Menu Close

Category: None

Question-148068

Question Number 148068 by tabata last updated on 25/Jul/21 Answered by Olaf_Thorendsen last updated on 25/Jul/21 $$\left(\mathrm{B}\right) \\ $$$$\mathrm{Let}\:{f}\left({z}\right)\:=\:{z}^{\mathrm{7}} −\mathrm{4}{z}^{\mathrm{3}} +{z}−\mathrm{1}\:=\:\mathrm{0},\:\mid{z}\mid\:=\:\mathrm{1} \\ $$$$\mathrm{and}\:{g}\left({z}\right)\:=\:−\mathrm{4}{z}^{\mathrm{3}} \\ $$$$…

p-q-p-q-simplify-

Question Number 148051 by abdurehime last updated on 25/Jul/21 $$\rightharpoondown\left(\rightharpoondown\mathrm{p}\rightarrow\mathrm{q}\right)\vee\left(\mathrm{p}\wedge\rightharpoondown\mathrm{q}\right)\: \\ $$$$\mathrm{simplify} \\ $$ Commented by abdurehime last updated on 25/Jul/21 $$\mathrm{please}\:\mathrm{sir}\:\mathrm{help}\:\mathrm{me} \\ $$ Commented…

Question-82499

Question Number 82499 by Maclaurin Stickket last updated on 21/Feb/20 Commented by Maclaurin Stickket last updated on 21/Feb/20 $${ABCD}\:{is}\:{a}\:{square}\:{with}\:{side}\:\mathrm{1}. \\ $$$${The}\:{circles}\:{are}\:{congruent}. \\ $$$${AC}\:{is}\:{the}\:{diagonal}\:{of}\:{square}. \\ $$$${Find}\:{the}\:{radius}\:{r}.…

Question-82485

Question Number 82485 by naka3546 last updated on 21/Feb/20 Commented by abdomathmax last updated on 21/Feb/20 $${let}\:{f}\left({x}\right)=\frac{\mathrm{6}}{{t}^{\mathrm{2}} }−\frac{{sin}\left(\mathrm{6}{t}\right)}{{t}^{\mathrm{3}} {cos}^{\mathrm{2}} \left(\mathrm{3}{t}\right)}\:\Rightarrow \\ $$$${f}\left({x}\right)=\frac{\mathrm{1}}{{t}^{\mathrm{2}} }\left\{\mathrm{6}−\frac{{sin}\left(\mathrm{6}{t}\right)}{{t}\:{cos}^{\mathrm{2}} \left(\mathrm{3}{t}\right)}\right\}\:{we}\:{have}\: \\…