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Question Number 86361 by redmiiuser last updated on 28/Mar/20 $${mr}.{w}\:{can}\:{you}\:{check} \\ $$$${question}\:{no}.\mathrm{76808} \\ $$ Commented by mr W last updated on 28/Mar/20 $${sorry}\:{sir}! \\ $$$${i}\:{can}'{t}\:{read}\:{your}\:{working}\:{and}\:{can}'{t}…
Question Number 20825 by mondodotto@gmail.com last updated on 04/Sep/17 Commented by mondodotto@gmail.com last updated on 04/Sep/17 $$\mathrm{help}\:\mathrm{me}\:\mathrm{this}\:\mathrm{problem}\:\mathrm{please}! \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 86358 by A8;15: last updated on 28/Mar/20 Commented by Prithwish Sen 1 last updated on 28/Mar/20 $$\mathrm{cos}^{\mathrm{2}} \mathrm{x}+\mathrm{sin}^{\mathrm{2}} \mathrm{x}\:=\:\mathrm{1} \\ $$ Terms of…
Question Number 86349 by redmiiuser last updated on 28/Mar/20 $${mr}.{aliesam}\:{can}\:{you} \\ $$$${check}\:\:{the}\:{answer}\:{of} \\ $$$$\mathrm{76808} \\ $$ Commented by mr W last updated on 28/Mar/20 $${how}\:{many}\:{times}\:{do}\:{you}\:{want}\:{to}…
Question Number 151876 by tabata last updated on 23/Aug/21 Answered by Olaf_Thorendsen last updated on 23/Aug/21 $$\mathrm{A}\:=\:\mathrm{0}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{2}}{\mathrm{3}}+\frac{\mathrm{5}}{\mathrm{7}}+… \\ $$$$\mathrm{A}\:=\:\frac{\mathrm{0}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{2}}{\mathrm{4}}+\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{4}}{\mathrm{6}}+\frac{\mathrm{5}}{\mathrm{7}}+… \\ $$$$\mathrm{A}\:=\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{n}}{{n}+\mathrm{2}}\:\:\:\mathrm{diverges} \\ $$…
Question Number 20798 by ANTARES_VY last updated on 03/Sep/17 $$\begin{cases}{\mathrm{4}\boldsymbol{{x}}−\boldsymbol{{y}}=\mathrm{11}}\\{\mathrm{2}\boldsymbol{{y}}+\mathrm{5}\boldsymbol{{x}}=\mathrm{5}}\\{\boldsymbol{{x}}−\mathrm{2}\boldsymbol{{z}}=\mathrm{9}}\end{cases}\:\:\:\:\boldsymbol{{z}}+\boldsymbol{{y}}−\boldsymbol{{x}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 20744 by mondodotto@gmail.com last updated on 02/Sep/17 Answered by $@ty@m last updated on 02/Sep/17 $${ATQ}, \\ $$$${Let}\:{the}\:{equation}\:{of}\:{the}\:{st}.\:{line}\:{be} \\ $$$${y}={mx}+{c}\:−−\left(\mathrm{1}\right) \\ $$$${It}\:{passes}\:{through}\:\left(\mathrm{4},−\mathrm{2}\right) \\ $$$$\therefore\:−\mathrm{2}=\mathrm{4}{m}+{c}…
Question Number 151805 by abdurehime last updated on 23/Aug/21 $$\mathrm{1}.\mathrm{Let}\:\mathrm{R}\:\mathrm{be}\:\mathrm{a}\:\mathrm{relation}\:\mathrm{on}\:\mathrm{a}\:\mathrm{set}\: \\ $$$$\mathrm{A}=\left\{\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5},\mathrm{6}\right\}\:\mathrm{defined}\:\mathrm{by}\: \\ $$$$\mathrm{R}\left\{\left(\mathrm{a},\mathrm{b}\right):\mathrm{a}+\mathrm{b}\leqslant\mathrm{9}\:\mathrm{then}\:\mathrm{find}\right. \\ $$$$\mathrm{A}.\:\:\mathrm{R}\:\mathrm{and}\:\mathrm{R}^{−\mathrm{1}} \\ $$$$\mathrm{B}.\:\:\mathrm{domain}\:\mathrm{and}\:\mathrm{range}\:\mathrm{of}\:\mathrm{R}\:\mathrm{and}\:\mathrm{R}^{−\mathrm{1}} \\ $$$$\mathrm{C}.\mathrm{is}\:\mathrm{R}=\mathrm{R}^{−\mathrm{1}} ?? \\ $$$$ \\ $$…
Question Number 151804 by abdurehime last updated on 23/Aug/21 $$\mathrm{4}.\mathrm{Let}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{2}} \mathrm{and}\:\mathrm{g}\left(\mathrm{x}\right)=\sqrt{\mathrm{x}\:} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{fog}\left(\mathrm{x}\right)\:\mathrm{and}\:\mathrm{gof}\left(\mathrm{x}\right)\:\mathrm{and} \\ $$$$\:\mathrm{domain}\:\mathrm{of}\left(\mathrm{fog}\right)\left(\mathrm{x}\right)\mathrm{and}\left(\mathrm{gof}\right) \\ $$$$\mathrm{are}\:\mathrm{they}\:\mathrm{they}\:\mathrm{the}\:\mathrm{same}?\mathrm{explain}. \\ $$$$ \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{me}??? \\ $$$$ \\ $$…