Question Number 140462 by ZiYangLee last updated on 08/May/21 Commented by mr W last updated on 08/May/21 $${T}_{{n}} ={ar}^{{n}−\mathrm{1}} \\ $$$$\frac{{T}_{{n}+\mathrm{4}} −{T}_{{n}+\mathrm{2}} }{{T}_{{n}+\mathrm{1}} }=\frac{{ar}^{{n}+\mathrm{3}} −{ar}^{{n}+\mathrm{1}}…
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Question Number 9372 by geovane10math last updated on 03/Dec/16 $$\mathrm{I}\:\mathrm{was}\:\mathrm{able}\:\mathrm{to}\:\mathrm{discover}\:\mathrm{the}\:\mathrm{conditions}\:\mathrm{for} \\ $$$$\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{two}\:\mathrm{irrational}\:\mathrm{numbers}\:\mathrm{be}\:\mathrm{an} \\ $$$$\mathrm{integer}\:\mathrm{and}\:\mathrm{the}\:\mathrm{conditions}\:\mathrm{for}\:\mathrm{the}\:\mathrm{sum} \\ $$$$\mathrm{be}\:\mathrm{a}\:\mathrm{finite}\:\mathrm{decimal}. \\ $$$$\mathrm{But}\:\mathrm{I}\:\mathrm{can}\:\mathrm{not}\:\mathrm{do}\:\mathrm{the}\:\mathrm{same}\:\mathrm{for}\:\mathrm{periodic} \\ $$$$\mathrm{tithe}. \\ $$$$\mathrm{Someone}\:\mathrm{can}\:\mathrm{help}\:\mathrm{me},\:\mathrm{please}? \\ $$$$ \\…
Question Number 140424 by otchereabdullai@gmail.com last updated on 07/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 74863 by mrS last updated on 02/Dec/19 Commented by abdomathmax last updated on 03/Dec/19 $${we}\:{have}\:{S}=\sum_{{n}=\mathrm{1}} ^{\mathrm{45}} \:\frac{\mathrm{1}}{{n}^{\mathrm{2}} }\:=\sum_{{p}=\mathrm{1}} ^{\left[\frac{\mathrm{45}}{\mathrm{2}}\right]} \:\:\frac{\mathrm{1}}{\left(\mathrm{2}{p}\right)^{\mathrm{2}} }\:+\sum_{{p}=\mathrm{0}} ^{\left[\frac{\mathrm{45}−\mathrm{1}}{\mathrm{2}}\right]} \:\frac{\mathrm{1}}{\left(\mathrm{2}{p}+\mathrm{1}\right)^{\mathrm{2}}…
Question Number 140395 by dhgt last updated on 07/May/21 $${Q}\mathrm{135933} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140384 by Willson last updated on 07/May/21 Answered by benjo_mathlover last updated on 07/May/21 $$\left(\mathrm{2}\right)\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\left(\mathrm{x}^{\mathrm{p}} +\mathrm{1}\right)^{\mathrm{n}} \left(\mathrm{x}^{\mathrm{q}} +\mathrm{1}\right)^{\mathrm{m}} −\mathrm{1}}{\mathrm{x}}\:= \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\left(\mathrm{1}+\mathrm{nx}^{\mathrm{p}}…
Question Number 74840 by aliesam last updated on 01/Dec/19 Commented by kaivan.ahmadi last updated on 01/Dec/19 $${a}^{\mathrm{4}} =\mathrm{1}\Rightarrow \\ $$$${b}^{\mathrm{4}} ={a}^{\mathrm{4}} =\mathrm{1}\Rightarrow{o}\left({b}\right)=\mathrm{4} \\ $$$$\left({a}^{\mathrm{2}} \right)^{\mathrm{2}}…
Question Number 140367 by aliibrahim1 last updated on 06/May/21 Answered by meetbhavsar25 last updated on 06/May/21 $${Answer}\:{is}\:\frac{\mathrm{9}}{\mathrm{25}}. \\ $$$${x}^{\mathrm{2}} \:{has}\:{minimum}\:{value}\:\mathrm{0}. \\ $$$${y}^{\mathrm{2}} \:{has}\:{minimum}\:{value}\:\mathrm{0}. \\ $$$$\left({z}−\mathrm{1}\right)^{\mathrm{2}}…
Question Number 74825 by liki last updated on 01/Dec/19 Commented by liki last updated on 01/Dec/19 $$…{Anyone}\:{to}\:{help}\:{me}\:! \\ $$ Commented by $@ty@m123 last updated on…