Question Number 74371 by liki last updated on 23/Nov/19 Commented by liki last updated on 23/Nov/19 $$….{plz}\:{help}\:{me}\:\mathrm{16}{a}\:,,{emergerce} \\ $$ Answered by MJS last updated on…
Question Number 139897 by malwan last updated on 02/May/21 $$ \\ $$$$\mathrm{mrW}\:\mathrm{and}\:\mathrm{others}\:\mathrm{you}\:\mathrm{posted} \\ $$$$\mathrm{amzing}\:\mathrm{graphs}\:\mathrm{for}\:\mathrm{implicit} \\ $$$$\mathrm{funcions} \\ $$$$\mathrm{1}\:{What}\:{is}\:{the} \\ $$$$\mathrm{number}\:\mathrm{of}\:\mathrm{question}\:\mathrm{please}? \\ $$$$\mathrm{2}\:\mathrm{Canyou}\:\mathrm{send}\:\mathrm{me}\:\mathrm{the}\:\mathrm{links}\:\mathrm{to} \\ $$$$\mathrm{d}{own}\mathrm{load}\:\mathrm{these}\:\mathrm{graphers}\:\mathrm{thank} \\…
Question Number 74355 by Mr. K last updated on 22/Nov/19 $${let}\:{f}\left({x}\right),\:{g}\left({x}\right)\:{and}\:{h}\left({x}\right)\:{be}\:{functions} \\ $$$$\mathbb{R}\rightarrow\mathbb{R},\:{given}\:{by} \\ $$$${f}\left({x}\right)={x}^{\mathrm{2}} ,\:{if}\:{x}\geqslant\mathrm{0}\:{and}\:{x}+\mathrm{1}\:{if}\:{x}<\mathrm{0} \\ $$$${g}\left({x}\right)={x}^{\mathrm{2}} −\mathrm{4},\:{if}\:{x}\geqslant\mathrm{2}\:{and}\:\frac{\mathrm{1}}{\mathrm{2}−{x}}\:{if}\:{x}<\mathrm{2} \\ $$$${h}\left({x}\right)=\mathrm{3}^{−{x}} ,\:{if}\:{x}\leqslant\mathrm{0}\:{and}\:\mathrm{3}^{{x}} \:{if}\:{x}\geqslant\mathrm{0} \\ $$$${Calculate}\:\frac{{f}\left(\mathrm{2}\right)+{f}\left({g}\left(\mathrm{2}\right)\right)}{{f}\left({g}\left({h}\left(−\mathrm{1}\right)\right)\right)}.…
Question Number 8801 by arinto27 last updated on 28/Oct/16 $$\mathrm{tent}.\:\mathrm{persamaan}\:\mathrm{garis}\:\mathrm{singung}\:\mathrm{pada}\:\mathrm{lingkaran} \\ $$$$\mathrm{a}.\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{4x}−\mathrm{6y}−\mathrm{7}=\mathrm{0}\:\mathrm{dititik}\:\mathrm{yg}\:\mathrm{berabsis}\:\mathrm{2}. \\ $$$$\mathrm{b}.\:\left(\:\mathrm{x}+\mathrm{2}\:\right)^{\mathrm{2}} \:\left(\mathrm{y}−\mathrm{3}\right)^{\mathrm{2}} \:=\mathrm{16}\:\mathrm{tegak}\:\mathrm{lurus}\:\mathrm{garis}\:\mathrm{x}−\mathrm{2y}+\mathrm{4}=\mathrm{0}. \\ $$ Answered by ridwan balatif last…
Question Number 74337 by Maclaurin Stickker last updated on 22/Nov/19 $${find}\:{the}\:{contracted}\:{form}\:{of}: \\ $$$$\begin{pmatrix}{{n}}\\{{p}}\end{pmatrix}+\mathrm{2}\begin{pmatrix}{\:\:\:{n}}\\{{p}+\mathrm{1}}\end{pmatrix}+\begin{pmatrix}{\:\:\:{n}}\\{{p}+\mathrm{2}}\end{pmatrix} \\ $$ Answered by MJS last updated on 23/Nov/19 $$\begin{pmatrix}{{n}}\\{{p}}\end{pmatrix}\:=\frac{{n}!}{{p}!\left({n}−{p}\right)!}=\frac{{n}!\left({p}+\mathrm{1}\right)\left({p}+\mathrm{2}\right)}{{p}!\left({n}−{p}\right)!\left({p}+\mathrm{1}\right)\left({p}+\mathrm{2}\right)} \\ $$$$\mathrm{2}\begin{pmatrix}{{n}}\\{{p}+\mathrm{1}}\end{pmatrix}\:=\frac{\mathrm{2}{n}!}{\left({p}+\mathrm{1}\right)!\left({n}−{p}−\mathrm{1}\right)!}=\frac{\mathrm{2}{n}!\left({n}−{p}\right)}{{p}!\left({n}−{p}\right)!\left({p}+\mathrm{1}\right)}=…
