Question Number 24057 by NECx last updated on 12/Nov/17 $${A}\:{block}\:{of}\:{ice}\:{slides}\:{down}\:{a}\:\mathrm{45}° \\ $$$${incline}\:{plane}\:{in}\:{twice}\:{the}\:{time}\:{it} \\ $$$${takes}\:{to}\:{slide}\:{down}\:{a}\:\mathrm{45}°\:{frictionless} \\ $$$${incline}\:{plane}.{What}\:{is}\:{the}\:{coefficient} \\ $$$${of}\:{kinetic}\:{friction}\:{between}\:{the} \\ $$$${ice}\:{block}\:{and}\:{the}\:{incline}\:{plqne}. \\ $$ Answered by mrW1…
Question Number 155122 by saly last updated on 25/Sep/21 Commented by benhamimed last updated on 25/Sep/21 $$/{x}−\mathrm{3}/+\mathrm{3}−{x}\neq\mathrm{0} \\ $$$$/{x}−\mathrm{3}/=\begin{cases}{{x}−\mathrm{3}\:\:\:;{x}\geqslant\mathrm{3}}\\{\mathrm{3}−{x}\:\:\:\:;{x}\leqslant\mathrm{3}}\end{cases} \\ $$$$/{x}−\mathrm{3}/+\mathrm{3}−{x}=\begin{cases}{\mathrm{0}\:\:\:;{x}\geqslant\mathrm{3}}\\{\mathrm{6}−\mathrm{2}{x}\:\:\:;{x}\leqslant\mathrm{0}}\end{cases} \\ $$$$\left.{D}=\right]−\infty;\mathrm{3}\left[\right. \\ $$…
Question Number 155101 by SANOGO last updated on 25/Sep/21 $${soit}:\:{y}\:{y}'+{xy}^{\mathrm{2}} +{x}=\mathrm{0}\:,{avec}\:{f}\left(\mathrm{0}\right)=\mathrm{1} \\ $$$${f}''\left(\mathrm{0}\right)=? \\ $$ Commented by tabata last updated on 25/Sep/21 $$\boldsymbol{{yy}}^{'} \:=\:−\boldsymbol{{x}}\:\left(\boldsymbol{{y}}^{\mathrm{2}} \:+\:\mathrm{1}\right)\:\Rightarrow\:\frac{\boldsymbol{{y}}\:}{\boldsymbol{{y}}^{\mathrm{2}}…
Question Number 89534 by mathocean1 last updated on 17/Apr/20 Commented by abdomathmax last updated on 17/Apr/20 $$\left.\mathrm{1}\right)\:{we}\:{have}\:{e}_{\mathrm{1}} \left(\mathrm{2},\mathrm{3}\right)\:\:{e}_{\mathrm{2}} \left(\mathrm{1},\mathrm{2}\right)\:{and}\:{e}_{\mathrm{3}} \left(\mathrm{4},\mathrm{5}\right) \\ $$$${let}\:{find}\:\:{x}\:{and}\:{y}\:/{e}_{\mathrm{3}} ={xe}_{\mathrm{1}} \:+{ye}_{\mathrm{2}} \:\Rightarrow…
Question Number 23996 by klok9917@gmail last updated on 10/Nov/17 $$\mathrm{z}^{−\mathrm{4}_{=\mathrm{1}/\mathrm{3}\left(\mathrm{1}−\sqrt{\left.\mathrm{3i}\right)}\right.} } \\ $$ Answered by FilupES last updated on 11/Nov/17 $${z}^{−\mathrm{4}} =\frac{\mathrm{1}}{\mathrm{3}}\left(\mathrm{1}−\sqrt{\mathrm{3}{i}}\right) \\ $$$${z}^{−\mathrm{4}} =\frac{\mathrm{1}}{\mathrm{3}}\left(\mathrm{1}−\sqrt{\mathrm{3}}×\left(−\mathrm{1}\right)^{\frac{\mathrm{1}}{\mathrm{4}}}…
Question Number 89530 by mathocean1 last updated on 17/Apr/20 $$\mathrm{F}\:\mathrm{which}\:\mathrm{is}\:\:\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{funtions}\:\mathrm{from}\:\mathbb{R}\:\mathrm{to}\:\mathbb{R}\: \\ $$$$\mathrm{is}\:\mathrm{a}\:\mathrm{vectorial}\:\mathrm{space}\:\mathrm{and}\:\mathrm{G}\left(\mathrm{a}\:\mathrm{part}\:\mathrm{of}\:\mathrm{F}\right)\:\mathrm{is} \\ $$$$\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{odd}\:\mathrm{functions}\:\mathrm{such}\:\mathrm{as} \\ $$$$\mathrm{G}=\left\{\:{f}\:\in\:\mathrm{F}/\forall\:\mathrm{x}\in\:\mathbb{R},\:{f}\left({x}\right)=−{f}\left(−{x}\right)\right\} \\ $$$$\left.\mathrm{1}\right)\:{S}\mathrm{how}\:\mathrm{that}\:\mathrm{G}\:\mathrm{is}\:\mathrm{sub}\:\mathrm{vector}\:\mathrm{space}\:\mathrm{of}\:\mathrm{F} \\ $$$$\mathrm{in}\:\mathbb{R}. \\ $$ Commented by arcana…
Question Number 89513 by mr W last updated on 17/Apr/20 $${i}\:{open}\:{this}\:{test}\:{post}\:{to}\:{see}\:{if}\:{i}\:{can} \\ $$$${edit}\:{or}\:{delete}\:{it}\:{later}. \\ $$ Commented by mr W last updated on 17/Apr/20 $${thank}\:{you}\:{sir}! \\…
Question Number 23957 by ANTARES_VY last updated on 10/Nov/17 $$\int\frac{\boldsymbol{\mathrm{sinx}}−\mathrm{2}\boldsymbol{\mathrm{cosx}}}{\mathrm{1}+\mathrm{2}\boldsymbol{\mathrm{sin}}\mathrm{2}\boldsymbol{\mathrm{x}}}\boldsymbol{\mathrm{dx}} \\ $$$$\boldsymbol{\mathrm{solves}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 89482 by mr W last updated on 18/Apr/20 $${URGENT}\:! \\ $$$${to}\:{TINKUTARA}\:{developers}: \\ $$$${because}\:{i}\:{didn}'{t}\:{get}\:{notification},\:{i} \\ $$$${have}\:{updated}\:{the}\:{app}.\:{but}\:{since}\:{the} \\ $$$${update},\:{i}\:{can}'{t}\:{either}\:{edit}\:{my}\:{own} \\ $$$${posts}\:{or}\:{delete}\:{them}. \\ $$$${i}\:{am}\:{using}\:{a}\:{Huawei}\:{P}\mathrm{20},\:{Android}\:\mathrm{9}. \\ $$…
Question Number 155017 by SANOGO last updated on 24/Sep/21 $$\int_{\mathrm{0}} ^{\frac{\mathrm{3}}{\mathrm{2}}} {E}\left({x}^{\mathrm{2}} \right){dx};\:{avec}\:{E}\left({x}\right)\:{la}\:{partie}\:{entiere} \\ $$ Answered by puissant last updated on 24/Sep/21 $${K}=\int_{\mathrm{0}} ^{\frac{\mathrm{3}}{\mathrm{2}}} {E}\left({x}^{\mathrm{2}}…