Question Number 152417 by Olaf_Thorendsen last updated on 28/Aug/21 $$\boldsymbol{\mathrm{Blague}}\:\boldsymbol{\mathrm{de}}\:\boldsymbol{\mathrm{matheux}}. \\ $$$$ \\ $$$$\mathrm{Les}\:\mathrm{math}\acute {\mathrm{e}maticiens}\:\mathrm{n}'\mathrm{urinent}\:\mathrm{pas}. \\ $$$$ \\ $$$$\mathrm{Ils}\:\mathrm{font}\:\pi\pi. \\ $$$$ \\ $$$$\mathrm{Bon}\:\mathrm{ok}\:\mathrm{je}\:\mathrm{sors}… \\ $$…
Question Number 21350 by Bruce Lee last updated on 21/Sep/17 $$\boldsymbol{{prove}}\: \\ $$$$\:\sqrt{\mathrm{2}}\:<\:\boldsymbol{{log}}_{\mathrm{8}} \mathrm{19}\:<\:\sqrt[{\mathrm{3}}]{\mathrm{3}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 21342 by xxyy@gmail.com last updated on 21/Sep/17 Answered by $@ty@m last updated on 23/Sep/17 $${Let}\:\mathrm{10}+\mathrm{log}_{\mathrm{10}} \left({x}\right)^{\mathrm{10}+\mathrm{log}_{\mathrm{10}} \left({x}\right)^{\mathrm{10}+….} } ={y} \\ $$$$\Rightarrow\mathrm{10}+\mathrm{log}\:_{\mathrm{10}} {x}^{{y}} ={y}\:\:−−\left(\mathrm{1}\right)…
Question Number 152418 by Olaf_Thorendsen last updated on 30/Aug/21 $$\boldsymbol{\mathrm{Anecdote}}\:\boldsymbol{\mathrm{historique}} \\ $$$$ \\ $$$$\left({une}\:{vraie}\:{anecdote}\:{confirm}\acute {{e}e}\:{par}\right. \\ $$$$\left.{les}\:{historiens}\right). \\ $$$$ \\ $$$$\mathrm{Au}\:\mathrm{XVIII}\grave {{e}me}\:\mathrm{si}\grave {\mathrm{e}cle},\:\mathrm{Voltaire}\:\mathrm{est}\:\mathrm{parti} \\ $$$$\mathrm{aupr}\grave…
Question Number 86874 by oustmuchiya@gmail.com last updated on 01/Apr/20 $${A}\:{businessman}\:{bought}\:\mathrm{300}\:{company}\:{shares}\:{at}\:\boldsymbol{\mathrm{K}}\mathrm{60}.\mathrm{00}.\:{The}\:{nominal}\:{price}\:{was}\:\boldsymbol{\mathrm{K}}\mathrm{30}.\mathrm{00}.\:{How}\:{much}\:{does}\:{he}\:{pay}\:{for}\:{the}\:{shares}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 21341 by gopikrishnan005@gmail.com last updated on 21/Sep/17 $${the}\:{angle}\:{between}\:{the}\:{straight}\:{lines}\:{x}^{\mathrm{2}} +\mathrm{4}{xy}+\mathrm{3}{y}^{\mathrm{2}} =\mathrm{0}\:{is} \\ $$ Answered by mrW1 last updated on 21/Sep/17 $$\mathrm{x}^{\mathrm{2}} +\mathrm{4xy}+\mathrm{3y}^{\mathrm{2}} =\mathrm{0} \\…
Question Number 152393 by Olaf_Thorendsen last updated on 28/Aug/21 $$\mathrm{Quels}\:\mathrm{sont}\:\mathrm{les}\:\mathrm{deux}\:\hat {\mathrm{a}ges}\:? \\ $$$$ \\ $$$$\mathrm{J}'\mathrm{ai}\:\mathrm{deux}\:\mathrm{fois}\:\mathrm{l}'\hat {\mathrm{a}ge}\:\mathrm{que}\:\mathrm{vous}\:\mathrm{aviez} \\ $$$$\mathrm{quand}\:\mathrm{j}'\mathrm{avais}\:\mathrm{l}'\hat {\mathrm{a}ge}\:\mathrm{que}\:\mathrm{vous}\:\mathrm{avez}. \\ $$$$\mathrm{Quand}\:\mathrm{vous}\:\mathrm{aurez}\:\mathrm{l}'\hat {\mathrm{a}ge}\:\mathrm{que}\:\mathrm{j}'\mathrm{ai},\:\mathrm{nous} \\ $$$$\mathrm{aurons}\:\grave {\mathrm{a}}\:\mathrm{nous}\:\mathrm{deux}\:\mathrm{63}\:\mathrm{ans}.…
Question Number 152394 by Olaf_Thorendsen last updated on 28/Aug/21 $$\mathrm{Le}\:\mathrm{spaghetti}\:\mathrm{de}\:\mathrm{Cyril}\:\mathrm{Lignac}. \\ $$$$ \\ $$$$\mathrm{Le}\:\mathrm{chef}\:\mathrm{Cyril}\:\mathrm{Lignac}\:\mathrm{pr}\acute {\mathrm{e}pare}\:\mathrm{des} \\ $$$$\mathrm{spaghettis}.\:\mathrm{Mais}\:\mathrm{au}\:\mathrm{moment}\:\mathrm{de}\:\mathrm{les} \\ $$$$\mathrm{plonger}\:\mathrm{dans}\:\mathrm{l}'\mathrm{eau},\:\mathrm{l}'\mathrm{un}\:\mathrm{tombe}\:\mathrm{par} \\ $$$$\mathrm{terre}\:\mathrm{et}\:\mathrm{se}\:\mathrm{casse}\:\mathrm{en}\:\mathrm{trois}\:\mathrm{morceaux}. \\ $$$$ \\ $$$$\mathrm{Le}\:\mathrm{chef}\:\mathrm{Lignac}\:\mathrm{se}\:\mathrm{demande}\:\mathrm{alors}…
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Question Number 86821 by Crabby89p13 last updated on 31/Mar/20 Commented by Crabby89p13 last updated on 31/Mar/20 $${WITH}\:{LOGIC} \\ $$ Terms of Service Privacy Policy Contact:…