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Question Number 151197 by KONE last updated on 18/Aug/21 $${etude}\:{de}\:{la}\:{monotonie}?\:{svp} \\ $$$${u}_{{n}} =\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{{k}}−{ln}\left({n}\right) \\ $$ Answered by mathmax by abdo last updated on…
Question Number 85653 by M±th+et£s last updated on 23/Mar/20 $${if}\:\:{f}\geqslant\mathrm{0}\:\:{and}\:\:\:\frac{{d}}{{dx}}\left({f}\left({x}\right)\right)^{\mathrm{2}} =\left({f}'\left({x}\right)\right)^{\mathrm{2}} \:{and}\:{f}\left(\mathrm{0}\right)=\mathrm{1} \\ $$$${find}\:{f}\left({x}\right)\:\:\: \\ $$$$ \\ $$$${if}\:{f}\left({x}\right)=\frac{\mathrm{4}{x}^{\mathrm{3}} }{{x}^{\mathrm{2}} +\mathrm{1}}\:\:{find}\:{f}^{\:−\mathrm{1}} \left({x}\right)\:\:\:{and}\:\left({f}^{\:−\mathrm{1}} \right)^{'} \left(\mathrm{2}\right) \\ $$…
Question Number 85649 by Hassen_Timol last updated on 23/Mar/20 $$\mathrm{Proove}\:\mathrm{that}\:: \\ $$$$ \\ $$$$\frac{\sqrt{\mathrm{2}−\sqrt{\mathrm{3}}}}{\mathrm{2}}\:=\:\frac{\sqrt{\mathrm{6}}−\sqrt{\mathrm{2}}}{\mathrm{4}} \\ $$ Commented by mr W last updated on 23/Mar/20 $$\frac{\sqrt{\mathrm{2}−\sqrt{\mathrm{3}}}}{\mathrm{2}}=\frac{\sqrt{\mathrm{8}−\mathrm{4}\sqrt{\mathrm{3}}}}{\mathrm{4}}=\frac{\sqrt{\left(\sqrt{\mathrm{6}}\right)^{\mathrm{2}}…
Question Number 20110 by mondodotto@gmail.com last updated on 22/Aug/17 Commented by ajfour last updated on 22/Aug/17 $$\mathrm{74658} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 85630 by Roland Mbunwe last updated on 23/Mar/20 $$\int_{\mathrm{0}} ^{\mathrm{2}\Pi} \:\:\:\frac{{dx}}{\:\sqrt{\mathrm{2}}−{cosx}}\:\: \\ $$ Commented by MJS last updated on 23/Mar/20 $$\mathrm{see}\:\mathrm{question}\:\mathrm{85568} \\ $$…
Question Number 151162 by tabata last updated on 18/Aug/21 Commented by tabata last updated on 18/Aug/21 $${how}\:{can}\:{it}\:{solve} \\ $$ Commented by mr W last updated…
Question Number 20079 by 314159 last updated on 21/Aug/17 Commented by ajfour last updated on 21/Aug/17 $${great}\:{question}.\:{no}\:{short}\:{way}. \\ $$ Commented by ajfour last updated on…
Question Number 85620 by Roland Mbunwe last updated on 23/Mar/20 $${prove}\:{that} \\ $$$$ \\ $$$$\mathrm{cosh}\:\left({x}−{y}\right)=\mathrm{cosh}\:{x}\mathrm{cosh}\:{y}−\mathrm{sinh}\:{x}\mathrm{sinh}\:{y} \\ $$ Answered by Rio Michael last updated on 23/Mar/20…
Question Number 20068 by mondodotto@gmail.com last updated on 21/Aug/17 Commented by mondodotto@gmail.com last updated on 21/Aug/17 $$\mathrm{Help}\:\mathrm{please}! \\ $$ Answered by Tinkutara last updated on…