Question Number 24184 by FilupES last updated on 14/Nov/17 Commented by FilupES last updated on 14/Nov/17 $$\mathrm{I}\:\mathrm{will}\:\mathrm{upload}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{to}\:\mathrm{my}\:\mathrm{challange}\:\mathrm{later}, \\ $$$$\mathrm{or}\:\mathrm{if}\:\mathrm{requested}! \\ $$ Commented by FilupES last…
Question Number 24178 by NECx last updated on 13/Nov/17 $${A}\:{block}\:{is}\:{released}\:{from}\:{rest}\:{at}\:{the} \\ $$$${top}\:{of}\:{a}\:{frictionless}\:{incline} \\ $$$${plane}\:\mathrm{16}.\mathrm{00}{m}\:{long}.{It}\:{reaches}\:{the} \\ $$$${bottom}\:\mathrm{4}.\mathrm{0}{s}\:{later}.{A}\:{second}\:{block} \\ $$$${is}\:{projected}\:{up}\:{the}\:{plane}\:{from}\:{the} \\ $$$${bottom}\:{at}\:{the}\:{instant}\:{the}\:{first}\:{one} \\ $$$${is}\:{released}\:{in}\:{such}\:{a}\:{way}\:{that}\:{it} \\ $$$${returns}\:{to}\:{the}\:{bottom}\:{simultaneously} \\…
Question Number 24177 by NECx last updated on 13/Nov/17 $${A}\:{lorry}\:{goes}\:{round}\:{an}\:{unbanked} \\ $$$${curve}.{If}\:{the}\:{radius}\:{of}\:{the}\:{curve} \\ $$$${is}\:\mathrm{30}{m}\:{and}\:{the}\:{coefficient}\:{of} \\ $$$${friction}\:{between}\:{the}\:{ground}\:{and} \\ $$$${the}\:{tyre}\:{is}\:\mathrm{0}.\mathrm{6}.\:{Calculate}\:{the} \\ $$$${maximum}\:{speed}\:{of}\:{the}\:{lorry}. \\ $$$$\left({g}=\mathrm{10}{m}/{s}^{\mathrm{2}} \right) \\ $$$$…
Question Number 24175 by NECx last updated on 13/Nov/17 $${A}\:{cyclist}\:{goes}\:{round}\:{a}\:{circular} \\ $$$${track}\:{of}\:{radius}\:\mathrm{70}{m}.{The}\:{total}\:{mass} \\ $$$${of}\:{bicycle}\:{and}\:{rider}\:{is}\:\mathrm{70}{kg}.{Calculate} \\ $$$${the}\:{frictional}\:{force}\:{which}\:{will} \\ $$$${ensure}\:{that}\:{the}\:{rider}\:{successfully} \\ $$$${negotiates}\:{the}\:{track}\:{with}\:{a}\:{speed} \\ $$$${of}\:\mathrm{25}{m}/{s}.{What}\:{happens}\:{to}\:{the} \\ $$$${rider}\:{if}\:\mu=\mathrm{0}.\mathrm{3}? \\…
Question Number 155243 by aliyn last updated on 27/Sep/21 $$\boldsymbol{{the}}\:\boldsymbol{{value}}\:\boldsymbol{{of}}\:\boldsymbol{{the}}\:\boldsymbol{{integral}}\:\int_{−\mathrm{1}} ^{\:\mathrm{1}} \:\boldsymbol{{x}}^{\mathrm{2}} \:\boldsymbol{{p}}_{\mathrm{2}} \left(\boldsymbol{{x}}\right)\:\boldsymbol{{dx}}\:\:\:\boldsymbol{{is}}\:?\: \\ $$ Commented by aliyn last updated on 28/Sep/21 $$???\: \\…
Question Number 155242 by aliyn last updated on 27/Sep/21 $$\boldsymbol{{the}}\:\boldsymbol{{value}}\:\boldsymbol{{of}}\:\:\boldsymbol{\beta}\:\left(\mathrm{2},\:{n}\:\right)\:\boldsymbol{{is}}\:? \\ $$ Commented by tabata last updated on 27/Sep/21 $$=\:\frac{\Gamma\mathrm{2}\:\Gamma\left({n}\right)}{\Gamma\left({n}+\mathrm{2}\right)}\:=\:\frac{\left({n}−\mathrm{1}\right)!}{\left({n}+\mathrm{1}\right)!}\:=\:\frac{\left({n}−\mathrm{1}\right)!}{{n}\:\left({n}+\mathrm{1}\right)\left({n}−\mathrm{1}\right)!}\:=\:\frac{\mathrm{1}}{{n}\:\left({n}+\mathrm{1}\right)} \\ $$ Answered by puissant…
Question Number 89698 by M±th+et£s last updated on 18/Apr/20 $${hi}\:{everyone} \\ $$$${what}\:{is}\:{the}\:{definition}\:{of}\:{the}\:{tangent} \\ $$$${straight}\:{line}\:{to}\:{the}\:{curve}\:{without}\:{relying} \\ $$$${to}\:\:{the}\:{derivitve}\: \\ $$$${because}\:{the}\:{derivative}\:{is}\:{the}\:{slope} \\ $$$${and}\:{thanx}\:{for}\:{all} \\ $$ Commented by mr…
Question Number 155225 by aliyn last updated on 27/Sep/21 Commented by aliyn last updated on 27/Sep/21 $${how}\:{can}\:{it}\:{solve}\:{this}\:{proplem}\:? \\ $$ Commented by bemath last updated on…
Question Number 155215 by 0731619 last updated on 27/Sep/21 Answered by MJS_new last updated on 27/Sep/21 $${x}=\frac{\mathrm{1}}{\mathrm{2}}\wedge{y}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$ Commented by 0731619 last updated on…
Question Number 89668 by Mr.Panoply last updated on 18/Apr/20 $${what}\:{is}\:{the}\:{first}\:{three}\:{smallest}\:{positive}\: \\ $$$${integer}\:{that}\:{leaves}\:{a}\:{reminder}\:{of}\:\mathrm{1}.\:{when} \\ $$$${divided}\:{by}\:\mathrm{3}\:{and}\:\mathrm{5}\:{qnd}\:\mathrm{7}? \\ $$ Commented by mr W last updated on 18/Apr/20 $${lcm}\left(\mathrm{3},\mathrm{5},\mathrm{7}\right)=\mathrm{3}×\mathrm{5}×\mathrm{7}=\mathrm{105}…