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Question Number 10864 by chux last updated on 28/Feb/17 Answered by ridwan balatif last updated on 28/Feb/17 $$\mathrm{first}\:\mathrm{step} \\ $$$$\left(\frac{\mathrm{sinx}}{\mathrm{cosx}}\right)^{\mathrm{2}} =\left(\mathrm{tanx}\right)^{\mathrm{2}} \\ $$$$\frac{\mathrm{sin}^{\mathrm{2}} \mathrm{x}}{\mathrm{cos}^{\mathrm{2}} \mathrm{x}}=\mathrm{tan}^{\mathrm{2}}…
Question Number 10853 by geovane10math last updated on 27/Feb/17 $$\left({x}\:+\:{y}\right)^{{n}} \:=\:\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\begin{pmatrix}{{n}}\\{{k}}\end{pmatrix}{x}^{{k}} {y}^{{n}−{k}} \\ $$$$\left({x}\:−\:{y}\right)^{{n}} \:=\:??????? \\ $$ Answered by mrW1 last updated on…
Question Number 141924 by Study last updated on 24/May/21 $${cos}\left({x}−\mathrm{180}\right)=? \\ $$ Commented by MJS_new last updated on 24/May/21 $$−\mathrm{cos}\:{x} \\ $$ Answered by mathmax…
Question Number 76386 by Maclaurin Stickker last updated on 27/Dec/19 $${Are}\:{give}\:{two}\:{parallel}\:{lines}\:{and}\:{a}\:{point} \\ $$$${A}\:{is}\:{given}\:{between}\:{them},\:{and}\:{the} \\ $$$${distance}\:{from}\:{A}\:{to}\:{the}\:{lines}\:{are}\: \\ $$$$\boldsymbol{{a}}\:{and}\:\boldsymbol{{b}}.\:{Determine}\:{the}\:{cathetus}\:{of} \\ $$$${right}−{angled}\:{triangle}\:{in}\:{A}\:{knowing} \\ $$$${that}\:{the}\:{other}\:{vertices}\:{belong}\:{to} \\ $$$${the}\:{parallel}\:{lines}\:{and}\:{the}\:{area}\:{of} \\ $$$${the}\:{triangle}\:{is}\:{equal}\:{to}\:\boldsymbol{{k}}^{\mathrm{2}}…
Question Number 141912 by dhgt last updated on 24/May/21 $${Q}\mathrm{138579} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 141911 by dhgt last updated on 24/May/21 $${Q}\mathrm{137956} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 141908 by dhgt last updated on 24/May/21 $${Q}\mathrm{137984} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 141910 by dhgt last updated on 24/May/21 $${Q}\mathrm{137026} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com