Question Number 81308 by naka3546 last updated on 11/Feb/20 Commented by mr W last updated on 11/Feb/20 $$\mathrm{2104}? \\ $$ Commented by naka3546 last updated…
Question Number 146837 by Aydin last updated on 16/Jul/21 $${p} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 146838 by bobhans last updated on 16/Jul/21 $$\mathrm{Given}\:\mathrm{4}^{\mathrm{x}} +\mathrm{4}^{−\mathrm{x}} −\mathrm{2}^{\mathrm{2}−\mathrm{x}} +\mathrm{2}^{\mathrm{2}+\mathrm{x}} −\mathrm{7}=\mathrm{0}\:,\mathrm{x}>\mathrm{0} \\ $$$$\:\mathrm{find}\:\mathrm{2}^{\mathrm{x}} +\mathrm{2}^{−\mathrm{x}} . \\ $$$$\: \\ $$$$\:\mathrm{if}\:\mathrm{x}\in\left[\:−\frac{\pi}{\mathrm{6}},\mathrm{0}\:\right]\:\mathrm{then}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\mathrm{function}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{cot}\:\left(\mathrm{x}+\frac{\pi}{\mathrm{3}}\right)−\mathrm{tan}\:\left(\frac{\mathrm{2}\pi}{\mathrm{3}}−\mathrm{x}\right)\: \\…
Question Number 81267 by behi83417@gmail.com last updated on 10/Feb/20 $$\boldsymbol{\mathrm{p}},\mathrm{is}\:\mathrm{a}\:\mathrm{point},\boldsymbol{\mathrm{inside}}\:,\boldsymbol{\mathrm{onside}}\:,\boldsymbol{\mathrm{outside}}\:\mathrm{of} \\ $$$$\mathrm{equilateral}\:\mathrm{triangle}.\mathrm{find}\:\mathrm{side}\:\mathrm{of}\:\mathrm{triangle} \\ $$$$\mathrm{if}\:\mathrm{distance}\:\mathrm{of}\::\boldsymbol{\mathrm{p}}\:\mathrm{from}\:\:\mathrm{vertices}\:\mathrm{of}\:\mathrm{triangle} \\ $$$$\mathrm{be}\:\mathrm{equail}\:\mathrm{to}:\:\mathrm{5},\mathrm{7},\mathrm{11}. \\ $$$$\left(\mathrm{study}\:\mathrm{each}\:\mathrm{conditions}\:\mathrm{separately}\right). \\ $$$$\mathrm{find}\:\mathrm{side}\:\mathrm{of}\:\mathrm{ABC}\:\mathrm{and}\:\mathrm{p}_{\mathrm{1}} \mathrm{p}_{\mathrm{2}} \mathrm{p}_{\mathrm{3}} \:\mathrm{in}\:\mathrm{a}\: \\ $$$$\mathrm{special}\:\mathrm{case}\:\mathrm{that}:\begin{cases}{\mathrm{Ap}_{\mathrm{1}}…
Question Number 146793 by KONE last updated on 15/Jul/21 $$\forall{n}\geqslant\mathrm{2},\:{u}_{{n}} =\underset{{k}=\mathrm{2}} {\overset{{n}} {\prod}}\mathrm{cos}\:\left(\frac{\pi}{\mathrm{2}^{{k}} }\right)\:{et}\:{v}_{{n}} ={u}_{{n}} \mathrm{sin}\:\left(\frac{\pi}{\mathrm{2}^{{n}} }\right) \\ $$$${convergence},\:{nature},\:{sens}\:{of}\:{variations}\:{and}\:{adjantes}? \\ $$$${u}_{{n}} \:{and}\:{v}_{{n}} \\ $$$${help}\:{me}\:{please} \\…
Question Number 146784 by tabata last updated on 15/Jul/21 Commented by tabata last updated on 15/Jul/21 $$??????? \\ $$ Commented by tabata last updated on…
Question Number 146780 by tabata last updated on 15/Jul/21 $${find}\:{by}\:{residue}\:\int_{\mathrm{0}} ^{\:\mathrm{2}\pi} \:\frac{{d}\theta}{\mathrm{1}+{ksin}\theta}\:\:\:,\mathrm{0}<{k}<\mathrm{1} \\ $$ Answered by mathmax by abdo last updated on 15/Jul/21 $$\Phi=\int_{\mathrm{0}} ^{\mathrm{2}\pi}…
Question Number 146772 by ZiYangLee last updated on 15/Jul/21 $$\mathrm{If}\:{z}=\mathrm{cos}\:\theta+{i}\:\mathrm{sin}\:\theta,\:\mathrm{prove}\:\mathrm{that} \\ $$$$\mathrm{cos}^{\mathrm{6}} \theta=\frac{\mathrm{1}}{\mathrm{32}}\left(\mathrm{cos}\:\mathrm{6}\theta+\mathrm{6cos}\:\mathrm{4}\theta+\mathrm{15cos}\:\mathrm{2}\theta+\mathrm{10}\right). \\ $$$$\mathrm{Hence}\:\mathrm{or}\:\mathrm{otherwise},\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:{a}} \sqrt{\left({a}^{\mathrm{2}} −{x}^{\mathrm{2}} \right)^{\mathrm{5}} }\:{dx}. \\ $$ Answered…
Question Number 146771 by ZiYangLee last updated on 15/Jul/21 $$\mathrm{Given}\:\mathrm{that}\:{y}''−\mathrm{4}{y}'+\mathrm{3}{y}=\mathrm{0},\:{y}\left(\mathrm{0}\right)=\mathrm{0},\:{y}'\left(\mathrm{0}\right)=\mathrm{2}, \\ $$$$\mathrm{find}\:{y}\left(\mathrm{ln}\:\mathrm{2}\right). \\ $$ Answered by mathmax by abdo last updated on 15/Jul/21 $$\rightarrow\mathrm{r}^{\mathrm{2}} −\mathrm{4r}+\mathrm{3}=\mathrm{0}\:\rightarrow\Delta^{'}…
Question Number 81226 by 20092104 last updated on 10/Feb/20 $$\frac{{d}}{{dx}}\left({x}!\right)\:{and}\:\frac{{d}}{{dx}}\left(\mathrm{1}+\mathrm{2}+\mathrm{3}+…+{x}\right) \\ $$ Answered by MJS last updated on 10/Feb/20 $$\frac{{d}}{{dx}}\left[{x}!\right]\:\mathrm{doesn}'\mathrm{t}\:\mathrm{exist}\:\mathrm{because}\:{x}!\:\mathrm{is}\:\mathrm{not}\:\mathrm{continuous} \\ $$$$\mathrm{1}+\mathrm{2}+\mathrm{3}+…+{x}=\frac{{x}\left({x}+\mathrm{1}\right)}{\mathrm{2}} \\ $$$$\frac{{d}}{{dx}}\left[\frac{{x}\left({x}+\mathrm{1}\right)}{\mathrm{2}}\right]={x}+\frac{\mathrm{1}}{\mathrm{2}} \\…