Question Number 18715 by khamizan833@yahoo.com last updated on 28/Jul/17 $$\mid\mathrm{x}\:+\:\mathrm{1}\mid \\ $$ Answered by ajfour last updated on 29/Jul/17 $$\geqslant\mathrm{0}\:. \\ $$ Terms of Service…
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Question Number 84205 by 1406 last updated on 10/Mar/20 $${prove}\: \\ $$$${a}.\:{sin}\mathrm{2}{x}={tanx}\left(\mathrm{1}+{cos}\mathrm{2}{x}\right) \\ $$$${b}.\:{sin}\mathrm{2}{x}=\frac{\mathrm{2}{tanx}}{\mathrm{1}+{tan}^{\mathrm{2}} {x}} \\ $$ Answered by john santu last updated on 10/Mar/20…
Question Number 84206 by naka3546 last updated on 10/Mar/20 $${a},\:{b},\:{c},\:{d}\:\:\in\:\:\mathbb{N} \\ $$$$\left({a},\:{b},\:{c},\:{d}\right)\:\:{is}\:\:{quadruple}\:\:{of}\:\:{a},\:{b},\:{c},\:{d}\:\:{such}\:\:{that} \\ $$$$\:\:\:\:\:\:\:\:{b}\:\:=\:\:{a}^{\mathrm{2}} \:+\:\mathrm{1} \\ $$$$\:\:\:\:\:\:\:\:{c}\:\:=\:\:{b}^{\mathrm{2}} \:+\:\mathrm{1} \\ $$$$\:\:\:\:\:\:\:\:{d}\:\:=\:\:{c}^{\mathrm{2}} \:+\:\mathrm{1} \\ $$$$\tau\left({a}\right)\:+\:\tau\left({b}\right)\:+\:\tau\left({c}\right)\:+\:\tau\left({d}\right)\:\:{is}\:\:\:{odd}\:\:{number}\left({s}\right)\:. \\ $$$$\tau\left({k}\right)\:\:{is}\:\:{the}\:\:{number}\:\:{of}\:\:{positive}\:\:{divisor}\:\:{of}\:\:\:{natural}\:\:{number}\:\:{k}\:.…
Question Number 84202 by 1406 last updated on 10/Mar/20 $${prove}\: \\ $$$${cos}^{\mathrm{4}} {x}−{sin}^{\mathrm{4}} {x}={cos}\mathrm{22}{x} \\ $$ Answered by john santu last updated on 10/Mar/20 $$\left(\mathrm{cos}\:^{\mathrm{2}}…
Question Number 18632 by khamizan833@yahoo.com last updated on 26/Jul/17 $${x}\:−\:\mathrm{5}{x}\:+\:\mathrm{3}\:=\:\mathrm{7} \\ $$$$−\mathrm{4}{x}\:=\:\mathrm{4} \\ $$$${x}\:=\:−\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 84152 by naka3546 last updated on 09/Mar/20 Commented by MJS last updated on 09/Mar/20 $$\mathrm{we}\:\mathrm{have}\:\mathrm{to}\:\mathrm{find}\:\mathrm{for}\:\mathrm{which}\:\mathrm{values}\:\mathrm{of}\:{n}\:\mathrm{there} \\ $$$$\mathrm{is}\:\mathrm{such}\:\mathrm{an}\:{x}\:\mathrm{at}\:\mathrm{all}… \\ $$$$\mathrm{it}\:\mathrm{works}\:\mathrm{for}\:{n}=\mathrm{3}\:\mathrm{but}\:\mathrm{not}\:\mathrm{for}\:{n}=\mathrm{2}\:\mathrm{and}\:{n}=\mathrm{4} \\ $$$$… \\ $$…
Question Number 84156 by naka3546 last updated on 10/Mar/20 Commented by Tony Lin last updated on 10/Mar/20 Commented by Tony Lin last updated on 10/Mar/20…
Question Number 84123 by Roland Mbunwe last updated on 09/Mar/20 $$\int\frac{\mathrm{5}−\boldsymbol{{x}}}{\mathrm{1}+\sqrt{\left(\boldsymbol{{x}}−\mathrm{4}\right)}} \\ $$ Commented by mathmax by abdo last updated on 09/Mar/20 $${I}=\int\:\frac{\mathrm{5}−{x}}{\mathrm{1}+\sqrt{{x}−\mathrm{4}}}{dx}\:{we}\:{do}\:{the}\:{changement}\:\sqrt{{x}−\mathrm{4}}={t}\:\Rightarrow{x}−\mathrm{4}={t}^{\mathrm{2}} \\ $$$${I}\:=\int\:\frac{\mathrm{5}−\left(\mathrm{4}+{t}^{\mathrm{2}}…
Question Number 149628 by DELETED last updated on 06/Aug/21 Answered by DELETED last updated on 06/Aug/21 $$\frac{\mathrm{1}}{\mathrm{R}_{\mathrm{p}} }\:=\frac{\mathrm{1}}{\mathrm{R}_{\mathrm{1}} }+\frac{\mathrm{1}}{\mathrm{R}_{\mathrm{2}} }\:=\frac{\mathrm{1}}{\mathrm{6}}\:+\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\:\:\:\:\:\:=\frac{\mathrm{1}}{\mathrm{6}}\:+\:\frac{\mathrm{2}}{\mathrm{6}}\:=\frac{\mathrm{3}}{\mathrm{6}}\:\rightarrow\mathrm{R}_{\mathrm{p}} =\frac{\mathrm{6}}{\mathrm{3}}=\mathrm{2}\Omega \\ $$$$\mathrm{I}_{\mathrm{p}}…