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Question Number 212360 by MrGaster last updated on 11/Oct/24 $$ \\ $$$$\:\:\:\:\:{T}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left(\frac{\mathrm{1}}{\left(\mathrm{4}{n}+\mathrm{1}\right)^{\mathrm{2}} }−\frac{\mathrm{1}}{\left(\mathrm{4}{n}+\mathrm{3}\right)^{\mathrm{2}} }\right. \\ $$ Answered by Berbere last updated on 15/Oct/24…

Question Number 212335 by MrGaster last updated on 10/Oct/24 $$ \\ $$$$\underset{{n}\rightarrow\infty} {\:\:\:\:\:\:\:\:\mathrm{lim}\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\mathrm{1}−\frac{{k}}{{n}}\right)\mathrm{ln}\left(\mathrm{1}+\frac{{k}}{{n}^{\mathrm{2}} }\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 212311 by MrGaster last updated on 09/Oct/24 $$ \\ $$$$\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\:\:\underset{{j}=\mathrm{1}} {\overset{{n}^{\mathrm{2}} } {\sum}}\:\mathrm{sin}\frac{{k}}{{n}}\centerdot\mathrm{sin}\frac{{k}}{{n}^{\mathrm{2}} }\centerdot\frac{\mathrm{1}}{\:\sqrt{{n}^{\mathrm{2}} +{j}}}\mathrm{l}{n}\left(\mathrm{1}+\frac{\mathrm{1}}{{n}}\right) \\ $$ Terms of Service…

Question Number 212233 by Davidtim last updated on 07/Oct/24 $$\mathrm{sin}^{−\mathrm{1}} \left(\frac{\mathrm{12}}{\mathrm{13}}\right)+\mathrm{cos}^{−\mathrm{1}} \left(\frac{\mathrm{3}}{\mathrm{5}}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{63}}{\mathrm{16}}\right)=? \\ $$ Commented by Davidtim last updated on 07/Oct/24 $${I}\:{kindly}\:{request}\:{you}\:{for}\:{helping} \\ $$…

Question Number 212228 by zakirullah last updated on 07/Oct/24 Terms of Service Privacy Policy Contact: info@tinkutara.com