Question Number 18278 by mondodotto@gmail.com last updated on 17/Jul/17 Commented by mondodotto@gmail.com last updated on 18/Jul/17 $$\mathrm{help}\:\mathrm{please}!! \\ $$ Answered by geovane10math last updated on…
Question Number 149341 by saly last updated on 04/Aug/21 Commented by saly last updated on 04/Aug/21 $$\:{Do}\:{you}\:{help}\:{m}? \\ $$ Commented by Mathfinity last updated on…
Question Number 149342 by MJS_new last updated on 04/Aug/21 $$\mathrm{is}\:\mathrm{this}\:\mathrm{true}\:\mathrm{and}\:\mathrm{is}\:\mathrm{there}\:\mathrm{a}\:\mathrm{proof}? \\ $$$$\forall{k}\in\mathbb{N}\mid{k}>\mathrm{1} \\ $$$$\frac{\underset{{n}=\mathrm{1}} {\overset{{k}^{\mathrm{2}} −\mathrm{1}} {\sum}}\sqrt{{k}+\sqrt{{n}}}}{\underset{{n}=\mathrm{1}} {\overset{{k}^{\mathrm{2}} −\mathrm{1}} {\sum}}\sqrt{{k}−\sqrt{{n}}}}=\mathrm{1}+\sqrt{\mathrm{2}} \\ $$ Commented by mr…
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Question Number 18257 by aplus last updated on 17/Jul/17 Commented by mondodotto@gmail.com last updated on 17/Jul/17 $$\mathrm{Already}\:\mathrm{solved} \\ $$ Commented by prakash jain last updated…
Question Number 149323 by naka3546 last updated on 04/Aug/21 $${How}\:\:{many}\:\:{ordered}\:\:{pairs}\:\left({a},{b}\right)\:{with}\:\:{b}\:<\:{a}\:<\:\mathrm{100}\:\:,\:\:{a},{b}\:\in\:\mathbb{N}\:\:{such}\:\:{that}\:\:\frac{{a}}{{b}}\:\:{both}\:\:\:\frac{{a}+\mathrm{1}}{{b}+\mathrm{1}}\:\:{are}\:\:{integers}\:\:.\: \\ $$ Answered by Olaf_Thorendsen last updated on 05/Aug/21 $$\mathrm{N}\:=\:\underset{{b}=\mathrm{1}} {\overset{\mathrm{98}} {\sum}}\underset{{a}={b}+\mathrm{1}} {\overset{\mathrm{99}} {\sum}}\lfloor\frac{\lfloor\frac{{a}}{{b}}\rfloor}{\frac{{a}}{{b}}}×\frac{\lfloor\frac{{a}+\mathrm{1}}{{b}+\mathrm{1}}\rfloor}{\frac{{a}+\mathrm{1}}{{b}+\mathrm{1}}}\rfloor \\…
Question Number 149317 by tabata last updated on 04/Aug/21 $${lim}_{{x}\rightarrow\infty} \sqrt{{x}^{\mathrm{6}} +\mathrm{5}{x}^{\mathrm{3}} }−{x} \\ $$ Answered by EDWIN88 last updated on 04/Aug/21 $$\left.\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\sqrt{{x}^{\mathrm{6}} \left(\mathrm{1}+\mathrm{5}{x}^{−\mathrm{3}}…
Question Number 83756 by naka3546 last updated on 05/Mar/20 $${Find}\:\:{all}\:\:{real}\:\:{solutions}\:\:{of}\:\:\left({x},\:{y}\right)\:\:{such}\:\:{that} \\ $$$$\:\:\:\:\:\:\:\:\:{x}\:+\:\mathrm{3}{y}\:+\:\frac{\mathrm{4}}{{x}\:+\:{y}}\:\:=\:\:\mathrm{5} \\ $$$$\:\:\:\:\:\:\:\:\:{y}\:+\:\mathrm{3}{x}\:+\:\frac{\mathrm{5}}{{x}\:+\:{y}}\:\:=\:\:\mathrm{7} \\ $$ Commented by Prithwish Sen 1 last updated on 05/Mar/20…
Question Number 149247 by saly last updated on 04/Aug/21 Commented by saly last updated on 04/Aug/21 $$\:\:{do}\:{you}\:{help}\:\:{me}? \\ $$ Commented by john_santu last updated on…
Question Number 149244 by EDWIN88 last updated on 04/Aug/21 $$\:\:{Let}\:{a},{b},{c}\:{be}\:{positive}\:{real}\:{numbers} \\ $$$${with}\:{sum}\:\mathrm{3}.\:{Prove}\:{that}\: \\ $$$$\:\:\frac{\mathrm{1}}{{a}}+\frac{\mathrm{1}}{{b}}+\frac{\mathrm{1}}{{c}}\:\geqslant\:\frac{\mathrm{3}}{\mathrm{2}{a}^{\mathrm{2}} +{bc}}+\frac{\mathrm{3}}{\mathrm{2}{b}^{\mathrm{2}} +{ac}}+\frac{\mathrm{3}}{\mathrm{2}{c}^{\mathrm{2}} +{ab}} \\ $$ Terms of Service Privacy Policy Contact:…