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Question-154552

Question Number 154552 by 0731619 last updated on 19/Sep/21 Commented by Rasheed.Sindhi last updated on 20/Sep/21 $$\bullet\mathrm{Is}\:\mathrm{there}\:\mathrm{any}\:\mathrm{compitition}\:\mathrm{to}\:\mathrm{make} \\ $$$$\boldsymbol{\mathrm{posts}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{others}}\:'\mathrm{red}-\mathrm{flaged}'\:? \\ $$$$\heartsuit\mathrm{Is}\:\mathrm{there}\:\mathrm{any}\:\mathrm{compitition}\:\mathrm{of}\:'\mathrm{likes}' \\ $$$$\:\:\:\mathrm{of}\:\mathrm{somebodies}\:\mathrm{to}\:\boldsymbol{\mathrm{their}}\:\boldsymbol{\mathrm{own}}\:\boldsymbol{\mathrm{posts}}? \\ $$$$\blacklozenge\:\mathrm{Is}\:\mathrm{this}\:\mathrm{a}\:\boldsymbol{\mathrm{market}}\:\boldsymbol{\mathrm{place}}?…

Question-154542

Question Number 154542 by SANOGO last updated on 19/Sep/21 Answered by qaz last updated on 19/Sep/21 $$\mathrm{Let}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{ax}+\mathrm{b} \\ $$$$\mathrm{ax}^{\mathrm{2}} +\mathrm{bx}=\mathrm{x}^{\mathrm{2}} +\mathrm{a}\int_{\mathrm{0}} ^{\mathrm{x}} \left(\mathrm{x}−\mathrm{t}\right)\mathrm{dt}=\mathrm{x}^{\mathrm{2}} +\mathrm{a}\left(\mathrm{xt}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{t}^{\mathrm{2}} \right)_{\mathrm{0}}…

Question-89007

Question Number 89007 by naka3546 last updated on 14/Apr/20 Answered by TANMAY PANACEA. last updated on 14/Apr/20 $$\frac{{a}^{\mathrm{2}} }{{b}+{c}+{d}}+{a} \\ $$$$\frac{{a}^{\mathrm{2}} +{ab}+{ac}+{ad}}{{b}+{c}+{d}} \\ $$$$\frac{{a}\left({a}+{b}+{c}+{d}\right)}{{b}+{c}+{d}} \\…

Question-154514

Question Number 154514 by 0731619 last updated on 19/Sep/21 Commented by mr W last updated on 19/Sep/21 $${there}\:{is}\:{not}\:{much}\:{to}\:{solve}!\:{it}'{s}\:{a}\: \\ $$$${matter}\:{of}\:{definition}. \\ $$$$\begin{pmatrix}{\mathrm{2}{n}}\\{{n}}\end{pmatrix}=\frac{\left(\mathrm{2}{n}\right)!}{\left({n}!\right)^{\mathrm{2}} } \\ $$…

a-b-c-gt-0-a-3-b-3-c-3-a-b-b-c-c-a-3-8-

Question Number 23425 by Bruce Lee last updated on 30/Oct/17 $$\boldsymbol{{a}},\boldsymbol{{b}},\boldsymbol{{c}}>\mathrm{0}\:\Rightarrow\frac{\boldsymbol{{a}}^{\mathrm{3}} +\boldsymbol{{b}}^{\mathrm{3}} +\boldsymbol{{c}}^{\mathrm{3}} }{\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right)\left(\boldsymbol{{b}}+\boldsymbol{{c}}\right)\left(\boldsymbol{{c}}+\boldsymbol{{a}}\right)}\geqslant\frac{\mathrm{3}}{\mathrm{8}}\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-23419

Question Number 23419 by mondodotto@gmail.com last updated on 30/Oct/17 Answered by $@ty@m last updated on 31/Oct/17 $${Solution}\:\left({a}\right) \\ $$$${LHS}=\mathrm{cos}\:{A}+\mathrm{cos}\:{B}+\mathrm{cos}\:{C} \\ $$$$=\mathrm{2cos}\:\frac{{A}+{B}}{\mathrm{2}}\mathrm{cos}\:\frac{{A}−{B}}{\mathrm{2}}+\mathrm{cos}\:{C} \\ $$$$=\mathrm{2cos}\:\frac{\pi−{C}}{\mathrm{2}}\mathrm{cos}\:\frac{{A}−{B}}{\mathrm{2}}+\mathrm{cos}\:{C} \\ $$$$=\mathrm{2sin}\:\frac{{C}}{\mathrm{2}}\mathrm{cos}\:\frac{{A}−{B}}{\mathrm{2}}−\mathrm{2sin}\:^{\mathrm{2}}…

Question-23411

Question Number 23411 by ajfour last updated on 29/Oct/17 Commented by ajfour last updated on 29/Oct/17 $${Place}\:\mathrm{8}\:{queens}\:{on}\:{the}\:{chessboard} \\ $$$${so}\:{that}\:{there}\:{be}\:{no}\:{threat}\:\left({none}\right. \\ $$$$\left.{come}\:{in}\:{each}\:{other}'{s}\:{way}\right). \\ $$$$ \\ $$…