Question Number 139867 by Maclaurin Stickker last updated on 01/May/21 $${a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} =\mathrm{0} \\ $$$${a}^{\mathrm{12}} +{b}^{\mathrm{12}} +{c}^{\mathrm{12}} =\mathrm{8} \\ $$$${a}^{\mathrm{6}} +{b}^{\mathrm{6}} +{c}^{\mathrm{6}} =? \\…
Question Number 74322 by naka3546 last updated on 22/Nov/19 $${Let}\:\: \\ $$$${k}\:\:=\:\:\frac{\left({xy}\:+\:{yz}\:+\:{zx}\right)\left({x}\:+\:{y}\:+\:{z}\right)}{\left({x}\:+\:{y}\right)\left({y}\:+\:{z}\right)\left({z}\:+\:{x}\right)} \\ $$$${Find}\:\:{the}\:\:{minimum}\:\:{and}\:\:{maximum}\:\:{value}\:\:{of}\:\:\:{k}\:. \\ $$ Answered by MJS last updated on 23/Nov/19 $${k}−\mathrm{1}=\frac{{xyz}}{\left({x}+{y}\right)\left({x}+{z}\right)\left({y}+{z}\right)} \\…
Question Number 8757 by FilupSmith last updated on 26/Oct/16 $$\mathrm{A}\:\mathrm{balloon}\:\mathrm{is}\:\mathrm{inflated}\:\mathrm{such}\:\mathrm{that}\:\mathrm{every} \\ $$$$\mathrm{point}\:\mathrm{expands}\:\mathrm{at}\:{a}\:\mathrm{units}/\mathrm{second}. \\ $$$$ \\ $$$$\mathrm{An}\:\mathrm{ant}\:\mathrm{runs}\:\mathrm{from}\:\mathrm{one}\:\mathrm{point}\:\boldsymbol{{A}}\:\mathrm{to}\:\mathrm{another} \\ $$$$\mathrm{point}\:\boldsymbol{{B}}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{ant}\:\mathrm{moves}\:{b}\:\mathrm{units}/\mathrm{second}, \\ $$$$\mathrm{what}\:\mathrm{will}\:\mathrm{influence}\:\mathrm{if}\:\mathrm{or}\:\mathrm{not}\:\mathrm{the}\:\mathrm{ant}\:\mathrm{will} \\ $$$$\mathrm{ever}\:\mathrm{reach}\:\mathrm{point}\:\boldsymbol{{B}}? \\ $$ Commented…
Question Number 74293 by Mr. K last updated on 21/Nov/19 Commented by Mr. K last updated on 21/Nov/19 $${ABCD}\:{id}\:{a}\:{quadrilateral},\:{cos}\theta=\frac{\sqrt{\mathrm{7}}}{\mathrm{4}}. \\ $$$${AE}=\mathrm{1},\:{BE}=\mathrm{4},\:{CE}=\mathrm{3}\:{and}\:{DE}=\mathrm{2}. \\ $$$${Find}\:{the}\:{area}\:{of}\:{the}\:{quadrilateral}. \\ $$…
Question Number 139825 by mathdave last updated on 01/May/21 Commented by mr W last updated on 01/May/21 $${rate}\:{of}\:{changing}\:{of}\:{distance}\:{is}\:{the} \\ $$$${sum}\:{of}\:{the}\:{speeds}\:{of}\:{the}\:{cars}: \\ $$$${case}\:\mathrm{1}: \\ $$$$−\left(\mathrm{50}+\mathrm{40}\right)=−\mathrm{90}\:{km}/{h}\:{if}\:{A}\:{was}\:{to} \\…