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A-computer-systerm-has-a-memory-leak-issue-causing-its-usage-to-increase-over-time-the-rate-of-memory-usage-growth-is-directly-proportional-to-the-difference-between-the-current-memory

Question Number 202094 by otchereabdullai@gmail.com last updated on 20/Dec/23 $$\:{A}\:{computer}\:{systerm}\:{has}\:{a}\:{memory}\: \\ $$$$\:\:{leak}\:{issue}\:{causing}\:{its}\:{usage}\:{to} \\ $$$$\:\:{increase}\:{over}\:{time}.\:{the}\:{rate}\:{of}\: \\ $$$$\:\:{memory}\:{usage}\:{growth}\:{is}\:{directly}\: \\ $$$$\:\:{proportional}\:{to}\:{the}\:{difference}\: \\ $$$$\:\:{between}\:{the}\:{current}\:{memory}\:{usage}\: \\ $$$$\:{and}\:{the}\:{systerms}\:{maximum}\:{memory} \\ $$$$\:\:{capacity}.\:{Write}\:{one}\:{ODE}\:{and}\:{one}\: \\…

Question-202034

Question Number 202034 by cortano12 last updated on 19/Dec/23 Answered by MM42 last updated on 19/Dec/23 $${if}\:\frac{\mathrm{7}}{\mathrm{3}}<{a}<\frac{\mathrm{7}}{\mathrm{2}}\Rightarrow\lfloor\frac{\mathrm{7}}{{a}}\rfloor+\lfloor\frac{{a}}{\mathrm{7}}\rfloor=\mathrm{2} \\ $$$${if}\:\:\:\mathrm{14}<{a}<\mathrm{21}\Rightarrow\lfloor\frac{\mathrm{7}}{{a}}\rfloor+\lfloor\frac{{a}}{\mathrm{7}}\rfloor=\mathrm{2} \\ $$$$ \\ $$ Terms of…

Question-202016

Question Number 202016 by sonukgindia last updated on 18/Dec/23 Answered by MM42 last updated on 18/Dec/23 $${x}^{\mathrm{55}} −\mathrm{1}=\mathrm{253}×\mathrm{8}{k}\Rightarrow“{x}''\:{is}\:{odd} \\ $$$$\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{54}} +{x}^{\mathrm{53}} +…+\mathrm{1}\right)=\mathrm{253}×\mathrm{8}{k} \\ $$$${x}−\mathrm{1}=\mathrm{8}{k}'\Rightarrow{x}\overset{\mathrm{8}} {\equiv}\mathrm{1}…

Question-202017

Question Number 202017 by sonukgindia last updated on 18/Dec/23 Answered by Mathspace last updated on 18/Dec/23 $${f}\left({x}\right)=\sum_{{n}=\mathrm{1}} ^{\infty} \frac{{sin}\left({nx}\right)}{\mathrm{2}^{{n}} }\:\Rightarrow \\ $$$$\int_{\mathrm{0}} ^{\pi} {f}\left({x}\right){dx}=\int_{\mathrm{0}} ^{\pi}…

Question-201949

Question Number 201949 by sonukgindia last updated on 16/Dec/23 Answered by Frix last updated on 17/Dec/23 $${n}^{{k}} \equiv{n}\mathrm{mod2024};\:{n}\in\left\{\mathrm{529},\:\mathrm{737},\:\mathrm{760},\:\mathrm{1265},\:\mathrm{1288},\:\mathrm{1496}\right\} \\ $$$$\Rightarrow \\ $$$$\Sigma{n}^{{n}} \equiv\mathrm{3mod2024} \\ $$…