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Question Number 83694 by naka3546 last updated on 05/Mar/20 Commented by naka3546 last updated on 05/Mar/20 $${DE}\:=\:{EF}\:=\:{FC}\:, \\ $$$${BG}\:=\:\mathrm{2}\:{CG}\:, \\ $$$${ABCD}\:\:{is}\:\:{a}\:\:{square}\:. \\ $$$$\frac{\left[\:{BMN}\:\right]}{\left[\:{ABCD}\:\right]}\:\:=\:\:? \\ $$$$\left(\:{without}\:\:{Trigonometry}\:\:{or}\:{Menelause}\:\right)…
Question Number 18146 by mondodotto@gmail.com last updated on 15/Jul/17 Commented by prakash jain last updated on 16/Jul/17 $$\mathrm{cos}^{\mathrm{2}} {x}+\mathrm{sin}^{\mathrm{2}} {x}=\mathrm{1} \\ $$$$\frac{\left({x}+\mathrm{1}\right)^{\mathrm{2}} \mathrm{tan}^{−\mathrm{1}} \mathrm{3}{x}+\mathrm{9}{x}^{\mathrm{3}} +{x}}{\left(\mathrm{9}{x}^{\mathrm{2}}…
Question Number 18123 by mondodotto@gmail.com last updated on 15/Jul/17 Commented by prakash jain last updated on 15/Jul/17 $$\mathrm{log}\:\left({x}−\mathrm{3}\right)^{\mathrm{1}/\mathrm{3}} +\mathrm{log}\:\mathrm{5}−\mathrm{log}\:\left({x}−\mathrm{2}\right)^{\mathrm{2}} = \\ $$$$\mathrm{log}\:\mathrm{5}=\mathrm{log}\:\left({x}−\mathrm{2}\right)^{\mathrm{2}} −\mathrm{log}\:\left({x}−\mathrm{3}\right)^{\mathrm{1}/\mathrm{3}} \\ $$$$\mathrm{5}=\frac{\left({x}−\mathrm{2}\right)^{\mathrm{2}}…
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Question Number 18109 by virus last updated on 15/Jul/17 Commented by virus last updated on 15/Jul/17 $${in}\:{air}\:{no}\:{collision} \\ $$ Commented by virus last updated on…
Question Number 83638 by bshahid010@gmail.com last updated on 04/Mar/20 Answered by TANMAY PANACEA last updated on 05/Mar/20 $${S}=\frac{\mathrm{1}}{{x}+\mathrm{1}}+\frac{\mathrm{2}}{{x}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{4}}{{x}^{\mathrm{4}} +\mathrm{1}}+…+\frac{\mathrm{2}^{{n}} }{{x}^{\mathrm{2}^{{n}} } +\mathrm{1}}\:\left({i}\:{think}\right) \\ $$$${S}=\underset{{n}=\mathrm{0}}…
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Question Number 83614 by jatharphool53@gmail.com last updated on 04/Mar/20 $$\left(\mathrm{3}{x}−\mathrm{5}\right)\left(\mathrm{3}{x}+\mathrm{4}\right) \\ $$$$ \\ $$ Commented by john santu last updated on 04/Mar/20 $$???? \\ $$…
Question Number 18077 by virus last updated on 15/Jul/17 $${A}\:{mango}\:{in}\:{a}\:{tree}\:{is}\:{located}\:\left(\mathrm{30},\mathrm{40}\right)\:{from}\:{the} \\ $$$${point}\:{of}\:{projection}\:{of}\:{stone}.{Find}\:{the}\: \\ $$$${minimum}\:{speed}\:{and}\:{the}\:{angle}\:{of}\:{projevtion} \\ $$$${of}\:{the}\:{stone}\:{so}\:{as}\:{to}\:{hit}\:{the}\:{mango} \\ $$ Answered by ajfour last updated on 15/Jul/17…