Question Number 159733 by metamorfose last updated on 20/Nov/21 $$\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\:\frac{\lfloor{xcos}\left({x}\right)\rfloor}{{xsin}\left(\pi\lfloor\frac{{e}^{\frac{\mathrm{1}}{{x}}} }{{ln}\left({x}\right)}\rfloor\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 94193 by seedhamaieng@gmail.com last updated on 17/May/20 Commented by seedhamaieng@gmail.com last updated on 17/May/20 translate into Hind language Question no 7 Commented by seedhamaieng@gmail.com last updated on 17/May/20 Commented…
Question Number 159730 by Gbenga last updated on 20/Nov/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 94191 by oustmuchiya@gmail.com last updated on 17/May/20 Answered by mr W last updated on 17/May/20 $$\overset{\rightarrow} {{AD}}=\boldsymbol{{c}}+\frac{\boldsymbol{{a}}}{\mathrm{2}} \\ $$$$\overset{\rightarrow} {{BE}}=\boldsymbol{{a}}+\frac{\boldsymbol{{b}}}{\mathrm{2}} \\ $$$$\overset{\rightarrow} {{CF}}=\boldsymbol{{b}}+\frac{\boldsymbol{{c}}}{\mathrm{2}}…
Question Number 159723 by stelor last updated on 20/Nov/21 $$\frac{\mathrm{1}}{{k}+\mathrm{1}}\leqslant\int_{{k}} ^{{k}+\mathrm{1}} \left(\frac{\mathrm{1}}{{x}}\right){dx}\leqslant\frac{\mathrm{1}}{{k}}\:\:\:\:\:\:\:\:\: \\ $$$$\:{please}\:{show}\:{it}\:{with}\:{k}\in\aleph−\left(\mathrm{0}\right) \\ $$$$ \\ $$ Commented by stelor last updated on 20/Nov/21…
Question Number 159716 by mathocean1 last updated on 20/Nov/21 $${Show}\:{that}\:\bigtriangledown{r}^{{n}} ={nr}^{{n}−\mathrm{2}} {r} \\ $$ Answered by puissant last updated on 20/Nov/21 $$\bigtriangledown{r}^{{n}} \:=\:{nr}^{{n}−\mathrm{1}} \:=\:{nr}^{{n}−\mathrm{2}} ×{r}…
Question Number 94158 by seedhamaieng@gmail.com last updated on 17/May/20 Commented by prakash jain last updated on 17/May/20 $$\mathrm{mass}\:{m} \\ $$$$\mathrm{acceleration}\:{a}=−\frac{{R}}{{m}} \\ $$$$\:\:\:\:\:−{ve}\:{acclerarion}\:{as}\:{mention}\:{in} \\ $$$$\:\:\:\:\:\:{question} \\…
Question Number 159691 by 0731619 last updated on 20/Nov/21 Commented by mr W last updated on 20/Nov/21 $$={Q}\mathrm{159597} \\ $$ Terms of Service Privacy Policy…
Question Number 159690 by 0731619 last updated on 20/Nov/21 Answered by MJS_new last updated on 21/Nov/21 $$\mathrm{very}\:\mathrm{obviously}\:\mathrm{the}\:\mathrm{limit}\:\mathrm{is}\:+\infty \\ $$$$\mathrm{check}\:\mathrm{for}\:{x}=\mathrm{5} \\ $$$$\frac{\mathrm{5}^{\mathrm{5}!} }{\left(\mathrm{5}!\right)^{\mathrm{5}} }=\frac{\mathrm{5}^{\mathrm{120}} }{\mathrm{120}^{\mathrm{5}} }=\frac{\approx\mathrm{10}^{\mathrm{84}}…
Question Number 94134 by naka3546 last updated on 17/May/20 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\:\left(\:\frac{\mathrm{1}}{{x}−\mathrm{1}}\:−\:\frac{{x}}{\mathrm{ln}\:{x}}\:\right)\:=\:… \\ $$$$\left(\:{Without}\:\:{L}'\:{Hospital}\:\right) \\ $$ Commented by $@ty@m123 last updated on 17/May/20 $${Go}\:{To}\:\:{Q}.\:{No}.\:\mathrm{87105}\: \\ $$…