Menu Close

Category: None

64-1-6-10-1-10-I-need-so-much-plz-

Question Number 197299 by bbbbbbbb last updated on 12/Sep/23 $$\sqrt[{\mathrm{6}}]{−\mathrm{64}}−\sqrt[{\mathrm{10}}]{−\mathrm{10}}=? \\ $$$$\boldsymbol{{I}}\:\boldsymbol{\mathrm{need}}\:\boldsymbol{\mathrm{so}}\:\boldsymbol{\mathrm{much}}\:\boldsymbol{\mathrm{plz}} \\ $$ Answered by Frix last updated on 13/Sep/23 $$\forall{n}\in\mathbb{N}\backslash\left\{\mathrm{0}\right\}:\:−{n}={n}\mathrm{e}^{\mathrm{i}\pi} \:\Rightarrow \\ $$$$\sqrt[{{k}}]{−{n}}=\sqrt[{{k}}]{{n}}\mathrm{e}^{\mathrm{i}\frac{\pi}{{k}}}…

Question-197290

Question Number 197290 by sonukgindia last updated on 12/Sep/23 Commented by mahdipoor last updated on 12/Sep/23 $${log}_{\mathrm{7}} {A}={log}_{\mathrm{7}} \left(\frac{\mathrm{36}}{\mathrm{9}}\right)\Rightarrow{A}=\mathrm{4}\Rightarrow{log}_{\mathrm{2}} {A}=\mathrm{2} \\ $$ Terms of Service…

log-3-12-a-log-3-18-

Question Number 197253 by sciencestudentW last updated on 11/Sep/23 $$\mathrm{lo}\underset{\mathrm{3}} {\mathrm{g}12}={a} \\ $$$$\mathrm{log}\underset{\mathrm{3}} {\:}\mathrm{18}=?\: \\ $$ Answered by AST last updated on 11/Sep/23 $$\frac{{log}\mathrm{3}+\mathrm{2}{log}\mathrm{2}}{{log}\mathrm{3}}={a}\Rightarrow\mathrm{2}{log}\mathrm{2}=\left({a}−\mathrm{1}\right){log}\mathrm{3} \\…

log-2-20-2-log-2-5-2-log-2-10-

Question Number 197254 by sciencestudentW last updated on 11/Sep/23 $$\frac{\left(\mathrm{lo}\underset{\mathrm{2}} {\mathrm{g}20}\right)^{\mathrm{2}} \:−\left(\mathrm{lo}\underset{\mathrm{2}} {\mathrm{g}5}\right)^{\mathrm{2}} \:}{\mathrm{lo}\underset{\mathrm{2}} {\mathrm{g}10}\:}=? \\ $$ Answered by AST last updated on 11/Sep/23 $$=\frac{\left({log}_{\mathrm{2}}…

log-2-a-log-3-b-log-72-

Question Number 197255 by sciencestudentW last updated on 11/Sep/23 $$\mathrm{log}\:\mathrm{2}={a} \\ $$$$\mathrm{log}\:\mathrm{3}={b} \\ $$$$\mathrm{log}\:\mathrm{72}=? \\ $$ Answered by AST last updated on 11/Sep/23 $${log}\left(\mathrm{9}×\mathrm{8}\right)=\mathrm{2}{log}\mathrm{3}+\mathrm{3}{log}\mathrm{2}=\mathrm{2}{b}+\mathrm{3}{a} \\…

log-6-2-a-log-6-9-

Question Number 197249 by sciencestudentW last updated on 11/Sep/23 $$\mathrm{lo}\underset{\mathrm{6}} {\mathrm{g}2}={a} \\ $$$$\mathrm{lo}\underset{\mathrm{6}} {\mathrm{g}9}=?\:\: \\ $$ Answered by AST last updated on 11/Sep/23 $$\frac{{log}\mathrm{2}}{{log}\mathrm{2}+{log}\mathrm{3}}={a}\Rightarrow{log}\mathrm{2}\left(\mathrm{1}−{a}\right)={alog}\mathrm{3} \\…