Question Number 79081 by arkanmath7@gmail.com last updated on 22/Jan/20 $${I}\:{dont}\:{know}\:{how}\:{to}\:{show}\:{the}\:{functions}\:{of}\: \\ $$$${this}\:{type}\:{if}\:{it}\:{is}\:{continuous}\:{or}\:{not}\:{in}\:{topological}\:{space}. \\ $$$${I}\:{know}\:{the}\:{method}\:{is}\:{to}\:{use}\:{one}\:{of}\:{two}\:{properties}: \\ $$$${the}\:{inverse}\:{image}\:{of}\:{eah}\:{open}\:{is}\:{open}, \\ $$$${and}\:{the}\:{inverse}\:{image}\:{of}\:{each}\:{closed}\:{is}\:{closed} \\ $$$${but}\:{i}\:{dont}\:{know}\:{how}\:{to}\:{use}\:{them}. \\ $$$${i}\:{will}\:{be}\:{thaked}\:{if}\:{someone}\:{help}\:{ed}\:{me}\:{with}\:{the}\:{steps} \\ $$$$ \\…
Question Number 144607 by aliibrahim1 last updated on 26/Jun/21 Answered by mathmax by abdo last updated on 27/Jun/21 $$\mathrm{A}_{\mathrm{n}} =\prod_{\mathrm{k}=\mathrm{2}} ^{\mathrm{n}} \mathrm{e}\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{k}^{\mathrm{2}} }\right)^{\mathrm{k}^{\mathrm{2}} } \:\Rightarrow\prod_{\mathrm{n}=\mathrm{2}}…
Question Number 79064 by Khyati last updated on 22/Jan/20 $${find}\:\:{li}\underset{{x}\rightarrow\:−\mathrm{3}} {{m}}\frac{{x}^{\mathrm{3}} +\mathrm{27}}{{x}^{\mathrm{5}} +\mathrm{243}} \\ $$ Answered by john santu last updated on 22/Jan/20 $$\underset{{x}\rightarrow−\mathrm{3}} {\mathrm{lim}}\frac{\frac{{d}}{{dx}}\left({x}^{\mathrm{3}}…
Question Number 79065 by Khyati last updated on 22/Jan/20 $$\left.\right].\:{li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\:\frac{\left[{sin}\left(\alpha+\beta\right){x}+{sin}\left(\alpha−\beta\right){x}+{sin}\mathrm{2}\alpha{x}\right.}{{cos}\mathrm{2}\beta{x}−{cos}\mathrm{2}\alpha{x}}.{x} \\ $$ Commented by jagoll last updated on 22/Jan/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\left[\mathrm{sin}\:\left(\alpha+\beta\right)\mathrm{x}+\mathrm{sin}\:\left(\alpha−\beta\right)\mathrm{x}+\mathrm{sin}\:\mathrm{2}\alpha\mathrm{x}\right]}{\mathrm{cos}\:\mathrm{2}\beta\mathrm{x}−\mathrm{cos}\:\mathrm{2}\alpha\mathrm{x}}×\:\mathrm{x}? \\ $$ Commented…
Question Number 144602 by phally last updated on 26/Jun/21 Answered by mathmax by abdo last updated on 27/Jun/21 $$\mathrm{u}_{\mathrm{n}} =\sum_{\mathrm{k}=\mathrm{1}} ^{\mathrm{n}} \:\frac{\mathrm{cos}\left(\mathrm{k}\right)}{\mathrm{k}\left(\mathrm{k}+\mathrm{1}\right)}\:\Rightarrow\mathrm{lim}_{\mathrm{n}\rightarrow\infty} \mathrm{u}_{\mathrm{n}} =\sum_{\mathrm{k}=\mathrm{1}} ^{\infty}…
Question Number 144589 by ZiYangLee last updated on 26/Jun/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\underset{{k}=\mathrm{1}} {\overset{\mathrm{90}} {\sum}}\mathrm{sin}\:{k}°+\underset{{k}=\mathrm{1}} {\overset{\mathrm{90}} {\sum}}\mathrm{cos}\:\left(\mathrm{90}°+{k}°\right) \\ $$ Answered by Dwaipayan Shikari last updated on…
Question Number 79052 by gopikrishnan last updated on 22/Jan/20 $${if}\:\mid{adj}\left({A}\right)\mid=\mathrm{4}\:{of}\:{order}\mathrm{2},{then}\:\mid{adj}\left(\mathrm{3}{A}\right)\mid \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 79055 by gopikrishnan last updated on 22/Jan/20 $${The}\:{number}\:{of}\:{real}\:{numbers}\:{in}\:\left[\mathrm{0},\mathrm{2}{pi}\right]\:{satisfying}\:\mathrm{sin}^{−\mathrm{1}} {x}−\mathrm{2}{sin}^{\mathrm{2}} {x}+\mathrm{1}=\mathrm{0}\:{is} \\ $$ Commented by mr W last updated on 22/Jan/20 $${sir}:\:{i}\:{asked}\:{you}\:{repeatedly}\:{not}\:{to} \\ $$$${write}\:{the}\:{whole}\:{post}\:{in}\:{a}\:{single}\:{line}.…
Question Number 79054 by gopikrishnan last updated on 22/Jan/20 $${The}\:{angle}\:{between}\:{the}\:{planes}\:\overset{\rightarrow} {{r}}.\left(\mathrm{2}\overset{\rightarrow} {{i}}+\mathrm{2}\overset{\rightarrow} {{j}}+\mathrm{2}\overset{\rightarrow} {{k}}\right)=\mathrm{4}\:{and}\:\mathrm{4}{x}−\mathrm{2}{y}+\mathrm{2}{z}=\mathrm{15}\:{is} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 144584 by zakirullah last updated on 26/Jun/21 $$\mathrm{b}.\:\mathrm{An}\:\mathrm{experiment}\:\mathrm{consists}\:\mathrm{of}\:\mathrm{flipping}\:\mathrm{an}\:\mathrm{unbiased}\:\mathrm{coin} \\ $$$$\mathrm{and}\:\mathrm{flipping}\:\mathrm{again}\:\mathrm{if}\:\mathrm{a}\:\mathrm{head}\:\mathrm{occuors}\:\mathrm{and}\:\mathrm{yet} \\ $$$$\mathrm{again}\:\mathrm{if}\:\mathrm{a}\:\mathrm{second}\:\mathrm{bead}\:\mathrm{occours}\:,\:\mathrm{list}\:\mathrm{the}\:\mathrm{elements} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{sample}\:\mathrm{space}\:.\:\mathrm{find}\:\mathrm{the}\:\mathrm{probability} \\ $$$$\mathrm{of}\:\mathrm{exactly}\:\mathrm{two}\:\mathrm{tosses}. \\ $$$$\mathrm{c}.\:\mathrm{if}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{X}\:\:\mathrm{occours}\:\mathrm{but} \\ $$$$\mathrm{not}\:\mathrm{Y}\:=\:\mathrm{probability}\:\mathrm{that}\:\mathrm{X}\:\mathrm{occours}\:−\:\mathrm{probabulity}\:\mathrm{that}\:\mathrm{Y}\:\mathrm{occours} \\ $$$$\mathrm{CLO}−\mathrm{1}.\: \\…