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Question Number 199638 by witcher3 last updated on 06/Nov/23 $$\int_{\mathrm{0}} ^{\mathrm{1}} \int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{cos}\left(\mathrm{max}\left(\mathrm{x}^{\mathrm{3}} ,\mathrm{y}^{\frac{\mathrm{3}}{\mathrm{2}}} \right)\right)\mathrm{dxdy}=\mathrm{A} \\ $$$$\mathrm{old}\:\mathrm{Quation}\:\mathrm{By}\:\mathrm{mr},\mathrm{univers} \\ $$$$\mathrm{x}^{\mathrm{3}} =\mathrm{t},\mathrm{y}^{\frac{\mathrm{3}}{\mathrm{2}}} =\mathrm{s} \\ $$$$\mathrm{A}=\frac{\mathrm{2}}{\mathrm{9}}\int_{\mathrm{0}} ^{\mathrm{1}}…

Question-199658

Question Number 199658 by cherokeesay last updated on 06/Nov/23 Answered by cortano12 last updated on 07/Nov/23 $$\left(\mathrm{a}\right)\:\mathrm{Sum}\:\mathrm{the}\:\mathrm{coefficients}\:\mathrm{of}\:\mathrm{P}\left(\mathrm{x}\right)=\mathrm{3}^{\mathrm{1008}} \\ $$ Terms of Service Privacy Policy Contact:…

I-konw-that-Bosons-are-with-even-number-of-proton-and-neutron-and-eletron-but-I-am-not-sure-of-that-fermions-Can-someone-help-answer-the-question-below-Which-of-this-belongs-to-bosons-or-fermion

Question Number 199587 by aurpeyz last updated on 05/Nov/23 $$ \\ $$$${I}\:{konw}\:{that}\:{Bosons}\:{are}\:{with}\:{even}\:{number}\:{of}\: \\ $$$${proton}\:{and}\:{neutron}\:{and}\:{eletron}\:{but}\:{I}\:{am}\:{not}\:{sure} \\ $$$${of}\:{that}\:{fermions}.\: \\ $$$${Can}\:{someone}\:{help}\:{answer}\:{the}\:{question}\:{below}? \\ $$$$ \\ $$$${Which}\:{of}\:{this}\:{belongs}\:{to}\:{bosons}\:{or}\:{fermions}? \\ $$$$\mathrm{1}.\:\mathrm{12}{C}\:\left({Carbon}−\mathrm{12}\right) \\…

Question-199538

Question Number 199538 by cherokeesay last updated on 04/Nov/23 Answered by mr W last updated on 05/Nov/23 $$\left.{a}\right) \\ $$$${f}\left({x}\right)={x}^{\mathrm{3}} −\mathrm{1}−{m}\left({x}−\mathrm{1}\right) \\ $$$${f}'\left({x}\right)=\mathrm{3}{x}^{\mathrm{2}} −{m}=\mathrm{0} \\…

Question-199522

Question Number 199522 by cherokeesay last updated on 04/Nov/23 Answered by cortano12 last updated on 05/Nov/23 $$\left(\mathrm{g}_{\mathrm{1}} \right)\:\equiv\:\mathrm{y}=\mathrm{ax}+\mathrm{b}\:\left(\mathrm{tangent}\:\mathrm{line}\:\right) \\ $$$$\:\mathrm{where}\:\mathrm{a}\:=\:\frac{\mathrm{1}}{\mathrm{4}\left(\frac{\mathrm{1}}{\mathrm{4}}\right)}\:=\:\mathrm{1} \\ $$$$\:\mathrm{and}\:\mathrm{b}\:=\:\frac{\mathrm{1}}{\mathrm{4}}−\frac{\mathrm{1}}{\mathrm{8}}=\frac{\mathrm{1}}{\mathrm{8}} \\ $$$$\:\:\therefore\:\mathrm{y}=\mathrm{x}+\frac{\mathrm{1}}{\mathrm{8}} \\…