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Question-15217

Question Number 15217 by Mr Chheang Chantria last updated on 08/Jun/17 Answered by ajfour last updated on 08/Jun/17 $$\:\:\:\boldsymbol{{v}}=\boldsymbol{{ab}}^{\mathrm{2}} +\boldsymbol{{a}}^{\mathrm{2}} \boldsymbol{{b}}+\boldsymbol{{ac}}+\boldsymbol{{bc}} \\ $$$$\:\:\:\boldsymbol{{v}}\:=\boldsymbol{{ab}}\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right)+\boldsymbol{{c}}\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right) \\ $$$$\:\:\:\:\:\:=\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right)\left(\boldsymbol{{ab}}+\boldsymbol{{c}}\right)\leqslant\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right)\left[\frac{\left(\boldsymbol{{a}}+\boldsymbol{{b}}\right)^{\mathrm{2}}…

Question-146233

Question Number 146233 by tabata last updated on 12/Jul/21 Commented by tabata last updated on 12/Jul/21 $${From}\:{the}\:{figure}\:,{calculate}\: \\ $$$$ \\ $$$$\left(\mathrm{1}\right)\:{the}\:{electric}\:{potential}\:{difference}\:{between}\:{A}\:{and}\:{B} \\ $$$$ \\ $$$$\left(\mathrm{2}\right)\:{the}\:{electromotive}\:{force}…

Question-146183

Question Number 146183 by tabata last updated on 11/Jul/21 Commented by tabata last updated on 11/Jul/21 $${in}\:{the}\:{adjacent}\:{figure}\:,{calculate}\: \\ $$$$ \\ $$$$\left(\mathrm{1}\right)\:{the}\:{intensity}\:{of}\:{the}\:{current}\:{passing}\:{throuph}\:{the}\:{circuit} \\ $$$$ \\ $$$$\left(\mathrm{2}\right){the}\:{potential}\:{difference}\:{between}\:{the}\:{two}\:{points}\:{x},{y}…