Question Number 140702 by help last updated on 11/May/21 Answered by liberty last updated on 12/May/21 $$\left(\mathrm{3}\right)\:\frac{\mathrm{y}^{\cancel{\mathrm{2}}} }{\mathrm{2}}\:=−\mathrm{x}\cancel{\mathrm{y}}\:\frac{\mathrm{dy}}{\mathrm{dx}} \\ $$$$\Rightarrow\:−\frac{\mathrm{dx}}{\mathrm{x}}\:=\:\frac{\mathrm{2dy}}{\mathrm{y}} \\ $$$$\Rightarrow−\mathrm{ln}\:\mathrm{x}\:+\:\mathrm{c}\:=\:\mathrm{2ln}\:\mathrm{y}\: \\ $$$$\Rightarrow\:−\mathrm{ln}\:\mathrm{Cx}\:=\:\mathrm{ln}\:\mathrm{y}^{\mathrm{2}} \\…
Question Number 140688 by mohammad17 last updated on 11/May/21 Commented by mohammad17 last updated on 11/May/21 $${help}\:{me} \\ $$ Answered by TheSupreme last updated on…
Question Number 140676 by ZiYangLee last updated on 11/May/21 $$\int\:\frac{{x}^{\mathrm{3}} }{\mathrm{1}+{x}^{\mathrm{2}} }\:{dx}=? \\ $$ Answered by Dwaipayan Shikari last updated on 11/May/21 $$\int\frac{{x}^{\mathrm{3}} }{\mathrm{1}+{x}^{\mathrm{2}} }{dx}…
Question Number 9600 by Sopheak last updated on 20/Dec/16 Commented by prakash jain last updated on 20/Dec/16 $${k}^{{th}} \:\mathrm{Term}=\underset{{i}=\mathrm{0}} {\overset{{k}−\mathrm{1}} {\sum}}\mathrm{18}×\left(\mathrm{10}^{\mathrm{2}{i}} \right)=\frac{\mathrm{18}\left(\mathrm{10}^{\mathrm{2}{k}} −\mathrm{1}\right)}{\mathrm{99}} \\ $$$${S}_{{n}}…
Question Number 140665 by ERA last updated on 11/May/21 $$\int\frac{\mathrm{dx}}{\mathrm{x}\sqrt{\mathrm{x}^{\mathrm{6}} +\mathrm{x}^{\mathrm{3}} +\mathrm{1}}} \\ $$ Answered by MJS_new last updated on 11/May/21 $$\int\frac{{dx}}{{x}\sqrt{{x}^{\mathrm{6}} +{x}^{\mathrm{3}} +\mathrm{1}}}= \\…
Question Number 140667 by greg_ed last updated on 11/May/21 $$\mathrm{for}\:\mathrm{those}\:\mathrm{who}\:\mathrm{are}\:\mathrm{there}\:\mathrm{everytime}\:\mathrm{for}\:\mathrm{others}, \\ $$$$\mathrm{thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:! \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 140652 by mohammad17 last updated on 10/May/21 Answered by TheSupreme last updated on 10/May/21 $${x}^{\mathrm{3}} −{x}^{\mathrm{2}} +{x}−\mathrm{1}=\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{2}} +\mathrm{1}\right) \\ $$$$\int\frac{\mathrm{3}−{x}}{{x}^{\mathrm{3}} −{x}^{\mathrm{2}} +{x}−\mathrm{1}}{dx}=\int\frac{{A}}{{x}−\mathrm{1}}+\frac{{Bx}+{C}}{{x}^{\mathrm{2}} +\mathrm{1}}{dx}…
Question Number 140654 by muallim_riyoziyot last updated on 11/May/21 Answered by MJS_new last updated on 11/May/21 $$\mathrm{for}\:{x}\in\mathbb{R} \\ $$$$\sqrt[{\mathrm{3}}]{−{x}}=−\sqrt[{\mathrm{3}}]{{x}} \\ $$$$ \\ $$$$\left(\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{2}{x}+\mathrm{1}}={x}^{\mathrm{3}} −\mathrm{1}\right)^{\mathrm{3}} \\…
Question Number 140650 by aurpeyz last updated on 10/May/21 $${find}\:{the}\:{integral}\:{of}\: \\ $$$$\frac{\mathrm{1}}{\pi}\underset{\mathrm{0}} {\overset{\pi} {\int}}{e}^{{ie}^{{ksin}^{\mathrm{2}} \emptyset} } {d}\emptyset \\ $$ Terms of Service Privacy Policy Contact:…