Question Number 142603 by mohammad17 last updated on 02/Jun/21 Answered by mr W last updated on 03/Jun/21 Commented by mr W last updated on 03/Jun/21…
Question Number 77057 by Maclaurin Stickker last updated on 03/Jan/20 Commented by Maclaurin Stickker last updated on 03/Jan/20 $${I}\:{wouldn}'{t}\:{like}\:{an}\:{answer}.\:{I}\:{would}\:{like} \\ $$$${a}\:{tip}\:{on}\:{how}\:{to}\:{solve}\:{this}\:{problem}. \\ $$ Commented by…
Question Number 142558 by SOMEDAVONG last updated on 02/Jun/21 $$\mathrm{find}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{x}^{\mathrm{2}} =\mathrm{5}^{\mathrm{log}_{\mathrm{2}} \mathrm{x}} −\mathrm{3}^{\mathrm{log}_{\mathrm{2}} \mathrm{x}} \:\mathrm{on}\:\mathbb{R}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 77015 by aliesam last updated on 02/Jan/20 Commented by MJS last updated on 02/Jan/20 $$\mathrm{35}^{\mathrm{2}} =\mathrm{1225} \\ $$$$\mathrm{335}^{\mathrm{2}} =\mathrm{112225} \\ $$$$\mathrm{3335}^{\mathrm{2}} =\mathrm{11122225} \\…
Question Number 142537 by mathocean1 last updated on 01/Jun/21 $$\mathrm{Given}: \\ $$$$\mathrm{z}_{\mathrm{1}} =\mathrm{e}^{\mathrm{i}\frac{\pi}{\mathrm{3}}} \left(\mathrm{z}+\mathrm{3}\right)−\mathrm{3}\:\mathrm{and}\:\mathrm{z}_{\mathrm{2}} =\mathrm{e}^{−\mathrm{i}\frac{\mathrm{2}\pi}{\mathrm{3}}} \left(\mathrm{z}−\mathrm{3}\right)+\mathrm{3}. \\ $$$$\mathrm{Show}\:\mathrm{that}\: \\ $$$$\frac{\mathrm{z}_{\mathrm{2}} −\mathrm{z}}{\mathrm{z}_{\mathrm{1}} −\mathrm{z}}=\mathrm{i}\sqrt{\mathrm{3}}\frac{\mathrm{z}−\mathrm{3}}{\mathrm{z}+\mathrm{3}} \\ $$ Terms…
Question Number 77000 by vishalbhardwaj last updated on 02/Jan/20 $$\mathrm{One}\:\mathrm{vertex}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equalateral}\:\mathrm{triangle} \\ $$$$\mathrm{with}\:\mathrm{centroid}\:\mathrm{at}\:\mathrm{the}\:\mathrm{origin}\:\mathrm{and}\:\mathrm{one} \\ $$$$\mathrm{side}\:\mathrm{as}\:\mathrm{x}+\mathrm{y}−\mathrm{2}\:=\:\mathrm{0}\:\mathrm{is} \\ $$$$\left(\mathrm{a}\right)\:\:\left(−\mathrm{1},−\mathrm{1}\right)\:\:\left(\mathrm{b}\right)\:\left(\mathrm{2},\mathrm{2}\right)\:\:\left(\mathrm{c}\right)\:\left(−\mathrm{2},−\mathrm{2}\right) \\ $$$$\left(\mathrm{d}\right)\:\left(\mathrm{2},−\mathrm{2}\right) \\ $$ Commented by vishalbhardwaj last updated…
Question Number 77001 by vishalbhardwaj last updated on 02/Jan/20 $$\mathrm{The}\:\mathrm{point}\:\left(\mathrm{4},\mathrm{1}\right)\:\mathrm{undergoes}\:\mathrm{the}\:\mathrm{following} \\ $$$$\mathrm{two}\:\mathrm{successive}\:\mathrm{transformations} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{reflection}\:\mathrm{about}\:\mathrm{the}\:\mathrm{line}\:\mathrm{y}=\mathrm{x} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{translation}\:\mathrm{through}\:\mathrm{a}\:\mathrm{distance} \\ $$$$\mathrm{2}\:\mathrm{units}\:\mathrm{along}\:\mathrm{the}\:\mathrm{positive}\:\mathrm{x}\:\mathrm{axis} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{final}\:\mathrm{coordinates} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{point}\:???? \\ $$ Answered…
Question Number 142538 by Rankut last updated on 02/Jun/21 $$\mathrm{2}\boldsymbol{{x}}^{\mathrm{7}} +\boldsymbol{{x}}^{\mathrm{28}} =\mathrm{3}\boldsymbol{{x}}^{\mathrm{21}} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Answered by Ar Brandon last updated on 02/Jun/21 $$\mathrm{2x}^{\mathrm{7}}…
Question Number 142528 by mohammad17 last updated on 01/Jun/21 $$\int_{\mathrm{1}} ^{\:\infty} \:\frac{{dx}}{{e}^{{x}} −\mathrm{2}^{{x}} } \\ $$ Answered by mathmax by abdo last updated on 02/Jun/21…
Question Number 11459 by @ANTARES_VY last updated on 26/Mar/17 $$\boldsymbol{\mathrm{If}} \\ $$$$\frac{\mathrm{4}\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\mathrm{4}\boldsymbol{\mathrm{xy}}+\mathrm{3}\boldsymbol{\mathrm{y}}^{\mathrm{2}} }{\mathrm{2}\boldsymbol{\mathrm{y}}^{\mathrm{2}} +\mathrm{2}\boldsymbol{\mathrm{xy}}−\mathrm{5}\boldsymbol{\mathrm{x}}^{\mathrm{2}} }=\mathrm{1}\:\:\boldsymbol{\mathrm{if}}\:\:\boldsymbol{\mathrm{the}} \\ $$$$\frac{\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}}{\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{y}}}\:\:\boldsymbol{\mathrm{what}}\:\:\boldsymbol{\mathrm{is}}\:\:\boldsymbol{\mathrm{th}}\:\:\boldsymbol{\mathrm{value}}? \\ $$ Answered by ajfour last updated…