Question Number 74042 by liki last updated on 18/Nov/19 Commented by $@ty@m123 last updated on 18/Nov/19 $${I}\:{tried}\:{to}\:{send}\:{you}\:{a}\:{book}\:{but}\:{the}\:{above} \\ $$$${number}\:{is}\:{not}\:{recognised}\:{by}\:{whatsapp}. \\ $$$${Are}\:{you}\:{from}\:{Ivory}\:{coast}? \\ $$ Commented by…
Question Number 8498 by Chantria last updated on 13/Oct/16 Commented by Rasheed Soomro last updated on 13/Oct/16 $$\frac{\mathrm{2a}^{\mathrm{2}} }{\mathrm{3a}+\mathrm{bc}}×\sqrt{\frac{\mathrm{1}}{\mathrm{b}+\mathrm{c}}}×\frac{\mathrm{18ab}}{\left(\mathrm{3b}\right)^{\mathrm{2}} −\mathrm{5c}} \\ $$$$=\frac{\mathrm{2a}^{\mathrm{2}} }{\mathrm{3a}+\mathrm{bc}}×\frac{\mathrm{1}}{\:\sqrt{\mathrm{b}+\mathrm{c}}}×\frac{\mathrm{18ab}}{\mathrm{9b}^{\mathrm{2}} −\mathrm{5c}} \\…
Question Number 139561 by physicstutes last updated on 28/Apr/21 $$\mathrm{Near}\:\mathrm{the}\:\mathrm{shore}\:\mathrm{a}\:\mathrm{fisherman}\:\mathrm{jumps}\:\mathrm{out}\:\mathrm{of}\:\mathrm{his}\:\mathrm{boat}\:\mathrm{with}\:\mathrm{a}\:\mathrm{velocity} \\ $$$$\mathrm{of}\:\mathrm{5}.\mathrm{00}\:\mathrm{ms}^{−\mathrm{1}} \:\mathrm{and}\:\mathrm{lands}\:\mathrm{on}\:\mathrm{the}\:\mathrm{shore}\:\mathrm{0}.\mathrm{650}\:\mathrm{afterwards}.\mathrm{The}\:\mathrm{boat} \\ $$$$\mathrm{moves}\:\mathrm{backwards}.\:\mathrm{The}\:\mathrm{respective}\:\mathrm{masses}\:\mathrm{of}\:\mathrm{the}\:\mathrm{fisherman}\:\mathrm{and} \\ $$$$\mathrm{the}\:\mathrm{boat}\:\mathrm{are}\:\mathrm{85}.\mathrm{0}\:\mathrm{kg}\:\mathrm{and}\:\mathrm{165}\:\mathrm{kg}\:\mathrm{and}\:\mathrm{the}\:\mathrm{frictional}\:\mathrm{force}\:\mathrm{between} \\ $$$$\mathrm{the}\:\mathrm{boat}\:\mathrm{and}\:\mathrm{water}\:\mathrm{is}\:\mathrm{negligible}.\:\mathrm{What}\:\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{between} \\ $$$$\mathrm{the}\:\mathrm{fisherman}\:\mathrm{and}\:\mathrm{the}\:\mathrm{both}\:\mathrm{at}\:\mathrm{the}\:\mathrm{instant}\:\mathrm{when}\:\mathrm{he}\:\mathrm{just}\:\mathrm{lands}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{shore}? \\ $$…
Question Number 8486 by PradipGos. last updated on 12/Oct/16 $$\underset{−\infty} {\overset{\infty} {\int}}{e}^{−\mathrm{2}\mid{x}\overset{} {\mid}\:} \left(\mathrm{1}−\mathrm{cos}\:\mathrm{2}\alpha{x}\right){dx}=???? \\ $$$${solve}\:{this}\:……. \\ $$$$ \\ $$$$ \\ $$ Answered by Yozzias…
Question Number 139525 by TOTTI last updated on 28/Apr/21 Commented by mr W last updated on 29/Apr/21 $$=\mathrm{log}_{\sqrt{{x}}} \:\left(\sqrt{{x}}\right)^{\mathrm{2}} =\mathrm{3}^{\mathrm{1}/\mathrm{3}} \\ $$$$=\mathrm{2log}_{\sqrt{{x}}} \:\sqrt{{x}}=\mathrm{3}^{\mathrm{1}/\mathrm{3}} \\ $$$$\Rightarrow\mathrm{2}=\mathrm{3}^{\mathrm{1}/\mathrm{3}}…
Question Number 139501 by aliibrahim1 last updated on 28/Apr/21 Answered by mr W last updated on 28/Apr/21 $$\left({x}+\mathrm{3}{i}\right)^{\mathrm{100}} =−\mathrm{1}={e}^{\left(\mathrm{2}{k}+\mathrm{1}\right)\pi{i}} \\ $$$${x}_{{k}} +\mathrm{3}{i}={e}^{\frac{\left(\mathrm{2}{k}+\mathrm{1}\right)\pi}{\mathrm{100}}{i}} \\ $$$${x}_{{k}} ={e}^{\frac{\left(\mathrm{2}{k}+\mathrm{1}\right)\pi}{\mathrm{100}}{i}}…
Question Number 8421 by uchechukwu okorie favour last updated on 24/Oct/16 $${if}\:{x}=\frac{{a}\left(\mathrm{1}−{r}^{{n}} \right)}{\mathrm{1}−{r}};\:{make}\:{r}\:{the}\: \\ $$$${subject}\:{of}\:{the}\:{formulae} \\ $$ Commented by FilupSmith last updated on 11/Oct/16 $${x}−{xr}={a}−{ar}^{{n}}…
Question Number 139484 by ZiYangLee last updated on 27/Apr/21 $$\mathrm{If}\:\alpha,\beta\:\mathrm{and}\:\gamma\:\mathrm{are}\:\mathrm{the}\:\mathrm{interior}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{a}\: \\ $$$$\mathrm{triangle},\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\begin{vmatrix}{\mathrm{tan}\:\alpha}&{\mathrm{1}}&{\mathrm{1}}\\{\mathrm{1}}&{\mathrm{tan}\:\beta}&{\mathrm{1}}\\{\mathrm{1}}&{\mathrm{1}}&{\mathrm{tan}\:\gamma}\end{vmatrix} \\ $$ Answered by MJS_new last updated on 27/Apr/21 $$\mathrm{2} \\…
Question Number 8416 by Chantria last updated on 10/Oct/16 $$\boldsymbol{{Solve}}\:\boldsymbol{{equation}}\: \\ $$$$\:\mathrm{1}.\:\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} =\boldsymbol{{x}}+\boldsymbol{{y}}+\mathrm{8}\:\:\:\:\:\:\:\left({x};{y}\:{be}\:{positive}\right) \\ $$$$\:\mathrm{2}.\:\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{2}\sqrt{\boldsymbol{{x}}}+\mathrm{1}=\mathrm{0} \\ $$$$ \\ $$ Commented by Rasheed Soomro…
Question Number 139483 by qaz last updated on 27/Apr/21 $$\Gamma\left(\overset{−} {{z}}\right)=\overline {\Gamma\left({z}\right)}\:\:\:\:{why}? \\ $$ Answered by mnjuly1970 last updated on 27/Apr/21 $$\:\:{hint} \\ $$$$\:\:\Gamma\left({z}\right)={e}^{−\gamma{z}} \frac{\mathrm{1}}{{z}}\:\underset{{k}=\mathrm{1}}…