Question Number 76645 by naka3546 last updated on 29/Dec/19 Commented by mr W last updated on 29/Dec/19 $$\left(\mathrm{5}−{a}\right)^{\mathrm{2}} ={a}^{\mathrm{2}} +\left(\mathrm{3}+{a}\right)^{\mathrm{2}} \\ $$$${a}^{\mathrm{2}} +\mathrm{16}{a}−\mathrm{16}=\mathrm{0} \\ $$$$\Rightarrow{a}=\mathrm{4}\sqrt{\mathrm{5}}−\mathrm{8}=\mathrm{2}\left(\mathrm{2}\sqrt{\mathrm{5}}−\mathrm{4}\right)…
Question Number 142174 by mohammad17 last updated on 27/May/21 Commented by mohammad17 last updated on 27/May/21 $$????????? \\ $$ Commented by MJS_new last updated on…
Question Number 76627 by Maclaurin Stickker last updated on 28/Dec/19 Commented by Maclaurin Stickker last updated on 28/Dec/19 $${If}\:{C}'\:{and}\:{B}'\:{are}\:{midpints}\:{of}\:{AC}\:{and} \\ $$$${AB},\:{find}\:{cot}\left(\theta\right)\:{as}\:{a}\:{function} \\ $$$${of}\:{angles}\:{B}\:{and}\:{C}. \\ $$…
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Question Number 76575 by Rio Michael last updated on 28/Dec/19 $${define}\:{the}\:{concept}\:{of}\:{a}\:\boldsymbol{{contingency}} \\ $$$${Which}\:{of}\:{the}\:{following}\:{is}\:{a}\:{contingency}\: \\ $$$${and}\:{which}\:{is}\:{a}\:{tautology} \\ $$$$\left.\mathrm{1}\right)\:\left({P}\:\Rightarrow\sim{P}\right)\:\vee\:{Q}\:\: \\ $$$$\left.\mathrm{2}\right)\:\left({P}\:\Rightarrow\:\sim{P}\right)\:\Rightarrow\:{Q} \\ $$ Answered by benjo 1/2…
Question Number 142105 by PRITHWISH SEN 2 last updated on 26/May/21 $$\mathrm{Sum}\:\mathrm{the}\:\mathrm{series}\:\mathrm{to}\:\mathrm{n}\:\mathrm{terms} \\ $$$$\mathrm{sin}\:\theta−\mathrm{sin}\:\mathrm{2}\theta+\mathrm{sin}\:\mathrm{3}\theta−…….. \\ $$ Answered by Dwaipayan Shikari last updated on 26/May/21 $$\underset{{n}=\mathrm{1}}…
Question Number 142100 by ZiYangLee last updated on 26/May/21 $$\:\:\:\:\:\:\int^{\:} \:\frac{\mathrm{1}}{\mathrm{1}+\sqrt{\mathrm{1}+{t}}\:}\:{dt}=? \\ $$ Answered by iloveisrael last updated on 26/May/21 $${I}=\int\:\frac{{dt}}{\mathrm{1}+\sqrt{\mathrm{1}+{t}}}\:=\:\int\:\frac{\mathrm{1}−\sqrt{\mathrm{1}+{t}}}{−{t}}\:{dt} \\ $$$${I}=\int\:\frac{\sqrt{\mathrm{1}+{t}}}{{t}}\:{dt}\:−\mathrm{ln}\:{t}\:+{c} \\ $$$${let}\:\sqrt{\mathrm{1}+{t}}\:=\:{u}\Rightarrow{t}={u}^{\mathrm{2}}…
Question Number 142096 by mohammad17 last updated on 26/May/21 Commented by mohammad17 last updated on 26/May/21 $${help}\:{me}\:{sir}\:{please} \\ $$ Terms of Service Privacy Policy Contact:…