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Question Number 22740 by Sahib singh last updated on 22/Oct/17 $$\mathrm{Which}\:\mathrm{is}\:\mathrm{the}\:\mathrm{best}\:\mathrm{book}\:\mathrm{for} \\ $$$$+\mathrm{1}\:\mathrm{trigonometry}? \\ $$ Commented by math solver last updated on 22/Oct/17 $${NCERT}\:! \\…
Question Number 153800 by AliRaza123 last updated on 10/Sep/21 Answered by nadovic last updated on 10/Sep/21 $$\:\:\mathrm{Speed}\:\:=\:\:\frac{\mathrm{distance}}{\mathrm{time}} \\ $$$$\:\:\mathrm{600}\:\:=\:\:\frac{\mathrm{7200}}{{t}}\: \\ $$$$\:\:\:\:\:\:\:{t}\:\:=\:\:\frac{\mathrm{7200}}{\mathrm{600}}\: \\ $$$$\:\:\:\:\:\:\:{t}\:\:=\:\:\mathrm{12}\:{hours} \\ $$$$\:\:…
Question Number 153803 by weltr last updated on 10/Sep/21 $${solve}\:{for}\:{x} \\ $$$${cos}^{\mathrm{2}} {x}\:−\:{cos}^{\mathrm{2}} \mathrm{2}{x}\:=\:{cos}^{\mathrm{2}} \mathrm{4}{x}\:−\:{cos}^{\mathrm{2}} \mathrm{3}{x} \\ $$ Commented by Ar Brandon last updated on…
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Question Number 153769 by SANOGO last updated on 10/Sep/21 Answered by puissant last updated on 10/Sep/21 $${On}\:{remarque}\:{que}\:{z}=\mathrm{0}\:{est}\:{solution}\:{de}\: \\ $$$${l}'{equation}.\:{supposons}\:{z}\neq\mathrm{0}.\:{En}\:{prenant} \\ $$$${les}\:{modules},\:{on}\:{a}: \\ $$$$\mid{z}\mid^{\mathrm{5}} =\mid\bar {{z}}\mid=\mid{z}\mid\:\Rightarrow\:\mid{z}\mid^{\mathrm{6}}…
Question Number 153760 by ZiYangLee last updated on 10/Sep/21 $$\int\:\mathrm{sin}^{\mathrm{2}} \mathrm{4}{x}\:\mathrm{cos}\:\mathrm{4}{x}\:{dx}= \\ $$ Answered by puissant last updated on 10/Sep/21 $$=\int{sin}^{\mathrm{2}} \mathrm{4}{x}\:{cos}\mathrm{4}{x}\:{dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\int{sin}\mathrm{4}{x}\:{sin}\mathrm{8}{x}\:{dx} \\…
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Question Number 88204 by behi83417@gmail.com last updated on 09/Apr/20 $$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{radi}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{circle}}\left(\boldsymbol{\mathrm{s}}\right)\:\boldsymbol{\mathrm{that}}\:\boldsymbol{\mathrm{tangents}} \\ $$$$\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{corves}}\::\begin{cases}{\boldsymbol{\mathrm{y}}=\boldsymbol{\mathrm{x}}\pm\frac{\mathrm{1}}{\boldsymbol{\mathrm{y}}^{\mathrm{2}} }}\\{\boldsymbol{\mathrm{x}}=\boldsymbol{\mathrm{y}}\pm\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}^{\mathrm{2}} }}\end{cases} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 153736 by ZiYangLee last updated on 09/Sep/21 $$\mathrm{Given}\:\mathrm{that}\:\mathrm{7}\:\mathrm{cos}\:\mathrm{2}\theta+\mathrm{24}\:\mathrm{sin}^{\mathrm{2}} \theta={R}\:\mathrm{cos}\left(\mathrm{2}\theta−\alpha\right), \\ $$$$\mathrm{where}\:{R}>\mathrm{0}\:\mathrm{and}\:\mathrm{0}<\alpha<\frac{\pi}{\mathrm{2}},\:\mathrm{find}\:\mathrm{the}\:\mathrm{maximum} \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{14}\:\mathrm{cos}^{\mathrm{2}} \theta+\mathrm{48}\:\mathrm{sin}\:\theta\:\mathrm{cos}\:\theta. \\ $$ Answered by mr W last updated on…