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Question Number 19117 by sandy_suhendra last updated on 05/Aug/17 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\mathrm{7}} {\sum}}\:\frac{\mathrm{n}}{\left(\mathrm{n}^{\mathrm{2}} +\mathrm{1}\right)}\:=\:? \\ $$$$\mathrm{please}\:\mathrm{help} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 84627 by M±th+et£s last updated on 14/Mar/20 $$\left.\mathrm{1}\right)\mid{sec}\left({x}\right)\mid<\mathrm{2}{tan}\left({x}\right)\:{on}\left[\mathrm{0},\mathrm{2}\pi\right] \\ $$$$ \\ $$$$\left.\mathrm{2}\right){find}\:{the}\:{cirtical}\:{points}\:{and}\:{the}\:{range}\:{of} \\ $$$${f}\left({x}\right)=\mid{x}−\mathrm{3}\mid+\mid\mathrm{2}{x}+\mathrm{1}\mid \\ $$$$ \\ $$ Commented by TANMAY PANACEA last…
Question Number 19083 by mondodotto@gmail.com last updated on 04/Aug/17 Commented by ajfour last updated on 04/Aug/17 $$\mathrm{something}\:\mathrm{wrong}\:\mathrm{with}\:\mathrm{the}\:\mathrm{question}\:! \\ $$ Commented by mondodotto@gmail.com last updated on…
Question Number 19080 by mondodotto@gmail.com last updated on 04/Aug/17 Commented by iostream last updated on 04/Aug/17 $${a}\:\mathrm{can}\:\mathrm{be}\:\mathrm{any}\:\mathrm{integer}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 150135 by Gbenga last updated on 09/Aug/21 $$\mathrm{4}{n}^{\mathrm{2}} +\mathrm{2}{n}={e}^{{n}} \\ $$ Answered by MJS_new last updated on 10/Aug/21 $$\mathrm{you}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\ $$$${n}\approx−.\mathrm{684294}\vee{n}\approx\mathrm{4}.\mathrm{49967} \\ $$…
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Question Number 19060 by mondodotto@gmail.com last updated on 03/Aug/17 Commented by prakash jain last updated on 04/Aug/17 $${can}\:{u}\:{please}\:{use}\:{an}\:{app}\:{called} \\ $$$${camscanner}\:{to}\:{take}\:{clear}\:{images} \\ $$$${of}\:{handwritten}\:{or}\:{printed}\:{material}. \\ $$ Commented…
Question Number 19033 by Bruce Lee last updated on 03/Aug/17 Commented by Bruce Lee last updated on 03/Aug/17 $$\boldsymbol{{Help}}\:\boldsymbol{{me}},\:\boldsymbol{{by}}\:\boldsymbol{{no}}\:\boldsymbol{{Lhopital}} \\ $$ Answered by ajfour last…