Question Number 155710 by SANOGO last updated on 03/Oct/21 $$\mathrm{li}\underset{{x}−{oo}} {\mathrm{m}}\:\:\:\frac{\mathrm{1}}{{n}\sqrt{{n}}}\:\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{E}\left(\sqrt{\left.{k}\right)}\right. \\ $$$$ \\ $$ Commented by yeti123 last updated on 03/Oct/21 $$\underset{\boldsymbol{{x}}\rightarrow\infty}…
Question Number 24643 by mondodotto@gmail.com last updated on 23/Nov/17 Answered by $@ty@m last updated on 23/Nov/17 $${Let}\:{x}=\mathrm{3}×{y} \\ $$$$\mathrm{3}×\mathrm{2}×\mathrm{3}×\mathrm{4}×{y}=\mathrm{360} \\ $$$$\Rightarrow{y}=\mathrm{5} \\ $$$$\Rightarrow{x}=\mathrm{15} \\ $$$$…
Question Number 90148 by naka3546 last updated on 21/Apr/20 Commented by naka3546 last updated on 21/Apr/20 $${Find}\:\:\:\alpha\:\:\:\:{without}\:\:{trigonometry}\:. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 155677 by vvvv last updated on 03/Oct/21 Commented by vvvv last updated on 03/Oct/21 $${find}:\:\:\boldsymbol{{x}}=?\:\:\:\boldsymbol{{y}}=? \\ $$ Answered by ghimisi last updated on…
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Question Number 155643 by zen17 last updated on 03/Oct/21 Commented by yeti123 last updated on 03/Oct/21 $${s}\:=\:\frac{\mathrm{1}}{\mathrm{6}}{t}^{\mathrm{4}} \:−\:\frac{\mathrm{7}}{\mathrm{6}}{t}^{\mathrm{3}} \:−\:\mathrm{7}{t}^{\mathrm{2}} \:+\:\frac{\mathrm{1}}{\mathrm{2}}{t}\:+\:\mathrm{1} \\ $$$${v}\:=\:\frac{{ds}}{{dt}}\:=\:\frac{\mathrm{4}}{\mathrm{6}}{t}^{\mathrm{3}} \:−\:\frac{\mathrm{21}}{\mathrm{6}}{t}^{\mathrm{2}} \:−\:\mathrm{14}{t}\:+\:\frac{\mathrm{1}}{\mathrm{2}} \\…
Question Number 90100 by ar247 last updated on 21/Apr/20 Answered by john santu last updated on 21/Apr/20 $${let}\:{w}\:=\:\underset{{y}\:=\:\mathrm{2}} {\overset{\mathrm{2020}} {\prod}}\:\frac{\left({y}−\mathrm{1}\right)\left({y}+\mathrm{1}\right)}{{y}^{\mathrm{2}} } \\ $$$${w}\:=\:\left(\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{3}}{\mathrm{2}}\right)\left(\frac{\mathrm{2}}{\mathrm{3}}×\frac{\mathrm{4}}{\mathrm{3}}\right)\left(\frac{\mathrm{3}}{\mathrm{4}}×\frac{\mathrm{5}}{\mathrm{4}}\right)×…× \\ $$$$\left(\frac{\mathrm{2018}}{\mathrm{2019}}×\frac{\mathrm{2020}}{\mathrm{2019}}\right)\left(\frac{\mathrm{2019}}{\mathrm{2020}}×\frac{\mathrm{2021}}{\mathrm{2020}}\right)…
Question Number 155630 by SANOGO last updated on 03/Oct/21 Answered by Ar Brandon last updated on 03/Oct/21 $$\mathscr{L}=\underset{{n}\rightarrow\infty} {\mathrm{lim}}{n}\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{exp}\left(−\frac{{n}}{{k}}\right)}{{k}^{\mathrm{2}} }=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{1}}{{n}}\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{n}^{\mathrm{2}}…
Question Number 155604 by SANOGO last updated on 02/Oct/21 Answered by Kamel last updated on 02/Oct/21 $$ \\ $$$$\forall{x}\geqslant\mathrm{0}\:\:{x}−\frac{{x}^{\mathrm{3}} }{\mathrm{6}}\leqslant{sin}\left({x}\right)\leqslant{x} \\ $$$$\:\:\:\therefore\:\:\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{{n}+{k}}−\frac{\mathrm{1}}{\mathrm{6}}\underset{{k}=\mathrm{1}} {\overset{{n}}…
Question Number 24524 by mondodotto@gmail.com last updated on 20/Nov/17 Answered by mrW1 last updated on 20/Nov/17 $${x}\geqslant\mathrm{0} \\ $$$$\mathrm{2}\left({x}+\mathrm{1}\right)\mathrm{log}\:\mathrm{9}={x}^{\frac{\mathrm{1}}{\mathrm{2}}} \\ $$$$\left(\mathrm{2log}\:\mathrm{9}\right)^{\mathrm{2}} \left({x}+\mathrm{1}\right)^{\mathrm{2}} ={x} \\ $$$$\left(\mathrm{2log}\:\mathrm{9}\right)^{\mathrm{2}}…