Question Number 21394 by mondodotto@gmail.com last updated on 22/Sep/17 Answered by mrW1 last updated on 22/Sep/17 $$\mathrm{t}=\sqrt{\mathrm{2x}+\mathrm{1}} \\ $$$$\mathrm{x}=\frac{\mathrm{t}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{dx}=\mathrm{tdt} \\ $$$$\int\mathrm{x}\sqrt{\mathrm{2x}+\mathrm{1}}\:\mathrm{dx}=\int\frac{\mathrm{t}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}}×\mathrm{t}×\mathrm{tdt}…
Question Number 21392 by mondodotto@gmail.com last updated on 22/Sep/17 Answered by mrW1 last updated on 22/Sep/17 $$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{2x}^{\mathrm{2}} +\mathrm{23}=\mathrm{2}\left(\mathrm{x}−\mathrm{0}\right)^{\mathrm{2}} +\mathrm{23} \\ $$ Terms of Service Privacy…
Question Number 86902 by redmiiuser last updated on 01/Apr/20 $${Mr}.{mathmax}\:{by}\:{abdo} \\ $$$${i}\:{request}\:{you}\:{to}\:{check} \\ $$$${my}\:{process}\:{to}\:{your} \\ $$$${question}\:\mathrm{86375}. \\ $$ Commented by mathmax by abdo last updated…
Question Number 21366 by Glorious Man last updated on 22/Sep/17 Answered by mrW1 last updated on 22/Sep/17 $$\left[\mathrm{ADF}\right]=\left[\mathrm{ABE}\right]=\mathrm{25}+\mathrm{70}=\mathrm{95} \\ $$$$\Rightarrow\left[\mathrm{EHG}\right]=\mathrm{95}−\mathrm{25}−\mathrm{55}=\mathrm{15} \\ $$$$\left[\mathrm{HGJB}\right]=\mathrm{2}×\mathrm{95}−\mathrm{15}−\mathrm{80}=\mathrm{95} \\ $$ Commented…
Question Number 86894 by M±th+et£s last updated on 01/Apr/20 $${let}\:{f}\left({x}\right)=\frac{\mathrm{1}−{x}^{\mathrm{2}} }{\lceil{x}−\mathrm{1}\rceil} \\ $$$${find}\:{the}\:{domain}\:{and}\:{f}\:'\left(−\frac{\mathrm{1}}{\mathrm{2}}\right)\:{if}\:{exist}. \\ $$$$ \\ $$$$\lceil…\rceil\:{ceiling}\:{function} \\ $$ Commented by mathmax by abdo last…
Question Number 152420 by tabata last updated on 28/Aug/21 $$\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} \:\frac{{e}^{{sinx}} }{{e}^{{cosx}} +{e}^{{sinx}} }{dx}\:\:\:? \\ $$ Answered by mindispower last updated on 28/Aug/21 $${f}\left({a}+{b}−{x}\right)+{f}\left({x}\right)={c}…
Question Number 152417 by Olaf_Thorendsen last updated on 28/Aug/21 $$\boldsymbol{\mathrm{Blague}}\:\boldsymbol{\mathrm{de}}\:\boldsymbol{\mathrm{matheux}}. \\ $$$$ \\ $$$$\mathrm{Les}\:\mathrm{math}\acute {\mathrm{e}maticiens}\:\mathrm{n}'\mathrm{urinent}\:\mathrm{pas}. \\ $$$$ \\ $$$$\mathrm{Ils}\:\mathrm{font}\:\pi\pi. \\ $$$$ \\ $$$$\mathrm{Bon}\:\mathrm{ok}\:\mathrm{je}\:\mathrm{sors}… \\ $$…
Question Number 21350 by Bruce Lee last updated on 21/Sep/17 $$\boldsymbol{{prove}}\: \\ $$$$\:\sqrt{\mathrm{2}}\:<\:\boldsymbol{{log}}_{\mathrm{8}} \mathrm{19}\:<\:\sqrt[{\mathrm{3}}]{\mathrm{3}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 21342 by xxyy@gmail.com last updated on 21/Sep/17 Answered by $@ty@m last updated on 23/Sep/17 $${Let}\:\mathrm{10}+\mathrm{log}_{\mathrm{10}} \left({x}\right)^{\mathrm{10}+\mathrm{log}_{\mathrm{10}} \left({x}\right)^{\mathrm{10}+….} } ={y} \\ $$$$\Rightarrow\mathrm{10}+\mathrm{log}\:_{\mathrm{10}} {x}^{{y}} ={y}\:\:−−\left(\mathrm{1}\right)…
Question Number 152418 by Olaf_Thorendsen last updated on 30/Aug/21 $$\boldsymbol{\mathrm{Anecdote}}\:\boldsymbol{\mathrm{historique}} \\ $$$$ \\ $$$$\left({une}\:{vraie}\:{anecdote}\:{confirm}\acute {{e}e}\:{par}\right. \\ $$$$\left.{les}\:{historiens}\right). \\ $$$$ \\ $$$$\mathrm{Au}\:\mathrm{XVIII}\grave {{e}me}\:\mathrm{si}\grave {\mathrm{e}cle},\:\mathrm{Voltaire}\:\mathrm{est}\:\mathrm{parti} \\ $$$$\mathrm{aupr}\grave…