Question Number 22892 by NECx last updated on 23/Oct/17 $${A}\:{horizontal}\:{force}\:{of}\:\mathrm{10}{N}\:{just} \\ $$$${prevents}\:{a}\:{mass}\:{of}\:\mathrm{2}{kg}\:{from} \\ $$$${sliding}\:{down}\:{a}\:{rough}\:{plane} \\ $$$${inclined}\:{at}\:\mathrm{45}°\:{to}\:{the}\:{horizontal}. \\ $$$${Find}\:{the}\:{coefficient}\:{of}\:{friction}. \\ $$ Commented by ajfour last updated…
Question Number 22881 by Physics lover last updated on 23/Oct/17 $${which}\:{is}\:{your}\:{favourite}\:{subject}? \\ $$ Commented by NECx last updated on 23/Oct/17 $${mine}\:{is}\:{physics}\:{though}\:{i}'{m}\:{not} \\ $$$${too}\:{good}\:{at}\:{it}. \\ $$…
Question Number 153924 by ZiYangLee last updated on 12/Sep/21 $$\int\:\frac{\mathrm{1}+\mathrm{sin}\:{x}}{\mathrm{sin}\:{x}\left(\mathrm{1}+\mathrm{cos}\:{x}\right)}\:{dx}\:=? \\ $$ Answered by ArielVyny last updated on 12/Sep/21 $$\int\frac{\left(\mathrm{1}+{sinx}\right)}{{sinx}\left(\mathrm{1}+{cosx}\right)}{dx}=\int\frac{\mathrm{1}}{{sinx}\left(\mathrm{1}+{cosx}\right)}+\int\frac{\mathrm{1}}{\mathrm{1}+{cosx}}{dx} \\ $$$${t}={tan}\left(\frac{{x}}{\mathrm{2}}\right)\rightarrow{dt}=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{1}+{t}^{\mathrm{2}} \right){dx} \\ $$$${dx}=\frac{\mathrm{2}}{\mathrm{1}+{t}^{\mathrm{2}}…
Question Number 22855 by NECx last updated on 23/Oct/17 $${Equal}\:{forces}\:{act}\:{on}\:{two}\:{bodies} \\ $$$${which}\:{are}\:{initially}\:{at}\:{rest},{for} \\ $$$${equal}\:{times}.{If}\:{the}\:{ratio}\:{of}\:{the}\: \\ $$$${masses}\:{is}\:\mathrm{4}:\mathrm{3},{What}\:{is}\:{the}\:{ratio} \\ $$$${of}\:{the}\:{distance}\:{covered}? \\ $$ Commented by NECx last updated…
Question Number 153918 by joki last updated on 12/Sep/21 $$\mathrm{the}\:\mathrm{base}\:\mathrm{of}\:\mathrm{an}\:\mathrm{object}\:\mathrm{is}\:\mathrm{in}\:\mathrm{the}\:\mathrm{form}\:\mathrm{of}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{with} \\ $$$$\mathrm{radius}\:\mathrm{1}.\:\mathrm{suppose}\:\mathrm{that}\:\mathrm{all}\:\mathrm{section}\:\mathrm{of}\:\mathrm{the}\:\mathrm{object}\:\mathrm{are} \\ $$$$\mathrm{perpendicular}\:\mathrm{to}\:\mathrm{a}\:\mathrm{diameter}\:\mathrm{of}\:\mathrm{a}\:\mathrm{square}.\:\mathrm{determine} \\ $$$$\mathrm{the}\:\mathrm{volume}\:\mathrm{of}\:\mathrm{the}\:\mathrm{object}? \\ $$ Answered by talminator2856791 last updated on 12/Sep/21…
Question Number 153896 by SANOGO last updated on 11/Sep/21 Answered by ARUNG_Brandon_MBU last updated on 12/Sep/21 $$\Omega=\int_{\mathrm{1}} ^{\infty} \frac{\mathrm{ln}{x}}{\left(\mathrm{1}+{x}\right)\left(\mathrm{1}+{x}^{\mathrm{2}} \right)}{dx},\:{x}=\frac{\mathrm{1}}{{u}}\Rightarrow{dx}=−\frac{\mathrm{1}}{{u}^{\mathrm{2}} }{du} \\ $$$$\:\:\:\:=−\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{u}\mathrm{ln}{u}}{\left({u}+\mathrm{1}\right)\left({u}^{\mathrm{2}}…
Question Number 153877 by alisiao last updated on 11/Sep/21 Commented by alisiao last updated on 11/Sep/21 $$\boldsymbol{{prove}}\:\boldsymbol{{that}} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 153860 by SANOGO last updated on 11/Sep/21 Answered by puissant last updated on 11/Sep/21 $${Q}=\int_{\mathrm{0}} ^{\pi} {sin}^{\sqrt{\mathrm{3}}} {x}\:{dx} \\ $$$$=\mathrm{2}\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {sin}^{\sqrt{\mathrm{3}}} {x}\:{dx}…
Question Number 22769 by Bruce Lee last updated on 22/Oct/17 $$\boldsymbol{\mathrm{write}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{geometry}}\:\boldsymbol{\mathrm{form}} \\ $$$$\:\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{4}}{\mathrm{5}}\boldsymbol{\mathrm{i}} \\ $$$$ \\ $$$$\boldsymbol{\mathrm{help}}\:\boldsymbol{\mathrm{plz}}\: \\ $$ Answered by $@ty@m last updated on…