{x}_{{n}+\mathrm{1}} =\mathrm{1996}{x}_{{n}} +\mathrm{1997}{x}_{{n}−\mathrm{1}} \\ $$$${for}\:{n}\geqslant\mathrm{2}.\:{Find}\:{the}\:{remainder}\:{of} \\ $$$${the}\:{division}\:{of}\:{x}_{\mathrm{1996}} \:{by}\:\mathrm{3} \\ $$ Commented by Maclaurin…

Question-24937

Question Number 24937 by kosarrr last updated on 29/Nov/17 Commented by behi.8.3.4.17@gmail.com last updated on 29/Nov/17 $$\mathrm{2}^{\mathrm{k}+\mathrm{1}} =\mathrm{3}×\mathrm{2}^{\mathrm{k}−\mathrm{1}} +\mathrm{16} \\ $$$$\mathrm{2}×\mathrm{2}^{\mathrm{k}} =\frac{\mathrm{3}}{\mathrm{2}}×\mathrm{2}^{\mathrm{k}} +\mathrm{16} \\ $$$$\mathrm{4}×\mathrm{2}^{\mathrm{k}}…

Question-90465

Question Number 90465 by Hassen_Timol last updated on 23/Apr/20 Commented by Hassen_Timol last updated on 23/Apr/20 $$\mathrm{Proof}\:\mathrm{for}\:\mathrm{the}\:\mathrm{last}\:\mathrm{line} \\ $$$$\mathrm{Please}…\:\mathrm{its}\:\mathrm{quite}\:\mathrm{urgent},\:\mathrm{please}… \\ $$ Commented by abdomathmax last…

the-range-of-y-x-is-0-if-x-0-or-just-0-

Question Number 90457 by M±th+et£s last updated on 23/Apr/20 $${the}\:{range}\:{of}\:{y}=\sqrt{{x}}\:\:{is}\left[\mathrm{0},+\infty\right)\:{if}\:{x}\geqslant\mathrm{0} \\ $$$${or}\:{just}\:\left[\mathrm{0},+\infty\right)\:? \\ $$ Commented by MJS last updated on 24/Apr/20 $$\mathrm{talking}\:\mathrm{of}\:“\mathrm{definition}''\:\mathrm{and}\:“\mathrm{range}''\:\mathrm{makes} \\ $$$$\mathrm{no}\:\mathrm{sense}\:\mathrm{for}\:{x}\notin\mathbb{R}\:\mathrm{usually}. \\…