Question Number 152772 by Rankut last updated on 01/Sep/21 $$\boldsymbol{{if}}\:\:\sqrt[{\mathrm{3}}]{\sqrt[{\mathrm{3}}]{\boldsymbol{{x}}−\mathrm{2}}+\mathrm{2}}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{2}−\sqrt[{\mathrm{3}}]{\boldsymbol{{x}}−\mathrm{2}}}=\mathrm{2} \\ $$$$\:\boldsymbol{\mathrm{then}}\:\:\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{of}}\: \\ $$$$\sqrt{\mathrm{198}\boldsymbol{\mathrm{x}}^{\mathrm{4}} −\mathrm{868}\boldsymbol{\mathrm{x}}^{\mathrm{3}} −\mathrm{229}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{200}\boldsymbol{\mathrm{x}}} \\ $$ Commented by Rankut last updated on…
Question Number 152770 by naka3546 last updated on 01/Sep/21 $${How}\:\:{to}\:\:{prove}\:\:{that} \\ $$$$\:\:{a}<{b}<{c}\:\:\Rightarrow\:\:{a}+{b}\:>\:{c} \\ $$$${which}\:\:{a},{b},{c}\:\:{are}\:\:{sides}\:\:{of}\:\:{a}\:\:{triangle}\:? \\ $$ Commented by MJS_new last updated on 01/Sep/21 $${a}+{b}>{c}\wedge{a}+{c}>{b}\wedge{b}+{c}>{a}\:\Leftrightarrow\:{a},\:{b},\:{c}\:\mathrm{are}\:\mathrm{sides} \\…
Question Number 21636 by mondodotto@gmail.com last updated on 29/Sep/17 Commented by mondodotto@gmail.com last updated on 30/Sep/17 $$\mathrm{please}\:\mathrm{help}! \\ $$ Answered by Tinkutara last updated on…
Question Number 87171 by naka3546 last updated on 03/Apr/20 $${Given}\:\:{f}\left({x}\right)\:\:=\:\:\mathrm{2}\:\mathrm{sin}^{\mathrm{2}} \:{x}\:−\:\mathrm{sin}\:{x}\:+\:\mathrm{1}\:\:,\:\:\mathrm{0}\:\:\leqslant\:{x}\:\leqslant\:\mathrm{2}\pi \\ $$$${Find}\:\:{maximum}\:\:{and}\:\:{minumum}\:\:{value} \\ $$$${of}\:\:{f}\left({x}\right)\:\:{without}\:\:{differential}\:. \\ $$ Commented by john santu last updated on 03/Apr/20…
Question Number 152692 by ZiYangLee last updated on 31/Aug/21 $$\mathrm{If}\:{b}\:\mathrm{and}\:{h}\:\mathrm{are}\:\mathrm{two}\:\mathrm{integers}\:\mathrm{with}\:{b}>{h}, \\ $$$$\mathrm{and}\:{b}^{\mathrm{2}} +{h}^{\mathrm{2}} ={b}\left({a}+{h}\right)+{ah}, \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{b}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 152691 by ZiYangLee last updated on 31/Aug/21 $$\mathrm{If}\:{a},{p},{q}\:\mathrm{are}\:\mathrm{primes}\:\mathrm{with}\:{a}<{p},\:\mathrm{and} \\ $$$${a}+{p}={q},\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{a}. \\ $$ Answered by Rasheed.Sindhi last updated on 01/Sep/21 $${odd}+{odd}={even} \\ $$$$\Rightarrow{odd}\:{prime}+{odd}\:{prime}={even} \\…
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Question Number 21566 by mondodotto@gmail.com last updated on 27/Sep/17 Commented by mrW1 last updated on 27/Sep/17 $$\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }+\frac{\mathrm{3}}{\mathrm{2}^{\mathrm{2}} }=\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{3}}{\mathrm{4}}=\mathrm{1} \\ $$$$\Rightarrow\mathrm{a}=\mathrm{2} \\ $$ Commented by…
Question Number 152617 by eman_64 last updated on 30/Aug/21 Commented by mr W last updated on 30/Aug/21 $${L}=\underset{{x}\rightarrow\frac{\pi}{\mathrm{6}}} {\mathrm{lim}}\frac{−\mathrm{cos}\:\left(\frac{\pi}{\mathrm{6}}−{x}\right)}{−\mathrm{4cos}\:{x}}=\frac{\mathrm{1}}{\mathrm{4}×\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}}=\frac{\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{3}}} \\ $$ Terms of Service Privacy…