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A-lim-n-1-1-2-3-1-2-1-2-2-3-2-2-1-n-2-3n-2-

Question Number 144246 by SOMEDAVONG last updated on 23/Jun/21 $$\mathrm{A}=\underset{\mathrm{n}\rightarrow+\propto} {\mathrm{lim}}\left[\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{2}} +\mathrm{3}\left(\mathrm{1}\right)+\mathrm{2}}\:+\:\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} +\mathrm{3}\left(\mathrm{2}\right)+\mathrm{2}}\:+..+\:\frac{\mathrm{1}}{\mathrm{n}^{\mathrm{2}} +\mathrm{3n}+\mathrm{2}}\right] \\ $$ Answered by Ar Brandon last updated on 23/Jun/21 $$\mathscr{L}=\underset{\mathrm{n}\rightarrow\infty}…

0-pi-sinx-2n-dx-n-N-

Question Number 144174 by lapache last updated on 22/Jun/21 $$\int_{\mathrm{0}} ^{\pi} \left({sinx}\right)^{\mathrm{2}{n}} {dx}=….?\:\:\:\forall{n}\in\mathbb{N} \\ $$ Commented by Willson last updated on 22/Jun/21 $$\mathrm{4}^{\mathrm{n}} \mathrm{sin}^{\mathrm{2n}} \mathrm{t}\:=\:\mathrm{C}_{\mathrm{2n}}…

I-e-x-2-e-x-e-x-2-1-dx-

Question Number 144152 by SOMEDAVONG last updated on 22/Jun/21 $$\mathrm{I}=\int\frac{\mathrm{e}^{\mathrm{x}^{\mathrm{2}} } +\mathrm{e}^{\mathrm{x}} }{\mathrm{e}^{\mathrm{x}^{\mathrm{2}} } +\mathrm{1}}\mathrm{dx}=? \\ $$ Answered by ArielVyny last updated on 22/Jun/21 $$=\int\frac{{e}^{{x}^{\mathrm{2}}…

A-lim-n-1-2-1-7-3-1-7-4-1-7-n-1-7-n-9-1-7-

Question Number 144107 by SOMEDAVONG last updated on 21/Jun/21 $$\mathrm{A}=\underset{\mathrm{n}\rightarrow+\propto} {\mathrm{lim}}\frac{\mathrm{1}+\sqrt[{\mathrm{7}}]{\mathrm{2}}+\sqrt[{\mathrm{7}}]{\mathrm{3}}+\sqrt[{\mathrm{7}}]{\mathrm{4}}+…..+\sqrt[{\mathrm{7}}]{\mathrm{n}}}{\:\sqrt[{\mathrm{7}}]{\mathrm{n}^{\mathrm{9}} }}\:=? \\ $$ Answered by Dwaipayan Shikari last updated on 21/Jun/21 $${A}=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{1}+\sqrt[{\mathrm{7}}]{\mathrm{2}}+..+\sqrt[{\mathrm{7}}]{{n}}}{\:\sqrt[{\mathrm{7}}]{{n}^{\mathrm{8}} }}…

Question-13030

Question Number 13030 by 2002154006 last updated on 11/May/17 Commented by prakash jain last updated on 12/May/17 $${x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{5}=\mathrm{0} \\ $$$$\mathrm{x}_{\mathrm{1}} +\mathrm{x}_{\mathrm{2}} =\mathrm{4} \\ $$$$\mathrm{x}_{\mathrm{1}}…