Question Number 154542 by SANOGO last updated on 19/Sep/21 Answered by qaz last updated on 19/Sep/21 $$\mathrm{Let}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{ax}+\mathrm{b} \\ $$$$\mathrm{ax}^{\mathrm{2}} +\mathrm{bx}=\mathrm{x}^{\mathrm{2}} +\mathrm{a}\int_{\mathrm{0}} ^{\mathrm{x}} \left(\mathrm{x}−\mathrm{t}\right)\mathrm{dt}=\mathrm{x}^{\mathrm{2}} +\mathrm{a}\left(\mathrm{xt}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{t}^{\mathrm{2}} \right)_{\mathrm{0}}…
Question Number 89007 by naka3546 last updated on 14/Apr/20 Answered by TANMAY PANACEA. last updated on 14/Apr/20 $$\frac{{a}^{\mathrm{2}} }{{b}+{c}+{d}}+{a} \\ $$$$\frac{{a}^{\mathrm{2}} +{ab}+{ac}+{ad}}{{b}+{c}+{d}} \\ $$$$\frac{{a}\left({a}+{b}+{c}+{d}\right)}{{b}+{c}+{d}} \\…
Question Number 154514 by 0731619 last updated on 19/Sep/21 Commented by mr W last updated on 19/Sep/21 $${there}\:{is}\:{not}\:{much}\:{to}\:{solve}!\:{it}'{s}\:{a}\: \\ $$$${matter}\:{of}\:{definition}. \\ $$$$\begin{pmatrix}{\mathrm{2}{n}}\\{{n}}\end{pmatrix}=\frac{\left(\mathrm{2}{n}\right)!}{\left({n}!\right)^{\mathrm{2}} } \\ $$…
Question Number 154507 by RB95 last updated on 19/Sep/21 Commented by RB95 last updated on 19/Sep/21 $${Salut} \\ $$$${Aidez}\:−{moi}\:{svp} \\ $$$${urgent} \\ $$$${merci} \\ $$…
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Question Number 23425 by Bruce Lee last updated on 30/Oct/17 $$\boldsymbol{{a}},\boldsymbol{{b}},\boldsymbol{{c}}>\mathrm{0}\:\Rightarrow\frac{\boldsymbol{{a}}^{\mathrm{3}} +\boldsymbol{{b}}^{\mathrm{3}} +\boldsymbol{{c}}^{\mathrm{3}} }{\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right)\left(\boldsymbol{{b}}+\boldsymbol{{c}}\right)\left(\boldsymbol{{c}}+\boldsymbol{{a}}\right)}\geqslant\frac{\mathrm{3}}{\mathrm{8}}\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 23419 by mondodotto@gmail.com last updated on 30/Oct/17 Answered by $@ty@m last updated on 31/Oct/17 $${Solution}\:\left({a}\right) \\ $$$${LHS}=\mathrm{cos}\:{A}+\mathrm{cos}\:{B}+\mathrm{cos}\:{C} \\ $$$$=\mathrm{2cos}\:\frac{{A}+{B}}{\mathrm{2}}\mathrm{cos}\:\frac{{A}−{B}}{\mathrm{2}}+\mathrm{cos}\:{C} \\ $$$$=\mathrm{2cos}\:\frac{\pi−{C}}{\mathrm{2}}\mathrm{cos}\:\frac{{A}−{B}}{\mathrm{2}}+\mathrm{cos}\:{C} \\ $$$$=\mathrm{2sin}\:\frac{{C}}{\mathrm{2}}\mathrm{cos}\:\frac{{A}−{B}}{\mathrm{2}}−\mathrm{2sin}\:^{\mathrm{2}}…
Question Number 23411 by ajfour last updated on 29/Oct/17 Commented by ajfour last updated on 29/Oct/17 $${Place}\:\mathrm{8}\:{queens}\:{on}\:{the}\:{chessboard} \\ $$$${so}\:{that}\:{there}\:{be}\:{no}\:{threat}\:\left({none}\right. \\ $$$$\left.{come}\:{in}\:{each}\:{other}'{s}\:{way}\right). \\ $$$$ \\ $$…
Question Number 154476 by SANOGO last updated on 18/Sep/21 $${soit}:{y}''−\mathrm{3}{y}'−\mathrm{4}{y}=\mathrm{3}{e}^{\mathrm{3}{x}\:} \:{avec}\:, \\ $$$${f}\left({o}\right)=−\frac{\mathrm{1}}{\mathrm{2}}\:{et}\:{f}'\left(\mathrm{0}\right)=\mathrm{4} \\ $$$${alors}\:{f}\left(\mathrm{1}\right)=? \\ $$$$ \\ $$ Answered by ARUNG_Brandon_MBU last updated on…
Question Number 88936 by naka3546 last updated on 14/Apr/20 Answered by ajfour last updated on 14/Apr/20 $${let}\:\:\:{a}=\sqrt{\mathrm{196}−{c}^{\mathrm{2}} }\:\:\:\:{from}\:\mathrm{1}^{{st}} \\ $$$${b}^{\mathrm{2}} =\:\mathrm{2}{c}\sqrt{\mathrm{196}−{c}^{\mathrm{2}} }−\mathrm{27}\:\:\:{from}\:\mathrm{2}^{{nd}} \\ $$$${and}\:\:\:\:{b}^{\mathrm{2}} =\left({c}+\sqrt{\mathrm{225}−{c}^{\mathrm{2}}…